by   tekul Java Version: Current License: Apache-2.0

kandi X-RAY | spring-security Summary

kandi X-RAY | spring-security Summary

spring-security is a Java library. spring-security has no bugs, it has build file available, it has a Permissive License and it has low support. However spring-security has 1 vulnerabilities. You can download it from GitHub.


            kandi-support Support

              spring-security has a low active ecosystem.
              It has 4 star(s) with 3 fork(s). There are 1 watchers for this library.
              It had no major release in the last 6 months.
              spring-security has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of spring-security is current.

            kandi-Quality Quality

              spring-security has no bugs reported.

            kandi-Security Security

              spring-security has 1 vulnerability issues reported (0 critical, 1 high, 0 medium, 0 low).

            kandi-License License

              spring-security is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              spring-security releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of spring-security
            Get all kandi verified functions for this library.

            spring-security Key Features

            No Key Features are available at this moment for spring-security.

            spring-security Examples and Code Snippets

            Creates a spring security user .
            javadot img1Lines of Code : 11dot img1License : Permissive (MIT License)
            copy iconCopy
            private org.springframework.security.core.userdetails.User createSpringSecurityUser(String lowercaseLogin, User user) {
                    if (!user.getActivated()) {
                        throw new UserNotActivatedException("User " + lowercaseLogin + " was not activated  
            Start the Spring Security OAuth2 client application .
            javadot img2Lines of Code : 3dot img2License : Permissive (MIT License)
            copy iconCopy
            public static void main(String[] args) {
                    SpringApplication.run(SpringSecurityOauth2ClientApplication.class, args);

            Community Discussions


            org.springframework.security.web.access.AccessDeniedException: Access is Denied
            Asked 2021-Jun-14 at 02:53




            Answered 2021-Jun-14 at 02:53

            This issue is solved after correcting up my code

            Source https://stackoverflow.com/questions/67764058


            Spring Boot doesn't recognizing the repository file I've made
            Asked 2021-Jun-11 at 11:19

            I'm trying to get all information from Database inside a rest API in Sprint Boot, but I got the following error. I think Spring Boot doesn't recognize the Repository file I've created.




            Answered 2021-Jun-10 at 18:28

            Perhaps you problem lays on @Autowired annotation on your service.

            Which package is it from? It's not declared on InstallationService file, so it may be getting from another package instead of org.springframework.beans.factory.annotation, like in the other files.

            Source https://stackoverflow.com/questions/67924782


            How to use JWKs with spring?
            Asked 2021-Jun-10 at 17:59

            I got the task to implement jwks on the project. On our project, we have implemented a token validation check with oauth2. We use a jks format certificate to obtain a public key. the private key is not used in our project, since we need to check the validity of the token. Our goal is to get rid of the .jks file. There are too few resources for jwks and therefore some points are not clear. If I understand correctly, then jwks mean that there is a jwks.json file in the resources with keys inside, which we select by kid from the token header. Based on the documentation, it is not clear what kind of file it is and how it is loaded for checking by kid, that is, at what moment it happens.Does anyone have a project that can be used as an example? thanks in advance




            Answered 2021-Jun-10 at 17:59

            You can use spring-boot resource server implementation.

            First, what you need is to add the following dependency to your project

            Source https://stackoverflow.com/questions/67924811


            Client Registration with Spring-boot Oauth2 - tokenUri vs issuerUri
            Asked 2021-Jun-09 at 19:14

            Sorry folks, this may be a newb question. I'm a little lost.

            My Spring-boot environment provides me with keycloak for client authorization, it gives me these.



            Answered 2021-Jun-09 at 19:14

            tokenUri represents the URI for the token endpoint. For example:

            Source https://stackoverflow.com/questions/67906506


            Spring Security Error: java.lang.IllegalStateException: Can't configure anyRequest after itself [SpringBoot update 2.1.4 -> 2.3.11]
            Asked 2021-Jun-08 at 07:13

            I am updating the my existing springboot project from 2.1.4 -> 2.3.11

            The exiting code of class which extends WebSecurityConfigurerAdapter is as below



            Answered 2021-Jun-08 at 07:13

            The problem is that you have 2 times anyRequest() in your configuration. This is no longer allowed starting with Spring Security 5.2.

