abba | A/B Testing framework | Runtime Evironment library

 by   7anshuai JavaScript Version: Current License: MIT

kandi X-RAY | abba Summary

kandi X-RAY | abba Summary

abba is a JavaScript library typically used in Server, Runtime Evironment, Nodejs applications. abba has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

abba is a simple a/b testing framework for JavaScript and Node.js. It's a node.js clone with small improvement over @maccman's Abba.
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            kandi-support Support

              abba has a low active ecosystem.
              It has 16 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 5 open issues and 0 have been closed. There are 7 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of abba is current.

            kandi-Quality Quality

              abba has 0 bugs and 0 code smells.

            kandi-Security Security

              abba has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              abba code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              abba is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              abba releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.
              abba saves you 237 person hours of effort in developing the same functionality from scratch.
              It has 579 lines of code, 0 functions and 13 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            abba Key Features

            No Key Features are available at this moment for abba.

            abba Examples and Code Snippets

            No Code Snippets are available at this moment for abba.

            Community Discussions

            QUESTION

            How do I iterate over a dictionary for a specific key, then ading it to a new dictionary
            Asked 2021-Jun-06 at 15:06

            I know this is a noob question but I'm a new learner to Python and I'm struggling with dictionaries.

            I think my code is right but I'm not sure.

            What I am trying to achieve is that I want to iterate over a dictionary with a list items with a dictionary in it. If the value is == None then that key Should be skipped. but if there is a value. I want to append the Key:Value pair to the pmp_dict = {}

            Here is my code:

            ...

            ANSWER

            Answered 2021-Apr-07 at 01:21

            There's 2 problems with the code you have:

            1.pmp_dict["operation"]["Details"]["ACCOUNTLIST"] isn't a dictionary, it's a list. Unless this was intentional, I would replace

            Source https://stackoverflow.com/questions/66964405

            QUESTION

            Question about Record Collection challange from FreeCodeCamp
            Asked 2021-Apr-27 at 14:41

            Why do I have to add square brackets to make this code work? (eg: records[id][prop] = [value]; at below) If I take square brackets away, it cannot fulfill the " After updateRecords(recordCollection, 5439, "tracks", "Take a Chance on Me") , tracks should have the string Take a Chance on Me as the last element." requirement.

            Why?

            ...

            ANSWER

            Answered 2021-Apr-27 at 14:41

            tracks props is an array, as defined for Bon Jovi & Prince:
            tracks: ["1999", "Little Red Corvette"]

            In this statement, you want to add a tracks to the artist:
            prop === "tracks".

            But the artist hasn't any tracks yet: records[id].hasOwnProperty(“tracks”) === false.

            So you need to init the tracks array before adding any values to it:
            records[id][prop] = [value];

            PS:
            You used records[id].hasOwnProperty("tracks") === false. But for Robert Palmer, the props tracks exists and isn't an array.
            You should use :
            (records[id].hasOwnProperty("tracks") === false || !Array.isArray(records[id]['tracks])).

            Source https://stackoverflow.com/questions/67283514

            QUESTION

            how to set, get a variable in java
            Asked 2021-Apr-27 at 09:29

            I have to implement this class and the 2 methods but dont know how. How do i set the variable and get it again? Heres my starting point:

            ...

            ANSWER

            Answered 2021-Apr-27 at 09:29
            1. You will need to have a class field, which will store the value that was set:

            Source https://stackoverflow.com/questions/67279008

            QUESTION

            .\create.sh: line 52: X: command not found
            Asked 2021-Mar-13 at 20:24

            I have this shell script but I don't know why it doesn't work after passing parameters to it...

            Here it is

            ...

            ANSWER

            Answered 2021-Mar-13 at 20:24

            In your script you are not calling your function create, so nothing is done.

            Also you are expanding "$@" at the end: this prints the shell arguments you passed trying to execute them. The error message comes from "Line 52" that is exactly where $@ is.

