kandi X-RAY | lettuce Summary
kandi X-RAY | lettuce Summary
lettuce - A scalable Java Redis client. Lettuce is a scalable thread-safe Redis client providing both synchronous and asyncronous connections. Multiple threads may share one connection provided they avoid blocking and transactional operations such as BLPOP, and MULTI/EXEC. Multiple connections are efficiently managed by the excellent netty NIO framework. This version of lettuce has been tested against redis 2.6.12.
Top functions reviewed by kandi - BETA
- Decodes the output from the queue
- Attempt to decode a redis response
- Read a long
- Read a line
- Handles requests request
- Write a positive integer to a channel buffer
- Encodes the command
- Shuts down the client
- Closes the connection
- Called when a channel is closed
- Decode ascii characters
- Set the score value
- Handles the incoming message
- Received a message
- Completes commands
- Set the key
- Set the message type
- Reconnect to the remote address
- Completes the stack
- Called when a channel is connected
lettuce Key Features
lettuce Examples and Code Snippets
Trending Discussions on lettuce
I'm newbie and just starting coding a couple of months ago. I'm creating an app with react native with expo and I'm having trouble updating a map field into the document. So far, when I needed to update a filed(for example a name) I was doing the following:...
ANSWERAnswered 2022-Mar-26 at 16:18
To convert the array into a map, try using
reduce() as shown below:
So basically I am making an online restaurant website where you can order food. I am going to make cards for each food item listed. Right now, I am making buttons that add and subtract the number of each item the customer wants to purchase....
ANSWERAnswered 2022-Mar-11 at 18:42
The main issue is that
currentNumber is shared between both counters, making it impossible to differentiate one from the other.
Additionally, keeping state in the HTML (the current price per burger) and using
onclick makes it difficult to manage scoping.
I suggest removing all of the state from the HTML, then writing a loop over the
.food-item elements to add click handlers to their buttons and be able to manipulate each of their outputs. You can use a data structure like
burgers to keep track of prices for each burger instead of separate variables, which aren't amenable to looping over.
Here's one approach:
SELECT value from table1 limit 3;
ANSWERAnswered 2022-Mar-11 at 08:46
you could just use SPLIT if you know it's always the "second" value in the series. If that is not true, then the REGEPX version will not help you ether.
This is my first post here so I hope I am providing enough info to be clear in my question.
I have a SQL/BigQuery table that can be simplified to the following:Sale ID Item Description 2540 111 Apple 2540 112 Lettuce 2541 113 Bread
And essentially what I am trying to achieve is create a new column where whenever a Sale ID has a given Item, a marker will be placed on all rows that share that Sale ID. So, using Item 111 as an example, since Apple is a fruit, the top two rows would contain the Marker "Contains Fruit in Sale" and the new table would look like this:Sale ID Item Description Marker 2540 111 Apple Contains Fruit in Sale 2540 112 Lettuce Contains Fruit in Sale 2541 113 Bread
Hopefully this makes sense. I have no idea how to go about doing this. Thanks in advance for your help!...
ANSWERAnswered 2022-Mar-11 at 08:33
Consider the below query for your requirement:
I am trying to see how word frequency correlates with phonotactic probability using R, but there are a few issues. First, and most generally, I don't know merge these two graphs together (i want them to appear on the same axis).
This leads to a second problem because the first graph's y values are in probabilities, and the second is a count, so the scales are not the same. Should I combine data frames first, or is there a simpler way to merge two graphs?
Here is the reproducible sample, and the code for my graphs:...
ANSWERAnswered 2022-Mar-09 at 20:44
One way could be to use a second y axis. Although this method is to be used critically, in this situation I think it is appropriate:
I have a list of lists and I want to learn how to sort the list by the element at index 1 but also sorted by the element at index 2 if index 1 returns the same number for two items.
I want to do this without the use of inbuilt functions and methods so that I can continue to develop my understanding of lists and how to manipulate them.
- I have a list of lists
- Each sublist has the same number of elements
- I am trying to sort them in descending order by creating a new unsorted list which is a copy of the original list (I don't want to modify the original unsorted list) and looping over the copy of the unsorted list to grab the highest number in (from index 1) and then appending that to a newly created sorted_lists variable
- I then remove that list from the original unsorted list
- I repeat the process until one by one the remaining lists with the highest value is added to the new sorted list and removed from the original list
I have tried a few different things but cannot get it to work. Any help would be appreciated....
