Cinema | a sample app for book cinema ticket

by mohamadk Java Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | Cinema Summary

Cinema is a Java library typically used in User Interface, JavaFX applications. Cinema has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

a sample app for book cinema ticket. Special thanks for design Yaroslav Zubko

Support

Quality

Security

License

Reuse

Support

Cinema has a low active ecosystem.

It has 18 star(s) with 8 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 0 have been closed. On average issues are closed in 636 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Cinema is current.

Quality

Cinema has 0 bugs and 0 code smells.

Security

Cinema has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Cinema code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Cinema does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Cinema releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

It has 2913 lines of code, 185 functions and 67 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed Cinema and discovered the below as its top functions. This is intended to give you an instant insight into Cinema implemented functionality, and help decide if they suit your requirements.

Initializes the toolbar
Initializes the views
Initialize views
Bind a MovieItem to a ListView
Start an elevated view
Gets the fragment at the given position
Create a new instance of DayListFragment
Transforms a page at a specific position
Create the list of visible items
Draw the tab
Blends two colors
Initialize and drag views
Start animator
Create the day view
Inflates popup
Called when the view is created
Initialize the ramp image
Override this to create a date
Stretch the view
Intercept the touch event

Get all kandi verified functions for this library.

Cinema Key Features

No Key Features are available at this moment for Cinema.

Cinema Examples and Code Snippets

No Code Snippets are available at this moment for Cinema.

Community Discussions

Trending Discussions on Cinema

Django: why does my custom filter not find an existing item in the array?

Django: How to create some variable in model based on the foreign key data?

Solution for complex LINQ query with ROW_NUMBER() and PARTITION BY

Mongoose retrieve one document from nested array

How to calculate daily average frequency in a table in function of GROUP BY from another table?

Unexpected behaviour involving UNION ALL in CTE with MYSQL

Perl what is the best way to check if an object defined, missing or null within JSON

JSON how can I check if keys and array exists?

How to update a dictionary with nested list using a dictionary?

Django ORM better way to manipulate django ORM query

QUESTION

Django: why does my custom filter not find an existing item in the array?

Asked 2022-Apr-02 at 19:03

I am a beginner in Django. Right now i am working on my first project: reservation of sits for cinema event. The html map of sits is based on the array of cols and rows, provided from the Hall model.

There is also an Invoice model, which stores the information about reserved places, based on this event. Based on this, i am trying to disable the html-map checkboxes of the sit places, which are already reserved.

Here is my code:

views.py

...

ANSWER

Answered 2022-Apr-02 at 19:03

Your reserved_places is a list of strings, not a list of integers, and 0 is not equal to '0'.

You should convert these to ints, so:

Source https://stackoverflow.com/questions/71720130

QUESTION

Django: How to create some variable in model based on the foreign key data?

Asked 2022-Apr-02 at 17:50

I am new to Django and right now I am working on my first project: sits reservation system for some cinema. For this I have created 3 models: Movie, Hall and Event. Hall generates sits map as array.

...

ANSWER

Answered 2022-Apr-02 at 17:50

I solved the problem by restructurizing the project a little bit. The rows and columns of the specific Hall are now just stored in the model:

Models.py

Source https://stackoverflow.com/questions/71583519

QUESTION

Solution for complex LINQ query with ROW_NUMBER() and PARTITION BY

Asked 2022-Mar-02 at 10:26

This is my first question. For a school assignment I'm writing a program in ASP.net MVC with Rider. It is gonna be cinema webapp. The query gets the show which is played in every hall at the moment. So, for 6 halls I have 6 Id's and all of the ID's should give me back:

HallId
MovieTitle
Showtime (Starttime)

The code I build was this and it works in my Query-console:

...

ANSWER

Answered 2022-Mar-01 at 19:38

your question is not clear enough about the columns names but you can use the same as following linq query

Source https://stackoverflow.com/questions/71313678

QUESTION

Mongoose retrieve one document from nested array

Asked 2022-Feb-18 at 15:08

I'm working on an mongo database with mongoose in Node.js.