            In your command:

            Source https://stackoverflow.com/questions/66602183

            QUESTION

            Returns a list of all four-letter words that can be constructed using the first "n" letters of the uppercase alphabet
            Asked 2021-Feb-24 at 22:31

            I have a function called four_letter_list and the goal is to return a new list that has randomized 4-letter words that can be constructed using the "nth" letter of the alphabet

            You cannot use built in python functions besides len, range, for loops, while loops and if-elif-else statements.

            ex: def four_letter_words(2) returns the list ['AAAA', 'AAAB', 'AABA', 'AABB', 'ABAA', 'ABAB', 'ABBA', 'ABBB', 'BAAA', 'BAAB', 'BABA', 'BABB', 'BBAA', 'BBAB', 'BBBA', 'BBBB']

            This is the code I have

            ...

            ANSWER

            Answered 2021-Feb-24 at 21:43

            There is a python standard lib function: itertools.product that does this. Otherwise, just use a 4-layer for loop.

            Source https://stackoverflow.com/questions/66359199

            QUESTION

            How to Post object using presigned post with KMS(customer managed key)
            Asked 2021-Feb-23 at 11:31

            When i use presigned post to generate the url and other attributes, when i try to upload my image with server side encryption that is customer managed keys, this keys is created by me. In my case, I can upload with {"x-amz-server-side-encryption": "aws:kms"}. How can i upload customer managed key? If, i want to upload image with Customer managed key, am i using the x-amz-server-side​-encryption​-customer-key and x-amz-server-side​-encryption​-customer-key-MD5?

            here is my sample code:

            ...

            ANSWER

            Answered 2021-Feb-23 at 07:06

            Customer managed key, am i using the x-amz-server-side​-encryption​-customer-key and x-amz-server-side​-encryption​-customer-key-MD5?

            There is no such header as x-amz-server-side​-encryption​-customer-key for SSE-KMS (its for SSE-C, see below). Instead, if you are going to use "x-amz-server-side-encryption": "aws:kms" and what to use your own CMK (not AWS Managed CMK) then you have to use:

            • x-amz-server-side-encryption-aws-kms-key-id - to specify the ID of the customer managed CMK used to protect the data

            Header x-amz-server-side​-encryption​-customer-key-MD5 is for SSE-C (customer-provided keys), not for SSE-KMS.

            Source https://stackoverflow.com/questions/66328216

            QUESTION

            How to use a secondary alphabetical sort on a string list of names?
            Asked 2021-Feb-14 at 04:33

            I'm trying a way that when given a string of names which are first and last names, where names are split by ; and first name split to last name by : ->

            ...

            ANSWER

            Answered 2021-Jan-04 at 16:10

            If you are using Java stream you can use sorted like this:

            Source https://stackoverflow.com/questions/65565641

            QUESTION

            Fill R datatable upon condition with it's own value
            Asked 2021-Feb-02 at 02:23

            given this data table as an example:

            ...

            ANSWER

            Answered 2021-Feb-02 at 02:18

            Depending on whether you care about Zexpect being NA for the "OG" group, this should work for this dataset:

            Source https://stackoverflow.com/questions/66002739

            QUESTION

            emu 8086 divide error overflow in calculator
            Asked 2021-Jan-30 at 23:48

            I am writing a simple calculator in assembly but no matter what I do, I can't get the percentage part to start to work correctly and consistently getting this error:

            divide error - overflow.

            I almost worked a day and a half on it and it looks like it doesn't like to change anything.
            I tried every combination of multiplication and division and mix or separately and yet I can't make it work.

            ...

            ANSWER

            Answered 2021-Jan-30 at 23:48

            QUESTION

            Ruby - Permutations, lack of outputs
            Asked 2021-Jan-30 at 18:58
            def permutations(str)
              str.split(//).permutation.with_index.to_a.delete_if{|x,i| x[i].eql? x[i+1]}.flatten(1).to_a.delete_if{|x| x.class == Integer}.map{|x| x.join}
            end
            
            ...

            ANSWER

            Answered 2021-Jan-30 at 15:44
            def permutations(str)
              x = str.split(//).permutation.map(&:join).uniq
            end
            

            Source https://stackoverflow.com/questions/65968452

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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