51job | 前程无忧招聘信息爬取

by zhoubiao188 Java Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | 51job Summary

51job is a Java library. 51job has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

前程无忧(51job)招聘信息爬取

Support

Quality

Security

License

Reuse

Support

51job has a low active ecosystem.

It has 5 star(s) with 6 fork(s). There are no watchers for this library.

It had no major release in the last 6 months.

51job has no issues reported. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of 51job is current.

Quality

51job has no bugs reported.

Security

51job has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

51job does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

51job releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed 51job and discovered the below as its top functions. This is intended to give you an instant insight into 51job implemented functionality, and help decide if they suit your requirements.

Main entry point
Get data from db xml
Get list of jobs from url
Gets HTML response
Gets the job name
Set the company name
Sets the job key
Sets the job name
Set the push date
Set the salary
Set the work address

Get all kandi verified functions for this library.

51job Key Features

No Key Features are available at this moment for 51job.

51job Examples and Code Snippets

No Code Snippets are available at this moment for 51job.

Community Discussions

Trending Discussions on 51job

R : Returning a value from loop when manually stopping it

QUESTION

R : Returning a value from loop when manually stopping it

Asked 2020-Feb-19 at 21:54

I am trying to build a database with rvest. Since I have much data to download, I tried to write several functions that would allow me to interrupt the scraping process and to restart it where I left it. However, while the functions work more or less, whenever I manually interrupt them, I loose the output. Does anyone know a solution that would allow me to stop the function without loosing the dataframe that the loop is building ? I would be glad for any advice!

Some urls that I am trying to scrape data from:

...

ANSWER

Answered 2020-Feb-19 at 21:54

I come across this problem often in webscraping. The key is to store the intermediate results in an environment where they are accessible if your function throws an error. The obvious place is the global environment, but this depends on how you are using your function. If it is part of a package, then you don't want to write to the global workspace. In that case you can have a "storage" environment as part of the package.

Perhaps the neatest way to do this is to delete the intermediate object after the loop is complete, so it will only ever be visible / accessible if the loop throws an error.

Here is a function that demonstrates the principle:

Source https://stackoverflow.com/questions/60308526

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install 51job

You can download it from GitHub.
You can use 51job like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the 51job component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: