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interview | Interview questions

 by   mission-peace Java Version: Current License: Apache-2.0

 by   mission-peace Java Version: Current License: Apache-2.0

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kandi X-RAY | interview Summary

interview is a Java library typically used in MongoDB applications. interview has no vulnerabilities, it has build file available, it has a Permissive License and it has medium support. However interview has 45 bugs. You can download it from GitHub.
Interview questions
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Support
Quality
Quality
Security
Security
License
License
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kandi-support Support

  • interview has a medium active ecosystem.
  • It has 9741 star(s) with 4821 fork(s). There are 1037 watchers for this library.
  • It had no major release in the last 12 months.
  • There are 57 open issues and 25 have been closed. On average issues are closed in 27 days. There are 109 open pull requests and 0 closed requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of interview is current.
interview Support
Best in #Java
Average in #Java
interview Support
Best in #Java
Average in #Java

quality kandi Quality

  • interview has 45 bugs (4 blocker, 1 critical, 27 major, 13 minor) and 3103 code smells.
interview Quality
Best in #Java
Average in #Java
interview Quality
Best in #Java
Average in #Java

securitySecurity

  • interview has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
  • interview code analysis shows 0 unresolved vulnerabilities.
  • There are 16 security hotspots that need review.
interview Security
Best in #Java
Average in #Java
interview Security
Best in #Java
Average in #Java

license License

  • interview is licensed under the Apache-2.0 License. This license is Permissive.
  • Permissive licenses have the least restrictions, and you can use them in most projects.
interview License
Best in #Java
Average in #Java
interview License
Best in #Java
Average in #Java

buildReuse

  • interview releases are not available. You will need to build from source code and install.
  • Build file is available. You can build the component from source.
  • interview saves you 14814 person hours of effort in developing the same functionality from scratch.
  • It has 29606 lines of code, 2042 functions and 604 files.
  • It has medium code complexity. Code complexity directly impacts maintainability of the code.
interview Reuse
Best in #Java
Average in #Java
interview Reuse
Best in #Java
Average in #Java
Top functions reviewed by kandi - BETA

kandi has reviewed interview and discovered the below as its top functions. This is intended to give you an instant insight into interview implemented functionality, and help decide if they suit your requirements.

  • Start phase .
  • Returns the largest multiple of the given array
  • Checks if the input is schedramble
  • Returns the max chain of two nodes .
  • Returns the longest palindic char in linear form .
  • Gets the equation .
  • Justify one word .
  • Justify words .
  • Finds sub - square in the input string .
  • Get the skyline for the given buildings

interview Key Features

Interview questions

How it is possible to cast parent to child in c#

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if (p is Child child) {
    child.DriveParentsToDespair();
}

How to resolve Custom Sort Runtime error 1004

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Sub custom_sort()
    Dim vCustom_Sort As Variant, rr As Long

    vCustom_Sort = Array("Published", "Submitted", "Distributed", "Amending", "Awaiting Sign-off", "Materials Drafting", "Working Up", "Arranging Interview", "Sourcing Information/Images", "Confirmed", "Pitched", "On Hold", "Archive")
    Application.AddCustomList ListArray:=vCustom_Sort

    With ActiveWorkbook.Worksheets("Activity")
        .Sort.SortFields.Clear
        rr = .Cells(.Rows.Count, "B").End(xlUp).Row
        With .Range("A2:L" & rr)
            .Sort Key1:=.Columns(2), Order1:=xlAscending, DataOption1:=xlSortNormal, _
                        Orientation:=xlTopToBottom, Header:=xlYes, MatchCase:=False, _
                        OrderCustom:=Application.CustomListCount + 1
        End With
        .Sort.SortFields.Clear
    End With
End Sub
Sub custom_sort_table()

Dim ws As Worksheet
Set ws = ActiveSheet
Dim sortcol As Range
Dim tbl As ListObject
Dim vCustom_Sort As Variant

