neo | Original deepCode no learning statistical model
kandi X-RAY | neo Summary
kandi X-RAY | neo Summary
Original deepCode: no learning + statistical model:. ant neoDeep -Dapp=./problem/DeepCoder-New/prog13.json -Ddepth=3 -Dlearn=false -Dstat=false -Dfile="".
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Top functions reviewed by kandi - BETA
- Perform the type - checking of a problem
- Generate node specification for a node
- Internal abstract method
- Print out the UN SAT core
- Performs a SMT constraint
- Abstract recursive code
- Verify conflict
- Compute the head of the input set
- Verify 2
- Return a list of numeric columns
- Verify 2 conflict
- Performs the search algorithm
- Verifies that the objects are valid
- Converts a DataFrame to a DataFrame
- Main function
- Generate an example template
- N - gram
- Verify the conflict
- Main entry point to the Morphia problem
- Returns the productions for a given symbol
- Main implementation of unification
- Gets the productions
- Build the data from the given functions
- Returns the productions for a given symbol
- Returns the productions for the given symbol
- Retrieves the list of productions
neo Key Features
neo Examples and Code Snippets
Community Discussions
Trending Discussions on neo
QUESTION
I am attempting to add another checkbox to this program but for some reason it will not display when I run the program. Only the check box for the blue pill displays. I have attempted to add a couple things or change the way the program is structured, but nothing I have done so far has helped.
Code Below:
...ANSWER
Answered 2021-Jun-15 at 04:38When you're stuck on a problem, it never hurts to go back and consult the documentation.
You'll find information like this:
A border layout lays out a container, arranging and resizing its components to fit in five regions: north, south, east, west, and center. Each region may contain no more than one component, and is identified by a corresponding constant: NORTH, SOUTH, EAST, WEST, and CENTER. When adding a component to a container with a border layout, use one of these five constants...
When you add your button, you do this:
QUESTION
I'm doing a project with a Ublox NEO 6m gps and a Raspberry Pi 4 model B and I'm stuck on the following error:
...ANSWER
Answered 2021-Jun-07 at 15:17I'm assuming this is due to your code re-initializing the connection each loop. I recommend trying the following code instead --
QUESTION
Looked through past posts on SO but couldn't find the solution.
Environment:
- Mac OS Big Sur
- Rails 6.1.3.2
- ruby 3.0.1p64
Github repo https://github.com/tenzan/ruby-bootcamp
Added Bootsrtap 5 according to https://blog.corsego.com/rails-6-install-bootstrap-with-webpacker-tldr
To push to heroku I ran git push heroku main
Output:
...ANSWER
Answered 2021-Jun-10 at 00:32ModuleNotFoundError: Module not found: Error: Can't resolve '@popperjs/core'
suggests that you need to install @popperjs/core
.
QUESTION
I have two tables:
- g_relationships (id,request_id,receiver_id,status,approved)
- g_users (which contains: id,username,...)
I have a hard time making a query that adds a temporary column, checks whether userid: 4 exists in request_id or receiver_id column, and take the other userid and fetch username from g_users and adds it to the temporary column.
For example: Lets say I have userid 4. I then want to select g_relationships, and left join with g_users, and add a column that checks whether my userid (4) is in the request_id or the receiver_id column, and takes userid which isn't mine, and checks which username that it is and fills the new column with.
For example: a correct result would look like this: (if I were to receive a friend request)
id request_id receiver_id status approved friend(new_column) 1 3 4 friend no NeoBut if I was the one who sent the friend request it would look like this
id request_id receiver_id status approved friend(new_column) 1 4 3 friend no NeoIn other words, the query should always check in what column that I don't appear , and take that userid, and check against g_users table and place the username from there into friend column.
This is what I have come up with so far, but this only checks then request_id is not 4, and also doesn't populate the temporary column "friend" with the username :/
...ANSWER
Answered 2021-Jun-09 at 19:58Have you tried this? It will join on either of the two ids.
QUESTION
I have problems with URL Processing in Laravel mix.
here is my app.css
...ANSWER
Answered 2021-Feb-19 at 20:52First, in webpack.mix.js, do you need the SASS line? Because it's causing issues.
QUESTION
Using beautifulsoup to scrape a website (this guy as an example here:https://rocket-league.com/player/Guuter), I have managed to get the text I want. However, I do not know how to properly assign each string to certain variables to after format them correctly. It is a trading website so I want to separate the trade into the "has" and "wants" section
Where I have got so far (btw the massive gaps are included):
...ANSWER
Answered 2021-Jun-01 at 16:53I have taken items from a
tag and append into lst
and used join operation on by dividing into 2 parts you can use this code but if total items only were 2 on web page you can put condition to handle it
QUESTION
I am trying to create a youtube type of video player app(for learning purposes only) with expo and react native.
