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infovore | Centric Map/Reduce Framework | Data Manipulation library

 by   paulhoule Java Version: v3.1 License: Non-SPDX

 by   paulhoule Java Version: v3.1 License: Non-SPDX

kandi X-RAY | infovore Summary

infovore is a Java library typically used in Utilities, Data Manipulation applications. infovore has no bugs, it has no vulnerabilities, it has build file available and it has low support. However infovore has a Non-SPDX License. You can download it from GitHub.
Infovore is an RDF processing system that uses Hadoop to process RDF data sets in the billion triple range and beyond. Infovore was originally designed to process the (old) proprietary Freebase dump into RDF, but once Freebase came out with an official RDF dump, Infovore gained the ability to clean and purify the dump, making it not just possible but easy to process Freebase data with triple stores such as Virtuoso 7. Every week we run Infovore in Amazon Elastic/Map reduce in order to produce a product known as :BaseKB. Infovore depends on the Centipede framework for packaging and processing command-line arguments. The Telepath project extends the Infovore project in order to process Wikipedia usage information to produce a product called :SubjectiveEye3D.
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kandi-support Support

  • infovore has a low active ecosystem.
  • It has 149 star(s) with 19 fork(s). There are 21 watchers for this library.
  • It had no major release in the last 12 months.
  • There are 49 open issues and 71 have been closed. On average issues are closed in 8 days. There are no pull requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of infovore is v3.1
infovore Support
Best in #Data Manipulation
Average in #Data Manipulation
infovore Support
Best in #Data Manipulation
Average in #Data Manipulation

quality kandi Quality

  • infovore has 0 bugs and 0 code smells.
infovore Quality
Best in #Data Manipulation
Average in #Data Manipulation
infovore Quality
Best in #Data Manipulation
Average in #Data Manipulation

securitySecurity

  • infovore has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
  • infovore code analysis shows 0 unresolved vulnerabilities.
  • There are 0 security hotspots that need review.
infovore Security
Best in #Data Manipulation
Average in #Data Manipulation
infovore Security
Best in #Data Manipulation
Average in #Data Manipulation

license License

  • infovore has a Non-SPDX License.
  • Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.
infovore License
Best in #Data Manipulation
Average in #Data Manipulation
infovore License
Best in #Data Manipulation
Average in #Data Manipulation

buildReuse

  • infovore releases are available to install and integrate.
  • Build file is available. You can build the component from source.
  • It has 12177 lines of code, 878 functions and 243 files.
  • It has medium code complexity. Code complexity directly impacts maintainability of the code.
infovore Reuse
Best in #Data Manipulation
Average in #Data Manipulation
infovore Reuse
Best in #Data Manipulation
Average in #Data Manipulation
Top functions reviewed by kandi - BETA

kandi has reviewed infovore and discovered the below as its top functions. This is intended to give you an instant insight into infovore implemented functionality, and help decide if they suit your requirements.

  • move to next state
    • Read a single character .
      • Get a map of Hadoop Configuration variables to be used as a map of configuration variables
        • Creates a Job from the given strings .
          • Creates an iterator over the elements in this list .
            • Escapes special characters in a string
              • Escapes special characters in a string .
                • The graph term
                  • Creates the Mojo file .
                    • Logs in to an ipAddress

                      Get all kandi verified functions for this library.

                      Get all kandi verified functions for this library.

                      infovore Key Features

                      RDF-Centric Map/Reduce Framework and Freebase data conversion tool

                      infovore Examples and Code Snippets

                      Community Discussions

                      Trending Discussions on Data Manipulation
                      • R: Is there a "Un-Character" Command in R?
                      • Creating new columns based on data in row separated by specific character in R
                      • Multiplying and Adding Values across Rows
                      • How to make a rank column in R
                      • How to return the column title wherein the row contains the greatest value in Pandas Dataframe
                      • Split large csv file into multiple files based on column(s)
                      • Get the first non-null value from selected cells in a row
                      • pivot_longer with column pairs
                      • Simulating Random Draws From a "Hat"
                      • Break Apart a String into Separate Columns R
                      Trending Discussions on Data Manipulation

                      QUESTION

                      R: Is there a "Un-Character" Command in R?

                      Asked 2022-Apr-10 at 17:37

                      I am working with the R programming language.