Set tbl = ws.ListObjects("Table1") 'Set/adjust table name
Set sortcol = Range("Table1[Status]") 'Set/adjust table column you want to sort (i.e. table name + column name)

vCustom_Sort = Array("Published", "Submitted", "Distributed", "Amending", "Awaiting Sign-off", "Materials Drafting", "Working Up", "Arranging Interview", "Sourcing Information/Images", "Confirmed", "Pitched", "On Hold", "Archive")
Application.AddCustomList ListArray:=vCustom_Sort

With ActiveWorkbook.Worksheets("Activity")
    With tbl.Sort 'sort table
        .SortFields.Clear 'clear previous sorting
        .SortFields.Add Key:=sortcol, SortOn:=xlSortOnValues, Order:=xlAscending, CustomOrder:=Application.CustomListCount
        .Header = xlYes 'Ignore heading
        .Apply 'Need to apply sorting, otherwise it won't change sort
    End With
End With

End Sub
-----------------------
Sub custom_sort()
    Dim vCustom_Sort As Variant, rr As Long

    vCustom_Sort = Array("Published", "Submitted", "Distributed", "Amending", "Awaiting Sign-off", "Materials Drafting", "Working Up", "Arranging Interview", "Sourcing Information/Images", "Confirmed", "Pitched", "On Hold", "Archive")
    Application.AddCustomList ListArray:=vCustom_Sort

    With ActiveWorkbook.Worksheets("Activity")
        .Sort.SortFields.Clear
        rr = .Cells(.Rows.Count, "B").End(xlUp).Row
        With .Range("A2:L" & rr)
            .Sort Key1:=.Columns(2), Order1:=xlAscending, DataOption1:=xlSortNormal, _
                        Orientation:=xlTopToBottom, Header:=xlYes, MatchCase:=False, _
                        OrderCustom:=Application.CustomListCount + 1
        End With
        .Sort.SortFields.Clear
    End With
End Sub
Sub custom_sort_table()

Dim ws As Worksheet
Set ws = ActiveSheet
Dim sortcol As Range
Dim tbl As ListObject
Dim vCustom_Sort As Variant

Set tbl = ws.ListObjects("Table1") 'Set/adjust table name
Set sortcol = Range("Table1[Status]") 'Set/adjust table column you want to sort (i.e. table name + column name)

vCustom_Sort = Array("Published", "Submitted", "Distributed", "Amending", "Awaiting Sign-off", "Materials Drafting", "Working Up", "Arranging Interview", "Sourcing Information/Images", "Confirmed", "Pitched", "On Hold", "Archive")
Application.AddCustomList ListArray:=vCustom_Sort

With ActiveWorkbook.Worksheets("Activity")
    With tbl.Sort 'sort table
        .SortFields.Clear 'clear previous sorting
        .SortFields.Add Key:=sortcol, SortOn:=xlSortOnValues, Order:=xlAscending, CustomOrder:=Application.CustomListCount
        .Header = xlYes 'Ignore heading
        .Apply 'Need to apply sorting, otherwise it won't change sort
    End With
End With

End Sub

Calculate average of any two numbers in a given array in JavaScript?

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const
    values = [4, 5, 10, 9, 8];

for (let i = 0, l = values.length - 1; i < l; i++) {
    for (j = i + 1; j < values.length; j++) {
        const average = (values[i] + values[j]) / 2;
        console.log(values[i], values[j], '|', average, '|', ...values.filter(v => v > average));
    }
}
-----------------------
function solve(arr) {
    arr.sort(function (a, b) { return a - b });
    let firstMinimum = arr[0];
    let secondMinimun = arr[1];
    let avg = (firstMinimum + secondMinimun) / 2;

    for (let i = 0; i < arr.length; i++) {
        if (arr[i] > avg) console.log(arr[i]);
    }
}
solve([4, 5, 10, 9, 8]);
-----------------------
let arr = [4,5,10,9,8]
arr.sort((a,b) => a-b)    // sorted array