I have a collection like this :

...

ANSWER

Answered 2022-Feb-18 at 12:34

You can use aggregate query to get expected result:

Source https://stackoverflow.com/questions/71171252

QUESTION

How to calculate daily average frequency in a table in function of GROUP BY from another table?

Asked 2022-Feb-16 at 10:15

I want to know which cinema room is more frequented daily and I need the values as relative frequency.

My tables are:

table1:

client_id cinema_room 1 A 2 B 3 C 4 C 5 A 6 C 7 B 8 A 9 B 10 B 11 B 12 A 13 C 14 A 15 A 16 B

Table 2:

day client_id 01/01/2022 1 01/01/2022 1 01/02/2022 1 01/02/2022 2 01/02/2022 4 01/03/2022 8 01/04/2022 14 01/04/2022 15 01/04/2022 16

So I need results like:

day cinema_room avg_freq 01/01/2022 A 1 01/01/2022 B 0 01/01/2022 C 0 01/02/2022 A 0.33 01/02/2022 B 0.33 01/02/2022 C 0.33 01/03/2022 A 1 01/03/2022 B 0 01/03/2022 C 0 01/04/2022 A 0.66 01/04/2022 B 0.33 01/04/2022 C 0

What I've got by now is:

...

ANSWER

Answered 2022-Feb-16 at 01:11

You can try to use CROSS JOIN in a subquery which would be a calendar table, then aggregate table1 & table2 in another subquery the get count by each cinema_room per day.

Source https://stackoverflow.com/questions/71135082

QUESTION

Unexpected behaviour involving UNION ALL in CTE with MYSQL

Asked 2022-Feb-12 at 12:27

I've tried to re-create a minimal reproducible example but without success so I'll have to paste my actual query, I'm sorry for the name of the columns and tables in a foreign language.

The queries below have the same WITH preamble.

On MySQL 8.0.22 the following query

...

ANSWER

Answered 2022-Feb-12 at 12:27

In the file specified by log_error(see: show variables like 'log_error';) is the following info:

Source https://stackoverflow.com/questions/71090984

QUESTION

Perl what is the best way to check if an object defined, missing or null within JSON

Asked 2022-Jan-08 at 15:09

I have a JSON file below and I want to check 3 states

Within the array "categories" I have another array "children" which is currently null

How can I do to know

if children array is null ?
if children array is defined and contain at least one data ?
if children array is completely missing from the JSON whereas I was expecting to be here

Here below the JSON file

...

ANSWER

Answered 2022-Jan-08 at 15:02

1.if children array is null ?

Source https://stackoverflow.com/questions/70633433

QUESTION

JSON how can I check if keys and array exists?

Asked 2022-Jan-07 at 15:05

I have a JSON file, and I want to check if keys exists or not, if keys are empty or not.

I've already done this kind of check in the script below. But, here I have "children" which is an empty array. How can I see if this array exists or not and if this array is empty or not?

Here the JSON sample:

...

ANSWER

Answered 2022-Jan-07 at 15:02

In your code, @child is an array of arrays. Dereference the array. Change:

Source https://stackoverflow.com/questions/70623025

QUESTION

How to update a dictionary with nested list using a dictionary?

Asked 2021-Dec-05 at 13:47

I got the following dictionary, network_values

...

ANSWER

Answered 2021-Dec-05 at 13:47

First thing is to close the quotation marks for 'Écran mobile 74 in your dictionary as the code you pasted returns SyntaxError.

Then, in the if statement you are currently comparing dictionaries with strings, so the expression is never true. You want to see if the string is in the dictionary values and update that element of the dictionary if so:

Source https://stackoverflow.com/questions/70233669

QUESTION

Django ORM better way to manipulate django ORM query

Asked 2021-Nov-05 at 16:22

Below are the models:

...

ANSWER

Answered 2021-Nov-05 at 16:22

You can obtain these Seats with:

Source https://stackoverflow.com/questions/69856255

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Cinema

You can download it from GitHub.
You can use Cinema like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Cinema component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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