            Source https://stackoverflow.com/questions/67882836


            Keycloak + Spring Boot + Spring Security does somehow token validation 2 times if the token is invalid
            Asked 2021-Jun-07 at 22:18

            i'm using spring security with keycloak and if i do a request on a specific endpoint with an invalid token, it looks like the token validation is done 2 times, i've also tried to implement my own authentication provider which uses the logic of the keycloak authentication provider and overrided the BearerTokenRequestAuthenticator which does the token validation but it still does the same thing..i'm not sure if maybe the problem comes from some sort of bean definitions Here are same logs where you can see that the string "Verifying access_token" appears 2 times.



            Answered 2021-Apr-17 at 18:59

            You can add JwtAuthorizationTokenFilter and call it before each request

            In your security config use addFilterBefore()

            Source https://stackoverflow.com/questions/67126412


            java.lang.NoSuchMethodError: com.fasterxml.jackson.databind.ObjectMapper.addMixIn
            Asked 2021-Jun-07 at 14:33

            I am trying to run a project in Java and came across the following issues:



            Answered 2021-Jun-07 at 14:33

            There's a suspicious library com.fasterxml.jackson.databind.jar in your WEB-INF/lib. I'd kick it out, because it's probably shadowing jackson-databind-2.9.4.jar. The addMixin method exists since 2.5, so that com.fasterxml.jackson.databind.jar must be 2.4 or older.

            BTW, according to https://mvnrepository.com/artifact/org.springframework/spring-web/5.1.0.RELEASE, you should use jackson 2.9.7, but maybe 2.9.4 works, too.

            Source https://stackoverflow.com/questions/67872831


            Add a filter bean to spring-security filter chain based on condition in applicationContext.xml
            Asked 2021-Jun-06 at 09:35

            We have a spring-security filter chain as below where we provide the list of filters for each url pattern in the applicationContext.xml



            Answered 2021-Jun-06 at 08:13

            Following would switch between filter beans based on condition

            Source https://stackoverflow.com/questions/67847960


            Unable to locate persister: com.package.model.Bus
            Asked 2021-Jun-04 at 13:17

            I am desperately trying to migrate a Spring MVC 4.3.4.RELEASE application with Hibernate 4.3.8.Final to the latest version of Spring Boot, i.e. Spring Boot 2.5

            The idea is to turn it into a Restful API and to drop all views.

            Note : I did not create a custom configuration on the new spring-boot project.

            My architecture looks like :

            1. The controller
            2. The DTO
            3. The service
            4. The DAO
            5. The entity

            Here is my pom.xml file :



            Answered 2021-Jun-04 at 13:17

            In ApplicationConf you tell Hibernate to scan the com.package.repository package but your Bus entity class seems to be in the com.package.model package.

            Try changing:

            Source https://stackoverflow.com/questions/67829558


            Postman gives 401 Unauthorized - Spring Boot & MYSQL
            Asked 2021-Jun-04 at 10:51

            Firstly: Yes, i know there's lots of this question already asked but no one really helped me much.


            -I've tried making a simple Auth with my username+password from MySQL credentials into the Postman but didn't worked

            I've tried to remove the cookies from postman and that did not work.


            link where i got the idea: youtube link for this crud web app

            I'm trying to develop an simple CRUD web app with Spring Boot, Lombok, JPA and Hibernate, MySQL. Everytime i try to make a POST request into Postman it doesn't give me anything(401 Unathorized), as shown here:

            It only gives me "401 Unauthorized".

            Of course when i run the project it gives me the DB shown in MYSQL

            Here's the project content:(That YML file has nothing in it)

            Here's some code:




            Answered 2021-Jun-04 at 10:51

            It was my fault from the start: It was automatically checked from the checkbox in IntelliJ "Spring Security". I unchecked it and it all worked.

            Source https://stackoverflow.com/questions/67823128

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


            No vulnerabilities reported

            Install spring-security

            You can download it from GitHub.
            You can use spring-security like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the spring-security component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .


            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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