function greaterThanAverage(x,y){
    let average = (x+y)/2
    let index = arr.findIndex(e => e > average )
    return arr.slice(index == -1 ? arr.length : index)
}

console.log(greaterThanAverage(5,9))
console.log(greaterThanAverage(10,9))
console.log(greaterThanAverage(5,4))
console.log(greaterThanAverage(30,4))
-----------------------
    const values = [4, 5, 10, 9, 8];
    const minValue = Math.min(...values);
    values.splice(values.indexOf(minValue),1);
    const secondMinValue = Math.min(...values);
    const minAverage = (minValue + secondMinValue)/2;
    const result = values.filter(val => val > minAverage);

Why ambiguous reference error while using Left without parameters type?

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scala> for (v1 <- Right(2)) yield v1
res13: scala.util.Either[Nothing,Int] = Right(2)
for {
  v1 <- Left[Int,Int](1)
  v2 <- Right[Int,Int](2)
  v3 <- Right[Int,Int](3)
  v4 <- Left[Int,Int](4)
} yield v1 + v2 + v3 + v4
-----------------------
scala> for (v1 <- Right(2)) yield v1
res13: scala.util.Either[Nothing,Int] = Right(2)
for {
  v1 <- Left[Int,Int](1)
  v2 <- Right[Int,Int](2)
  v3 <- Right[Int,Int](3)
  v4 <- Left[Int,Int](4)
} yield v1 + v2 + v3 + v4

Counting total number of paper pieces

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int func(int a, int b, int c, int d, int n) {
 if (n == 0) return (a + b + c + d);
 if (n % 2 == 0) return func(a + b, a, c + d, c, n - 1);
 else return func(a + c, b + d, a, b, n - 1);
}

Permutations of the same 4 digits resulting into 2 pairs

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def xnor_pairs(seq):
    # Create two pointers: one on the start and another at the end
    i0 = 0
    i1 = len(seq) - 1
    
    pairs = []
    
    # Repeat this until the start pointer has not reached the end
    while i0 < len(seq) - 1:
        a, b = seq[i0], seq[i1]
        
        # If the start and end indexes are equal
        if i0 == i1:
            # Move the start pointer one position closer to the end
            i0 += 1
            # Move the end pointer back to the end
            i1 = len(seq) - 1
            
            continue

        # If the condition is satisfied (a XNOR b == -1)
        if ~(a ^ b) == -1:
            # Append to the pairs
            pairs.append((a, b))
        
        # Move the end pointer one position closer to the start
        i1 -= 1
        
    return pairs

print(xnor_pairs([1, 2, 3, 3, 4, 4, 4, 10, 10, 10]))
# Output: [(3, 3), (4, 4), (4, 4), (4, 4), (10, 10), (10, 10), (10, 10)]

Async operations when instance created

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    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));
-----------------------
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) => { return this.myAsyncCall(url); }));
    this.ready = Promise.all([URL1, URL2, URL3].map((url) =>  this.myAsyncCall(url)));
        notifyUrls(item, (res) => {
            resolve(res);
        });
        notifyUrls(item, resolve);
const asyncOperation = () => {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve();
        }, 2000);
    });
};
const asyncOperation = () => new Promise(resolve => setTimeout(resolve, 2000));

Interview question, setTimeout should be called first before console.log

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function callMe(delay) {
  return new Promise((resolve) => {
    setTimeout(() => {
      console.log("Called");
      // Resolve Promise, when Timeout is over
      resolve();
    }, delay);
  });
}

// Async Main Function
(async () => {
  const delays = [500, 1000, 1500];
  for (let delay of delays) {
    // Await the Timeout with the Promise
    await callMe(delay);
  }
  console.log("Completed");
})();

Dynamic number of currying strings

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const func = (arg) => {
  const args = [arg];
  const inner = (arg) => {
    args.push(arg);
    return inner;
  };
  inner.join = () => args.join(':');
  return inner;
};

console.log(func('hello')('world').join(':'));
console.log(func('hello')('world')('today').join(':'));

How type casting works in Python?

