OpenVideo | 视频APP--数据源自优酷
kandi X-RAY | OpenVideo Summary
kandi X-RAY | OpenVideo Summary
视频APP--数据源自优酷
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Top functions reviewed by kandi - BETA
- Override when the view is drawn .
- Handles a touch event .
- Get CPU feature information
- Parse metadata .
- Loads the image if necessary .
- Perform a HTTP request .
- Runs the network request .
- Attempt to retrieve an image from the cache .
- Transforms a bitmap .
- Creates an HttpRequest for the given request .
OpenVideo Key Features
OpenVideo Examples and Code Snippets
Community Discussions
Trending Discussions on OpenVideo
QUESTION
I having a problem optimizing the performance of my application build in Vuejs3/Vite and Aframe. I need to somehow prefetch 6 videos. The problem is that each time I open a modal the browser fetches a video again. I want the browser to only fetch it once and store it somehow.
My application should look like this. Homepage has 6 buttons. On click, each button opens a modal. Inside the modal there a 6 videos. So, when a user clicks on the 2nd button the modal opens and inside it is only the 2nd video playing automatically. When a user clicks on a "close" button the modal is closed and the video is paused.
Right now my code looks like this: HTML template
...ANSWER
Answered 2021-Dec-29 at 15:35Wrapping your component with should work:
QUESTION
I'm looking to integrate multiple embedded youtube videos (using Iframe's) that pop up on the screen after a user clicks a custom button.
There are a lot of similar questions that work for one video, but not multiple videos on the same page.
The button is nested within a set of div's uniform across all the videos. After the video pop's up, clicking outside of the video should make it disappear.
The below code finds the parent element after the button is clicked and should open that specific video modal, but instead, nothing happens.
Any help is much appreciated!
...ANSWER
Answered 2021-Sep-22 at 21:12First off, your modal
and trailerbox
are not defined correctly. They are offspring of a sibling of the button so .closest()
will not find them.
For each element in the set, get the first element that matches the selector by testing the element itself and traversing up through its ancestors in the DOM tree.
It tests itself, then the parent, so it will not encounter those elements. You need to use .find()
from the parent.
QUESTION
I've got an Angular 12 app that is using Firebase storage to store some files in a directory. I implemented the integration with Firebase using the AngularFire solution. The docs on how to use the AngularFire storage functions don't seem to include how to list all files in a directory. There are some docs on the Firebase site that speak to this (listAll) but I can't seem to make the code work in Angular with AngularFire. Code sample from the Firebase site below...
...ANSWER
Answered 2021-Sep-20 at 04:14After some trial and error I figured out how to make this work in Angular 12. For those who are interested in getting a list of files in their Firebase storage repository and then populating an array so that you can display the filename and the download link in your Angular component the code I used is found below. I'll be the first to admit I'm not the greatest coder in the world though so use at your own risk!
QUESTION
I have a video library page on my site and on this page I need to show videos uploaded to the MUX server. I have a problem with video playback through this library. Doc: https://docs.mux.com/guides/video/playback-videojs-with-mux. Code example:
...ANSWER
Answered 2021-Jun-18 at 01:25I've tried it myself and you essentially need to install @mux/videojs-kit
and to provide your env
variable as suggested in the docs.
Here is how it looks like
QUESTION
I have 3 blocks, when opening one, all should hide. I wrote the simplest code (I'm a beginner), I understand that it can and should be optimized. How can I do that? I'm thinking of using "if else" construction, but not sure how to do it correctly.
...ANSWER
Answered 2021-Jan-13 at 15:32Delegate
Here is a start
QUESTION
My code is here
...ANSWER
Answered 2021-Jan-03 at 12:46You need to set for settings like this or in plist.
QUESTION
So I have a VideoView but when I try to play video (which is in my res/raw folder)it gives me null pointer exception. I tried using video.setVideoUri(uri)
and also video.setVideoPath(path)
but it still shows null pointer exception.
Activity:
...ANSWER
Answered 2020-Oct-29 at 14:22You should add a contentView
on your activity onCreate
So change your onCreate
Like this:
QUESTION
I used Android 4.4.4 version. And My application used MediaPlayer.
I have get media list in device and each media put in mutableListOf. Next In the for loop that medias played.
But, It was dead after some time.
...ANSWER
Answered 2020-Oct-20 at 04:16I think the problem is that you are creating mutiple instances of MediaPlayer which is causing OutOfMemoryError exception. Also, do not forget to release MediaPlayer instance when you are done with playback. According to MediaPlayer Documentation:
It is also recommended that once a MediaPlayer object is no longer being used, call release() immediately so that resources used by the internal player engine associated with the MediaPlayer object can be released immediately. Resource may include singleton resources such as hardware acceleration components and failure to call release() may cause subsequent instances of MediaPlayer objects to fallback to software implementations or fail altogether. Once the MediaPlayer object is in the End state, it can no longer be used and there is no way to bring it back to any other state.
Add a method in MediaItemPlayer to release MediaPlayer after use:
QUESTION
I am trying to create a media player without MediaPlayer
class.Just a very basic videoview which selects a file from device and plays it.But I am receiving an error Can't play this video
.
Here's my code:
...ANSWER
Answered 2020-Aug-12 at 03:15I didn't understand what was the problem.But it was solved when I changed onActivityResult
to
QUESTION
Initially I choose a Intent chooser to pick up a media file, and in onActivityResult
i got the uri
ANSWER
Answered 2020-Jul-15 at 12:13think that I saved the uri in database as a string
You no longer have rights to access the content.
How to solve this issue ?
Use ACTION_OPEN_DOCUMENT
to let the user choose the content. Then, in onActivityResult()
, call takePersistableUriPermission()
on a ContentResolver
, to have access to that content for a longer period of time. See this blog post and the documentation for more.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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No vulnerabilities reported
Install OpenVideo
You can use OpenVideo like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the OpenVideo component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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