But I have this very weird issue that each time I save file and hot reload starts it throws error like
RangeError: Maximum call stack size exceeded
I have already looked about this and found that this error is occurring because of recursion. But I can't find any recursion in my code.
But more weird is that first time app runs fine and when I change something it shows this error and app crashes. But if I save the same file without any changes it refreshes and works normally. so it is like each even time I save it shows error and next time I save file it goes away.
I am using expo go app to test this app on my physical device.
Exact code of file is this:
...ANSWER
Answered 2021-May-21 at 05:09Simple solution for this is to use Animated.View component wrapped around Video component for your required animated styling.
But still I have no luck finding the real problems solution.
QUESTION
I am trying to get the second last value in each row of a data frame, meaning the first job a person has had. (Job1_latest is the most recent job and people had a different number of jobs in the past and I want to get the first one). I managed to get the last value per row with the code below:
first_job <- function(x) tail(x[!is.na(x)], 1)
first_job <- apply(data, 1, first_job)
...ANSWER
Answered 2021-May-11 at 13:56You can get the value which is next to last non-NA value.
QUESTION
const a = [
0: {market: "KRW-BTC", korean_name: "비트코인", english_name: "Bitcoin"}
1: {market: "KRW-ETH", korean_name: "이더리움", english_name: "Ethereum"}
2: {market: "KRW-NEO", korean_name: "네오", english_name: "NEO"}
3: {market: "KRW-MTL", korean_name: "메탈", english_name: "Metal"}
4: {market: "KRW-LTC", korean_name: "라이트코인", english_name: "Litecoin"}
5: {market: "KRW-XRP", korean_name: "리플", english_name: "Ripple"}
6: {market: "KRW-ETC", korean_name: "이더리움클래식", english_name: "Ethereum Classic"}
7: {market: "KRW-OMG", korean_name: "오미세고", english_name: "OmiseGo"}
8: {market: "KRW-SNT", korean_name: "스테이터스네트워크토큰", english_name: "Status Network Token"}
9: {market: "KRW-WAVES", korean_name: "웨이브", english_name: "Waves"}
10: {market: "KRW-XEM", korean_name: "넴", english_name: "NEM"}
11: {market: "KRW-QTUM", korean_name: "퀀텀", english_name: "Qtum"}
12: {market: "KRW-LSK", korean_name: "리스크", english_name: "Lisk"}
]
const b = [
0: {market: "KRW-BTC", trade_date: "20210506", trade_time: "144435", trade_date_kst: "20210506", trade_time_kst: "234435", …}
1: {market: "KRW-ETH", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
2: {market: "KRW-NEO", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
3: {market: "KRW-MTL", trade_date: "20210506", trade_time: "144432", trade_date_kst: "20210506", trade_time_kst: "234432", …}
4: {market: "KRW-LTC", trade_date: "20210506", trade_time: "144433", trade_date_kst: "20210506", trade_time_kst: "234433", …}
5: {market: "KRW-XRP", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
6: {market: "KRW-ETC", trade_date: "20210506", trade_time: "144437", trade_date_kst: "20210506", trade_time_kst: "234437", …}
7: {market: "KRW-OMG", trade_date: "20210506", trade_time: "144437", trade_date_kst: "20210506", trade_time_kst: "234437", …}
8: {market: "KRW-SNT", trade_date: "20210506", trade_time: "144434", trade_date_kst: "20210506", trade_time_kst: "234434", …}
9: {market: "KRW-WAVES", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
10: {market: "KRW-XEM", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
11: {market: "KRW-QTUM", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
12: {market: "KRW-LSK", trade_date: "20210506", trade_time: "144436", trade_date_kst: "20210506", trade_time_kst: "234436", …}
]
...ANSWER
Answered 2021-May-06 at 15:17something like that:
QUESTION
I'm trying to build a dictionary that should contain data about a coin, date and its close price on the given date.
The data I'm looping through, which I am using as the base out of which I want to build my dict, look like this (it's a Python list):
...ANSWER
Answered 2021-Apr-25 at 08:09The structure you are building has several levels of nesting. Let's think about them inside out.
Each coin's data is a mapping from date to value. It makes sense for this to be a single dict
rather than a list of singleton dictionaries. To add a new mapping, just set coindict[date] = value
The structure above this is a dictionary of coin names, which are strings, with a coindict
as described above as the value of each.
Python's defaultdict
provides a good way to avoid having to go through
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Python 2.7
NumPy and Tensorflow
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