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def get():
    prompt = 'Give a number or a word.\n'
    x = input(prompt)
    try:
        float(x)
        print('You entered a number.')

    except:
        print('You entered a string.')

Community Discussions

Trending Discussions on interview
  • How it is possible to cast parent to child in c#
  • How to resolve Custom Sort Runtime error 1004
  • Trigger a function after 5 API calls return (in a distributed context)
  • Calculate average of any two numbers in a given array in JavaScript?
  • Why wasn't this boolean value being registered in Go?
  • How the server make sure clients requests doesn't interfere with each other?
  • Why ambiguous reference error while using Left without parameters type?
  • Counting total number of paper pieces
  • Permutations of the same 4 digits resulting into 2 pairs
  • Async operations when instance created
Trending Discussions on interview

QUESTION

How it is possible to cast parent to child in c#

Asked 2021-Jun-15 at 12:54

A few days ago in an interview, i was asked to explain following cases:

public class Parent
{

}
public class Child:Parent
{

}

Case1:

Parent p = new Child();
    var c = (Child)p;

Case2:

    Parent p = new Parent();
    var c = (Child)p;

I said case1 is valid and case2 is invalid , but he asked:

Why case2 is invalid while both p variable in case1 and case2 are Type of Parent class?

In case2 we get runtime exception by following message:

Unable to cast object of type 'Parent' to type 'Child

While in case1 p variable was also type of Parent class.

He wanted me to explain it from point of stack and heap memory.

Have you any idea?

Update:

The very spot that interviewer misguided me was exactly where he said in both cases p is type of 'parent' class, based on the answers, just static types of both variables are 'parent', but in run-time they have different types and it's run-time type that really matters.

ANSWER

Answered 2021-Jun-15 at 12:54

You must make a distinction between the static type of a variable (the type known at compile time) and the run time type of an object reference assigned to a variable.

The static type of p is Parent in both cases because it is declared as Parent p. No matter what you assign it. You may even assign it null.

The run time type of the value of p after the assignment is Child in the first case and Parent in the second case. It would be undetermined if p was null.

It is okay to assign a Child to a Parent, because the Child class derives from Parent. A Child is therefore a Parent (in OO terms).

However, a Parent is not a Child, because it does not derive from it. Therefore, in the second case, you cannot cast p to Child. In the first case the cast is valid, because you cast the object to its actual run time type. It tells the compiler, I know that this object assigned to a Parent variable is a Child, so, please, treat it as a Child. This does not involve any conversion; however, a runtime check will be performed, possibly throwing an exception, if the cast was not allowed.

You were asked to explain it from point of view of stack and heap memory. I'm sorry to say, but this has absolutely nothing to do with stack or heap memory. It has to do with inheritance rules and assignment compatibility.

Of course, here we are dealing with reference types (classes). This allows us to derive Child from Parent. This would not be possible with value types (structs). The point is reference type versus value type, not heap versus stack, which is an implementation detail. And btw., a value type (struct) field in a class will also be stored on the heap.

See also: The Stack Is An Implementation Detail, Part One and Two (Eric Lippert's blog)


You did not ask for it but casting to a derived type is mostly preceded by a type test, because you usually do not know the run time type in advance. Let us say that the Child class adds a new method DriveParentsToDespair() (only children can do this). Then you could use Type testing with pattern matching to test the type and assign it to a new variable at the same time:

if (p is Child child) {
    child.DriveParentsToDespair();
}

This avoids an exception in case p has a run time type of Parent.

Source https://stackoverflow.com/questions/67960172

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install interview

You can download it from GitHub.
You can use interview like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the interview component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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