lit-date | Light-weight , faster datetime formatter for modern browsers | Date Time Utils library
kandi X-RAY | lit-date Summary
kandi X-RAY | lit-date Summary
Light-weight, faster datetime formatter for modern browsers.
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QUESTION
I have table which stores person, start of holiday and stop of holiday.
I need to count from it, how many working days per month person was on holiday. So I want to partition this table over month. To get holidays I'm using: https://github.com/christopherthompson81/pgsql_holidays
Let's assume I have table for one person only with start/stop only.
...ANSWER
Answered 2021-Jan-28 at 08:15QUESTION
I would like to create GENERIC python code which will fill in the day, month and year to the correct field.
BUT not sure how to.
In the first example, we can see that we have a linkage between label and input by using for parameter (BUT we need to take for parameter from the label and somehow check if it will contain DAY, MONTH and e.t.c..)
In the second example, we can see that input does not have any IDs, by the span wrapper. So we can link label with span and then somehow by using following::/input[0,1,2] find DAY,MONTH and e.t.c..
QUESTION: is it any possible way to create generic code which will work for the first and second examples? ANy best practices?
First website:
...ANSWER
Answered 2020-Apr-29 at 19:56I don't think it is a good idea to spend too much time on a generic solution when a page specific solution is easy when it is done well. If you are sure that all the pages you want to use use the DD/MM/YYYY format and all the fields are numeric then you may try something like this:
QUESTION
I have code that splits records on months based on their length, the code currently works without problem, but I need to calculate how many days passed between these new records so I could get something like this:
...ANSWER
Answered 2019-Feb-04 at 17:45Just use another CTE:
QUESTION
I am trying to create a daily data view from an interval based table looking like this:
...ANSWER
Answered 2018-Nov-22 at 13:10You have a calendar table, awesome. Just use it on the left side of a LEFT JOIN:
QUESTION
#sample data
df.test <- data.frame(id = c(1,2,2,1,1,1),time=c("01:30:00","02:05:00","02:40:01","01:44:01","01:33:01","05:00:01"))
df.test $date.time <- as.POSIXct(df.test $time,format="%H:%M:%S")
#group the time per bour
df.test $date.hour <- cut(df.test $date.time, breaks="hour")
head(df.test)
#count how many people per hour
people.count <- df.test%>%group_by(date.hour)%>% summarize(count.user=n()) %>% arrange(count.user)
people.count
#find the smallest people and show the ralated hour
start.hour <- strptime(as.character(people.count$date.hour[1]),"%Y-%m-%d %H:%M:%S")
#convert time to numeric
num.start.hour <- gsub("[: -]", "" ,start.hour, perl=TRUE)
num.end <- as.numeric(as.POSIXct(start.hour))-1
#print(num.end)
#convert numeric to time
library(anytime)
anytime(num.end)
hr.range <- paste0(format(start.hour,"%H:%M:%S")," - ",format(num.end,"%H:%M:%S"))
hr.range
ANSWER
Answered 2018-May-19 at 08:59Why not use the lubridate package:
QUESTION
I need to display a range of dates in corresponding week for selected month.
Suppose the selected values are $month=2 and $year=2017.
The output should show a list of ranged dates for weeks in that particular month selected.
ANSWER
Answered 2017-Dec-08 at 04:48Here is your solution
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