spring-in-action | : blue_book : :green_book : spring实战学习代码

by sunweiguo Java Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | spring-in-action Summary

spring-in-action is a Java library. spring-in-action has no bugs, it has no vulnerabilities and it has low support. However spring-in-action build file is not available. You can download it from GitHub.

spring01 简单的hello world程序，展示导入jar包以及用beans.xml配置一个bean,最后进行测试 spring02 spring01的java注解版本 spring03 展示可以基于xml的自动组件扫描注入bean spring04 实现有依赖关系的自动注入，java注解 spring05 实现构造函数的显式注入，java注解 spring06 实现构造函数的显式注入，xml spring07 setter方式注入，xml spring08 java注解方式，展示了异常表演过程中，观众入场就座、离场、中间鼓掌的aop spring09 xml方式，同8 Spitter-springMVC springMVC最基本的原理和配置方式，写了一个spittr blog的欢迎页面 spitter-springMVC02 用jdbc template实现数据库的连接、表单的验证 spitter-springMVC03 spring相关标签 spitter-springMVC04 Apache Titles视图定义布局 spitter-springMVC05 单、多文件上传和下载以及异常处理 spring-hibernate-springMVC 基于java注解的方式完成基本ssh的整合 ssh-xml 基于xml方式完成的整合 security01 helloWorld入门—xml security02 helloWorld入门—java注解 security03 自定义表单—xml security04 自定义表单—java注解 security05 注销、显示视图 security06 基于角色登陆 security07 security与hibernate的简单整合，并且基于角色登陆 security08 在07的基础上增加一个remeber me的功能.

Support

Quality

Security

License

Reuse

Support

spring-in-action has a low active ecosystem.

It has 10 star(s) with 8 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

spring-in-action has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of spring-in-action is current.

Quality

spring-in-action has 0 bugs and 0 code smells.

Security

spring-in-action has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

spring-in-action code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

spring-in-action does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

spring-in-action releases are not available. You will need to build from source code and install.

spring-in-action has no build file. You will be need to create the build yourself to build the component from source.

spring-in-action saves you 24676 person hours of effort in developing the same functionality from scratch.

It has 48132 lines of code, 573 functions and 314 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed spring-in-action and discovered the below as its top functions. This is intended to give you an instant insight into spring-in-action implemented functionality, and help decide if they suit your requirements.

Register profile picture
Determine the target URL for the given authentication .
Configures the given HTTP security .
Get the user name .
Load a user by username .
Saves a new Spitter into the database .
The TilesConfigurer bean .
The view resolver bean .
Resolver for jstl views .
Set local session factory bean .

Get all kandi verified functions for this library.

spring-in-action Key Features

No Key Features are available at this moment for spring-in-action.

spring-in-action Examples and Code Snippets

No Code Snippets are available at this moment for spring-in-action.

Community Discussions

Trending Discussions on spring-in-action

Spring Security login fails despite correct username and password

Spring in Action chapter 6, project is not starting

Spring Data JPA: Example from Spring in Action don't run

Spring - Thymeleaf: Exception processing template

Issue with Passing Interface to controller Constructor

QUESTION

Spring Security login fails despite correct username and password

Asked 2020-Apr-10 at 12:57

Good morning, I have encountered problem with logging into app which uses Spring Security. Every time i try to log in (even though username and password are correct), app redirects me to failure url (in my case it's: /login?error=true). Passwords are encrypted with BCrypt and I'm using MySQL Database to store them.

App is based on code from Spring in Action 5: https://github.com/habuma/spring-in-action-5-samples/tree/master/ch04/tacos

My code:

User class

...

ANSWER

Answered 2020-Apr-10 at 12:57

Make sure your user returns enabled = true, as well as isAccountNonExpired = true (and all others as well, like isAccountNonLocked). Also return an empty list of authorities, not null.

Otherwise Spring Security will treat your user as disabled/locked/whatever and not allow you to login.

Source https://stackoverflow.com/questions/61140489

QUESTION

Spring in Action chapter 6, project is not starting

Asked 2019-Sep-22 at 14:05

I reached 6 chapter in the "Spring in Action" book, but I can't start up the project, and there is nothing i found about it, so i hope you'll help me with this. There is a lot of code, so i think i'll leave a link on a github and error below. I was trying to change entities and database from embedded h2 to mysql but it's not helped.

udp: spring and java versions

...

ANSWER

Answered 2019-Sep-22 at 14:05

hope this will solve your problem: which java version r u using? which hibernate version r u using?

in case you using java 11 you should upgrade to Spring Boot 2.1.x same for hibernate version on java 11 should be Hibernate 5.2.x

Source https://stackoverflow.com/questions/58049332

QUESTION

Spring Data JPA: Example from Spring in Action don't run

Asked 2019-Jun-24 at 08:47

I try to start an example from Spring in action 5. STS shows me the error:

Error starting ApplicationContext. To display the conditions report re-run your application with 'debug' enabled. 2019-06-24 10:47:06.472 ERROR 6300 --- [ restartedMain] o.s.boot.SpringApplication
: Application run failed

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not get constructor for org.hibernate.persister.entity.SingleTableEntityPersister

This's example may receive there: GitHub - Spring in action: Spring Data JPA

Can you help me? If need yet codes from example, I can copy here.

...

ANSWER

Answered 2019-Jun-24 at 08:47

This example does not run with Java > 8.

You have to use Java 8 to run it as it is.

Spring Boot 2.0.x does not support Java 11.

You should upgrade the example to 2.1.6

Source https://stackoverflow.com/questions/56732077

QUESTION

Spring - Thymeleaf: Exception processing template

Asked 2019-Jun-01 at 11:34

I'm following the a book Spring in Action 5th ed., but I believe that is presents a bug.

This is the GitHub of the book. I'm arrived on chap 3 tacos-jdbc source of code

When submit my order a sudden error appears:

and in this way on the terminal:

2019-05-25 16:58:18.164 ERROR 11777 --- [nio-8080-exec-7] org.thymeleaf.TemplateEngine : [THYMELEAF][http-nio-8080-exec-7] Exception processing template "orderForm": An error happened during template parsing (template: "class path resource [templates/orderForm.html]")

org.thymeleaf.exceptions.TemplateInputException: An error happened during template parsing (template: "class path resource [templates/orderForm.html]")

OrderController:

...

ANSWER

Answered 2019-May-25 at 17:13

You are using th:object="${order}" in your orderForm template but Thymeleaf doesn't know about it. You have to let Thymeleaf know about this object by passing it to the template like so

Source https://stackoverflow.com/questions/56306637

QUESTION

Issue with Passing Interface to controller Constructor

Asked 2019-Feb-17 at 18:29

I'm newbie to Spring. Below is the problem I'm facing. Please help.

While starting the dev tools I'm getting the below error

Parameter 0 of constructor in tacos.web.DesignTacoController required a bean of type 'taco.data.IngredientRepository' that could not be found.

Action:

Consider defining a bean of type 'taco.data.IngredientRepository' in your configuration.

IngredientRepository.java

...

ANSWER

Answered 2019-Feb-17 at 18:29

The problem

The TacoCloudApplication does not see any @Component (@Repository is a @Component) defined outside of the tacos package.

From Spring Boot Reference Guide:

A single @SpringBootApplication annotation can be used to enable those three features, that is:

@EnableAutoConfiguration: enable Spring Boot’s auto-configuration mechanism

@ComponentScan: enable @Component scan on the package where the application is located

@Configuration: allow to register extra beans in the context or import additional configuration classes

It sees only @Components defined below the tacos package

The solution

Move JdbcIngredientRepository to a package starting with tacos.

So that your application structure becomes:

Source https://stackoverflow.com/questions/54735033

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install spring-in-action

You can download it from GitHub.
You can use spring-in-action like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the spring-in-action component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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