Trie | Mixed Trie and Levenshtein distance implementation | Natural Language Processing library
kandi X-RAY | Trie Summary
kandi X-RAY | Trie Summary
A Mixed Trie and Levenshtein distance implementation in Java for extremely fast prefix string searching and string similarity.
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Top functions reviewed by kandi - BETA
- Main entry point for testing
- Calculates the recursive Levenshtein distance of a given word
- Inserts a word into trie
- Remove a word from trie
- Prints the trie
- Show the Trie
- Initializes the boolean state of the specified node
- Is visited boolean
- Depth - first search
- Print a vector
- Main method to test trie
- Prints a trie
- Test entry point
- Returns the word s similarity between the given word and maximum distance
Trie Key Features
Trie Examples and Code Snippets
Community Discussions
Trending Discussions on Trie
QUESTION
I'm trying to write a code that split a spaceless string into meaningful words but when I give sentence like "arealways" it returns ['a', 'real', 'ways'] and what I want is ['are', 'always'] and my dictionary contains all this words. How can I can write a code that keep backtracking till find the best matching?
the code that returns 'a', 'real', 'ways':
splitter.java:
...ANSWER
Answered 2022-Mar-03 at 16:45Using the OP's split method and the implementation of Trie found in The Trie Data Structure in Java Baeldung's article, I was able to get the following results:
QUESTION
Suppose that I have implemented two Python types using the C extension API and that the types are identical (same data layouts/C struct) with the exception of their names and a few methods. Assuming that all methods respect the data layout, can you safely change the type of an object from one of these types into the other in a C function?
Notably, as of Python 3.9, there appears to be a function Py_SET_TYPE, but the documentation is not clear as to whether/when this is safe to do. I'm interested in knowing both how to use this function safely and whether types can be safely changed prior to version 3.9.
I'm writing a Python C extension to implement a Persistent Hash Array Mapped Trie (PHAMT); in case it's useful, the source code is here (as of writing, it is at this commit). A feature I would like to add is the ability to create a Transient Hash Array Mapped Trie (THAMT) from a PHAMT. THAMTs can be created from PHAMTs in O(1) time and can be mutated in-place efficiently. Critically, THAMTs have the exact same underlying C data-structure as PHAMTs—the only real difference between a PHAMT and a THAMT is a few methods encapsulated by their Python types. This common structure allows one to very efficiently turn a THAMT back into a PHAMT once one has finished performing a set of edits. (This pattern typically reduces the number of memory allocations when performing a large number of updates to a PHAMT).
A very convenient way to implement the conversion from THAMT to PHAMT would be to simply change the type pointers of the THAMT objects from the THAMT type to the PHAMT type. I am confident that I can write code that safely navigates this change, but I can imagine that doing so might, for example, break the Python garbage collector.
(To be clear: the motivation is just context as to how the question arose. I'm not looking for help implementing the structures described in the Motivation, I'm looking for an answer to the Question, above.)
...ANSWER
Answered 2022-Mar-02 at 01:13According to the language reference, chapter 3 "Data model" (see here):
An object’s type determines the operations that the object supports (e.g., “does it have a length?”) and also defines the possible values for objects of that type. The type() function returns an object’s type (which is an object itself). Like its identity, an object’s type is also unchangeable.[1]
which, to my mind states that the type must never change, and changing it would be illegal as it would break the language specification. The footnote however states that
[1] It is possible in some cases to change an object’s type, under certain controlled conditions. It generally isn’t a good idea though, since it can lead to some very strange behaviour if it is handled incorrectly.
I don't know of any method to change the type of an object from within python itself, so the "possible" may indeed refer to the CPython function.
As far as I can see a PyObject is defined internally as a
QUESTION
I am attempting to construct an immutable Trie defined as such:
...ANSWER
Answered 2022-Jan-12 at 01:10The appears to get at what you're after.
QUESTION
When I was doing Leetcode 820, building a Trie, there is a bug in my code. I found it, also corrected it, but did NOT understand why. Could anyone help?
I made a simple test code here. Program 1 and Program 2 are doing same thing, that is, given a word list words, it builds a Trie in reversed order of these words. Variable trie stored the root of Trie, variable leaves stored beginning character of each word. The only difference between program 1 and program 2 is in line # difference, and I focus on the different results of leaves in 2 programs.
ANSWER
Answered 2022-Jan-06 at 06:27One obvious difference:
key in dictwill only give you a false value if the key is not there.dict.get(key)will give you the actual value for that key which is then treated as a truthy or falsey value. So, if the value for an existing key is falsey (such as zero or the empty string), theifstatement will not fire (though it will in the previous bullet point).
The following example shows this:
QUESTION
I'm trying to implement a Trie/Prefix Tree in Rust and I'm having trouble with the borrow checker. Here is my implementation so far and I'm getting an error when I call children.insert.