                      I have the following dataset:

                      v <- c(1,2,3,4,5,6,7,8,9,10)
                      
                      var_1 <- as.factor(sample(v, 10000, replace=TRUE, prob=c(0.1,0.1,0.1,0.1,0.1, 0.1,0.1,0.1,0.1,0.1)))
                      
                      var_2 <- as.factor(sample(v, 10000, replace=TRUE, prob=c(0.1,0.1,0.1,0.1,0.1, 0.1,0.1,0.1,0.1,0.1)))
                      
                      var_3 <- as.factor(sample(v, 10000, replace=TRUE, prob=c(0.1,0.1,0.1,0.1,0.1, 0.1,0.1,0.1,0.1,0.1)))
                      
                      var_4 <- as.factor(sample(v, 10000, replace=TRUE, prob=c(0.1,0.1,0.1,0.1,0.1, 0.1,0.1,0.1,0.1,0.1)))
                      
                      var_5 <- as.factor(sample(v, 10000, replace=TRUE, prob=c(0.1,0.1,0.1,0.1,0.1, 0.1,0.1,0.1,0.1,0.1)))
                      
                      my_data = data.frame(var_1, var_2, var_3, var_4, var_5)
                      

                      I also have another dataset of "conditions" that will be used for querying this data frame:

                      conditions = data.frame(cond_1 = c("1,3,4", "4,5,6"), cond_2 = c("5,6", "7,8,9"))
                      

                      My Question: I tried to run the following command to select rows from "my_data" based on the first row of "conditions" - but this returns an empty result:

                      my_data[my_data$var_1 %in% unlist(conditions[1,1]) &
                                  my_data$var_2 %in% unlist(conditions[1,2]), ]
                      
                      [1] var_1 var_2 var_3 var_4 var_5
                      <0 rows> (or 0-length row.names)
                      

                      I tried to look more into this by "inspecting" these conditions:

                      class(conditions[1,1])
                      [1] "character"
                      

                      This makes me think that the "unlist()" command is not working because the conditions themselves are a "character" instead of a "list".

                      Is there an equivalent command that can be used here that plays the same role as the "unlist()" command so that the above statement can be run?

                      In general, I am trying to produce the same results as I would have gotten from this code - but keeping the format I was using above:

                      my_data[my_data$var_1 %in% c("1", "3", "4") &
                                  my_data$var_2 %in% c("5", "6"), ]
                      

                      ANSWER

                      Answered 2022-Apr-10 at 05:36

                      Up front, "1,3,4" != 1. It seems you should look to split the strings using strsplit(., ",").

                      expected <- my_data[my_data$var_1 %in% c("1", "3", "4") & my_data$var_2 %in% c("5", "6"), ]
                      head(expected)
                      #     var_1 var_2 var_3 var_4 var_5
                      # 18      3     6     2     2     9
                      # 129     3     5     3     2     8
                      # 133     4     5     6     5     8
                      # 186     1     6     6    10    10
                      # 204     4     6     4     2     6
                      # 207     1     5     3     2     9
                      
                      out <- my_data[do.call(`&`, 
                        Map(`%in%`,
                            lapply(my_data[,1:2], as.character), 
                            lapply(conditions, function(z) strsplit(z, ",")[[1]]))),]
                      head(out)
                      #     var_1 var_2 var_3 var_4 var_5
                      # 18      3     6     2     2     9
                      # 129     3     5     3     2     8
                      # 133     4     5     6     5     8
                      # 186     1     6     6    10    10
                      # 204     4     6     4     2     6
                      # 207     1     5     3     2     9
                      

                      Edit: update for new conditions: change do.call to Reduce:

                      conditions = data.frame(cond_1 = c("1,3,4", "4,5,6"), cond_2 = c("5,6", "7,8,9"), cond_3 = c("4,6", "9"))
                      out <- my_data[Reduce(`&`,
                        Map(`%in%`,
                            lapply(my_data[,1:3], as.character),
                            lapply(conditions, function(z) strsplit(z, ",")[[1]]))),]
                      head(out)
                      #     var_1 var_2 var_3 var_4 var_5
                      # 133     4     5     6     5     8
                      # 186     1     6     6    10    10
                      # 204     4     6     4     2     6
                      # 232     1     5     6     5     8
                      # 332     3     6     6     5    10
                      # 338     1     5     6     3     6
                      

                      Source https://stackoverflow.com/questions/71813866

                      Community Discussions, Code Snippets contain sources that include Stack Exchange Network

                      Vulnerabilities

                      No vulnerabilities reported

                      Install infovore

                      You can download it from GitHub.
                      You can use infovore like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the infovore component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

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                      • gh repo clone paulhoule/infovore

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