ANSWERAnswered 2022-Mar-08 at 12:42
In your code sample, you define
food_list as a
tuple while mentioning a list of list. In order to use list function like remove, copy or append, you need to add brackets around your lists.
food_list should be defined this way :
I am new to Python, and I am trying to use Python to query a Microsoft SQL Server database. The data is returned in this format:
(('orange,apple,coconut',), ('lettuce,carrot,celery',), ('orange,lemon,strawberry',))
What I am trying to do is check to find a match, to see if some data from another data table exists in that data from SQL Server.
When I try to use the "in" to check, it does not work for me. I thought if I could convert the data (a tuple of tuples) into a list, then I could more easily search and match. But that doesn't work because there are some brackets around each list element. At least, that is the what I think because, if I manually recreate the list without the extra brackets, then I can search successfully.
I am wondering if there is a way to remove that extra bracket. Or, maybe there is a better approach. I have read several posts here and other articles, and so far, I have not found an approach.
Here is what I have tried. As you can see, the final one works, but that is what i have created manually....
ANSWERAnswered 2022-Feb-26 at 08:49
I have a 2-column dataframe. First column contains a single entry of a class of items (in this case, vegetables). The second column is the incoming
new_item, which are grocery items of different categories (meat, fruit, veg, etc).
ANSWERAnswered 2022-Feb-24 at 19:43
current <- tibble::tribble( ~prev_veg, ~new_item, "cabbage", "lettuce", NA, "apple", NA, "beef", NA, "spinach", NA, "broccoli", NA, "mango" ) target_veg <- c("cabbage", "lettuce", "spinach", "broccoli") library(dplyr, warn.conflicts = FALSE) library(purrr) current %>% mutate( prev_veg = accumulate( head(new_item, -1), ~ if_else(.y %in% target_veg, paste(.x, .y, sep = ", "), .x), .init = prev_veg ) ) #> # A tibble: 6 × 2 #> prev_veg new_item #> #> 1 cabbage lettuce #> 2 cabbage, lettuce apple #> 3 cabbage, lettuce beef #> 4 cabbage, lettuce spinach #> 5 cabbage, lettuce, spinach broccoli #> 6 cabbage, lettuce, spinach, broccoli mango
I have a list of lists containing characteristics of food.
What I want to be able to do is search take input from the user for the name of the food and then: IF the food is in the list, print details about the food IF the food is NOT in the list, print a single line to advise the food is not found
I have managed to create use a for loop to iterate over the list and return details of the food if the food is found. What I am struggling to do is return a SINGLE line to say 'Food not found' if the food is not in the lists.
I have tried a while loop to basically say 'while the food is not found, tell the user and ask for input again' but this hasnt worked I have tried 'if food is not in the list' print out the statement but that either seems to print the same line for as many iterations as the food is not found OR it prints the line even if the food is in the list.
Here is the code:...
ANSWERAnswered 2022-Feb-21 at 21:26
There are a bunch of ways to implement the behavior you want. Here's one.
I have a MySQL table like the following:BurgerExtra ID Burger ExtraName BurgerExtraPrice 1 Mayo 1 2 Burger Sauce 1 3 Ketchup 1 4 Hot Chilli Sauce 1 5 Pickles 1 6 Musard 1 7 Lettuce 1 8 Tomatoes 1 9 Grilled Onions 1 10 Onions 1 11 Jalapeños 1 12 American Cheese 1 13 Red Relish 1 14 Chipotle 1 15 Bacon 4 16 Egg 2 17 Cheese Sauce 3
But I need to show the data in the following format:
Mayo - Burger Sauce - Ketchup - Hot Chilli Sauce - Pickles - Mustard - Lettuce Tomatoes - Grilled Onions - Onions - Jalapeños - American Cheese - Red Relish Chipotle Mayo 1 Bacon 4 - Egg 2 - Cheese Sauce 3
I have tried...
ANSWERAnswered 2022-Feb-21 at 08:46
You can use
No vulnerabilities reported
You can use lettuce like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the lettuce component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
Reuse Trending Solutions
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page