...cannot borrow
*childrenas mutable because it is also borrowed as immutable
ANSWER
Answered 2022-Jan-02 at 00:25When you're doing multiple things with a single key (like find or insert and get) and run into borrow trouble, try using the Entry API (via .entry()):
QUESTION
An affix can be a prefix (before word), infix (in the middle of a word), or suffix (after word). I have a list of 200k+ latin/greek names used in biological taxonomy. It turns out there is no centralized list of all the affixes used in the taxonomy, unfortunately, other than this very basic list.
The question is, how can I take that 200k+ list of latin/greek names, and divide it into a list of affixes (ideally using just plain JavaScript)?
I don't really know where to begin on this one. If I construct a trie, I need to somehow instead test for specific chunks of words. Or if the chunk can be extended, don't include the chunk until we reach a final extension of some sort...
...ANSWER
Answered 2021-Dec-21 at 02:53Here is a simple approach, but it is probably in the hours period. Also, you could do it in JavaScript, but I'll take a generally Unixy approach that you could write in any language because that is simple to think about.
First, let's take your file, and add markers to the start/end of each word, and spaces between the letters. So your example would become:
QUESTION
My question is in the title. It seems the Trie tree is quite fit for string indexing, and why is it that no mainstream databases use it as an indexing strategy.
...ANSWER
Answered 2021-Dec-24 at 13:46Disks or SSDs are read in blocks, and the B+Tree indexes that databases use are optimized according to that structure. The B+Tree minimizes the average number of blocks you have to read to perform a lookup. They also allow you to update the index without changing too many blocks, and maximize the utility of cache.
Tries don't have these advantages. The one advantage they do provide is compressed storage of common prefixes, but for the short strings that are usually used as DB keys, that isn't much of an advantage. Sometimes specialized index structures are built to compress common prefixes, but again they're designed around the block structure of the storage.
QUESTION
How does a Tree's parent node get updated with the child updates we perform? Specifically like when you do a BFS or DFS search, perform a check at the node, and then update that node. What causes in memory or in the programming language to know "Oh hey, I have to make this update to the Root node as well!"
In my example I'm using a Trie (not really important but I will just refer to it as a Tree). I have this BFS search below that searches through a bunch of nodes and will update with a specific word value. The comment I have is where my question lies. That child node is currently stored in "deque." How does the program know I mean to update the value within Root, not just the value pass into the variable "deque?"
To me, what I think SHOULD be happening is Root shouldn't be updated and the only thing that gets updated is the variable "deque," and then after it's done, everything gets garbage collected and Root remains the same. Instead, Root gets updated when "deque" gets updated. Perhaps I missed this in my Data Structures course, but it has been bugging me for a while now and I've been having trouble finding resources that explain this.
...ANSWER
Answered 2021-Dec-03 at 04:53I think you are encountering what is roughly a pass by value vs pass by reference issue. When a function is pass by value, the parameter of that function is copied such that the function gets its own distinct version and the caller won't see changes the function makes to the parameter. However, if a function is pass by reference, no copy is made and if the function makes changes to a parameter the caller will see the changes that were made.
C# and Java are a little funny here because they are always pass by value (unless you explicitly tell C# to do otherwise), but they "pass references by value" too. That is, when you pass a function a reference type (like an object or a class), what the function receives is a copy of the reference to it (not a deep copy of the underlying object). This means the underlying object can still be changed inside a function, because that function has its own reference to it.
A consequence of this is that when you pass the Enqueue method a reference type, as your Node objects are, what is stored in the queue are just (copies of) references to the same underlying objects which live outside the queue. That is, the elements of your queue are not deep copies of your tree's nodes: they are references to the same underlying Node objects. When you Deque() into the "deque" variable you're therefore just creating another alias which refers to some node which you might otherwise have been able to reach in a traversal directly from the Root node. This way, when you modify the properties of the "deque" node, you're directly modifying the properties of some Node object as it exists in the tree under the Root node—not a copy of that object with its own address in memory but the same underlying object.
This is why when deque gets garbage collected the changes persist: deque just contained copies of references to the nodes which already existed in the Root tree. There's nothing your program had to figure out to know to make the changes you made via deque also affect nodes in the Root tree. Because deque contained references to those same underlying nodes, changes made through it were already directly modifying those nodes, and so after deque went out of scope the changes naturally persisted.
QUESTION
I have this error when I add node-sass to my react app, I can't deploy the app in netlify I trie to use all build cmd like CI= run build please check the result in below, the app is deployed in netlify when I remove node sass from my app and is work help me if you can or tell me if you need more information
...ANSWER
Answered 2021-Nov-06 at 06:51This probably seems to be a version mismatch error. Downgrading the Node version to something like 12.8.0 worked for me.
To do the same in Netlify, go to Build & Deploy -> Environment and add the NODE_VERSION environment variable. Refer below attached screenshot:
QUESTION
I am trying to solve a Trie problem, for which I create a TrieNode class as below:
ANSWER
Answered 2021-Oct-27 at 15:19You might do:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Trie
You can use Trie like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Trie component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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