testfun | Lightweight framework for testing JEE6 components | REST library
kandi X-RAY | testfun Summary
kandi X-RAY | testfun Summary
Project TestFun - JEE JUnit Testing Is Fun(no server is needed!).
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Trending Discussions on testfun
QUESTION
I am trying to find a way to use the name of a vector instead of its value in a function.
...ANSWER
Answered 2021-May-07 at 19:30We can use deparse/substitute
QUESTION
ANSWER
Answered 2021-Apr-07 at 11:40return
is returning from the event handler. No code in the event handler will run until after the testFun
call has finished, if and when the click
event occurs in one of the elements. Since testFun
has already finished its work, there's nothing the code in the event handler can do to prevent that — it can't go back in time. :-)
You could remove the event handler from the elements (or just some of them?), though, so that they don't respond to clicks after the first click:
QUESTION
I have a dataframe with multiple columns. For each column in the dataframe, I want to call a function on the column, and the input of the function is using the remained columns in the dataframe. For example, let's say I have this data and this testFunc which accepts two args:
...ANSWER
Answered 2021-Feb-19 at 19:49We could loop over the sequence of columns of dataset in sapply/lapply
, extract the column of dataset with that index for the Y
and the remaining columns with -
on the index, apply the testfun
, assign an already initialized numeric
vector (of same length as number of columns of dataset) based on the index (-i
), return the vector
and t
ranspose the output of sapply
QUESTION
I have several functions calculation the same thing using different methods. I now wanted to bundle them in one main function with a keyword argument for choosing the method. The structure I came up with looks sth. like the minimal example below. The idea behind this was to assign a specific function to a general function name, as it is used several times inside the function and I didn't want to have the if else .. structure in more than one place.
...ANSWER
Answered 2021-Feb-04 at 12:33When I paste this straight into the REPL, I get this: WARNING: Method definition calculate(Any) in module Main at REPL[35]:4 overwritten at REPL[35]:7.
Looks like for some reason only the last definition of calculate
will be used.
You can use an anonymous function like calculate = x -> 2x
:
QUESTION
Consider this Rcpp Armadillo function:
...ANSWER
Answered 2021-Jan-14 at 21:03A couple of quick statements:
- The Armadillo C++ Matrix Linear Algebra Library does not have automatic recycling outside of vector-to-scalar operations.
- C++ does have stricter type controls that make going from a comparison resulting in
unsigned int
to subtraction with adouble
problematic.
The second part is really where trouble resides. To illustrate, we'll systematically step through each operation by writing a debug function as follows:
QUESTION
type Test<'T> =
static member from : unit -> 'T[] = fun () -> Array.empty
let inline testFun< ^T, ^S when ^T : (static member from : unit -> ^S [])> () =
(^T : (static member from : unit -> ^S[]) ())
let a = testFun, int> ()
...ANSWER
Answered 2021-Jan-13 at 03:17The SRTP solver can't understand your static method signature, because technically it's not a method, but a property. It's a property whose type is a function unit -> 'T[]
, but it's not a method. I know, subtle and confusing, but there it is.
If you make it a method, everything will suddenly work:
QUESTION
I have written a variadic template function with recursive evaluation. For the final parameter I implemented a specialization without the variadic pack and everything worked fine.
Now I want to convert the variadic function parameters into template parameters.
This is my try:
...ANSWER
Answered 2020-Nov-24 at 11:26The parameter pack can indeed be empty. You can avoid the ambiguity by changing the specialization to handle the case of not adding anything:
QUESTION
What is this arbitrary RegExp execution time limit, how long is it, and when does it apply (because it does not apply equally in all Google Apps Script contexts)? Also, why does it apply when there are already execution time limits for the entire script?
Full Post:I have suddenly hit the error
"Error: Regular expression operation exceeded execution time limit."
in Google Apps Script. I have hit this error while running a function using a custom menu on Google sheets that I created. This makes a brief UI which requests the use to input a spreadsheet url, and then runs a function using the provided url (and spreadsheet).
I have run this function before and it worked fine, but now I am getting this regular expression time limit error. To be clear this script comes nowhere near the maximum time limit for script execution, it is only apparently that my regular expression is too long. I have determined the line with the regular expression (which runs repeatedly and is usually fine and has worked up to this point) has no obvious flaws. It is a large regular expression, but the text is not very long. It failed on a 217 character text.
Furthermore, I have discovered that the error does NOT occur, when I run the function equivalent from the Google Apps Script Editor (without the UI, which simply calls this same function from a Google Apps Script Library I created). To be clear I am certain that the variables and environment in the working execution are the same. It completed in 8 seconds, parsed the same text, and used the same regular expression.
This leads me to believe that there is an arbitrary time limit that is applied to regular expressions which applies either because the function has been called from a custom menu, the function briefly uses UI, or the function calls a library (or some combination of these).
What is this arbitrary RegExp execution time limit, how long is it, and when does it apply (because it does not apply equally in all Google Apps Script contexts)? Also, why does it apply when there are already execution time limits for the entire script?
I haven't been able to find anything mentioning this specific error/time limit/quota on Google's documentation of Google Apps Script.
To be clear, I have checked that they are using the UI script is using the correct library version (and development mode is on anyway, so it is using the most up to date version). I have also confirmed that same functions are running with the same variables via console printing so I know the only difference is how the function is being called.
Here is the RegExp that breaks the time limit in one context but no the other, if you need it for some reason:
...ANSWER
Answered 2020-Sep-22 at 22:01This seems to account for differences in execution context. Given the deprecation of rhino engine, It's unlikely that you find the exact limit or reason of the issue(But it seems to be around 300ms).
QUESTION
let user = {
firstName: "John",
sayHi: () => alert(this.firstName)
};
let user2 = {
firstName : "Mike",
testFun : function(){let argFun = user.sayHi; argFun();} // Hello, undefined!
};
...ANSWER
Answered 2020-Sep-22 at 18:22This great answer is quite helpful: Are 'Arrow Functions' and 'Functions' equivalent / interchangeable? To quote the pertinent part...
If the function you want to replace does not use this, arguments and is not called with new, then yes[, arrow functions and functions are equivalent].
Your function uses this
, so, if you want to use an arrow function, define it in the constructor...
QUESTION
The relevant code is below. I create a zeros matrix which here happens to be a 2X2 matrix. Then I march through a data file to populate the matrix with random numbers within the range of each column of the input data set. This works, except that the output matrix is transposed, and I'd rather do it right. Please see the comments in the code.
...ANSWER
Answered 2020-Aug-03 at 02:31Assignment to a 2d array:
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