lill | list structure in the JavaScript ecosystem | Dataset library
kandi X-RAY | lill Summary
kandi X-RAY | lill Summary
There are few implementation of the linked-list structure in the JavaScript ecosystem, but most of them create a bunch of extra objects to store metadata about the list. We didn't like that, so we created LiLL. The linked list data structure really shines in situations when you frequently need to iterate over a list of items, but only modify the list's structure infrequently. Linked lists are ordered simply by having each object in the list reference its previous and next siblings. Linked lists are much faster to iterate over than standard loops.
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Top functions reviewed by kandi - BETA
- remove an item from list
- Adds an item to the list and adds it to the list item
- find element matching predicate
- add object to owner
- Loops over a list element .
- iterate over elements
- Clear the contents of an item .
- returns true if object is attached to the provided object .
- Determine the value of a value .
- Sets whether the contents of a data element is attached .
lill Key Features
lill Examples and Code Snippets
Community Discussions
Trending Discussions on lill
QUESTION
I have a big dataset. It's about news reading. I'm trying to clean it. I created a checklist of cities that I want to keep (the set has all the cities). How can I drop the rows based on that checklist? For example, I have a checklist (as a list) that contains all the french cities. How can I drop other cities?
To picture the data frame (I have 1.5m rows btw):
...ANSWER
Answered 2022-Feb-24 at 10:48You can do this using pandas.Dataframe.isin. This will return boolean values checking whether each element is inside the list x. You can then use the boolean values and take out the subset of the df with rows that return True by doing df[df['City'].isin(x)]. Following is my solution:
QUESTION
So till now the only real difference that I knew about the difference in the append and += operation was that of speed but recently I stumbled upon a case in which += would throw an error while append would not can someone help out with what has been happening?
This code would not run and throw an error namely UnboundLocalError: local variable 'travel_log' referenced before assignment
...ANSWER
Answered 2022-Feb-23 at 08:01While using the operator '+', you should create the list
QUESTION
I want to find products and for each product attach deals to it. A deal is a product from same collection, yet based on some common properties.
So as per my requirement pipeline should return documents, for each document find other products those aren't same as current, but have equal detail.duration. But even though I've many docs with same duration, deals are always []. Could you please figure out the issue with my pipeline?
Following is the aggregation pipeline I'm running: I've added filter _id $in just for clarity based on shown documents below. This isn't a part of real pipeline $match query.
...ANSWER
Answered 2022-Feb-20 at 11:36The $match query syntax is identical to the read operation query syntax; i.e. $match does not accept raw aggregation expressions. To include aggregation expression in $match, use a $expr query expression.
And you need to use $$ to get the variable value.
To reference variables in pipeline stages, use the "$$" syntax.
Change the $match stage in the pipeline as:
QUESTION
I've suddenly started having a problem in RStudio when I've got file/folder names that contain unicode characters. I've been running the exact same code for months, but it stopped working this morning.
For example, when I run list.files() on a file path containing "Ø", it doesn't work. However, I can change my working directory to that folder and then run list.files():
ANSWER
Answered 2022-Jan-18 at 03:58R and RStudio are known to have unicode trouble on windows. Quoting a reply on this (similar but not identical) issue:
In general, the unfortunate truth right now for R on Windows is that you should restrict yourself to the characters representable in your native locale.
Your locale is shown to be English_United Kingdom.1252 and you're trying to use file names with characters outside it. There's a good chance changing your locale to match the file names would help.
I don't have a windows 10 machine to verify, but the internets say it'd done via Settings>Time & Language>Region & language.
QUESTION
I'm new to python and I don't have the right method for the for loop I have a list that looks like this
...ANSWER
Answered 2021-Dec-29 at 12:18f=False
final_list=[]
current=[]
l=['vendredi', '6', 'aoû.',
['Monaco'], '1', '-', '1', ['Nantes'],
'samedi', '7', 'aoû.',
['Lyon'], '1', '-', '1', ['Brest'],
['Troyes'], '1', '-', '2', ['Paris-SG'],
'dimanche', '8', 'aoû.',
['Rennes'], '1', '-', '1', ['Lens'],
['Saint-Étienne'], '1', '-', '1', ['Lorient'],
['Strasbourg'], '0', '-', '2', ['Angers'],
['Bordeaux'], '0', '-', '2', ['Clermont'],
['Nice'], '0', '-', '0', ['Reims'],
['Metz'], '3', '-', '3', ['Lille'],
['Montpellier'], '2', '-', '3', ['Marseille']]
for i in l:
if type(i) != list:
current.append(i)
else:
if f==False:
if len(current)!=0:
final_list.append(current)
current=i
f=True
else:
current.extend(i)
final_list.append(current)
current=[]
f=False
QUESTION
I have some text like the following:
...ANSWER
Answered 2021-Dec-21 at 10:12We can try using strsplit here as follows:
QUESTION
I have two tables :
Customer:
id name address_id 1 John 4 2 Kate 5 3 Bob 2 4 Michael 2 5 Adriana 3 6 Ann 1Address:
id detail_str_name city district street_name 1 France,Paris,str.2,N5 Paris Paris str.2 2 France,Parise,str.2 ,N3 Paris Paris str.2 3 France, Lille ,str.3,N4 Lille Lille str.3 4 France,Paris,str.4,N3 Paris Paris str.4 5 France, Paris, Batignolles,N4 Paris Batignolles BatignollesI want table like this:
name detail_str_name city district street_name sum(cu.num_cust) John France,Paris,str.4,N3 Paris Paris str.4 1 Kate France, Paris, Batignolles,N4 Paris Batignolles Batignolles 1 Bob France,Parise,str.2 ,N3 Paris Paris str.2 3 Michael France,Parise,str.2 ,N3 Paris Paris str.2 3 Adriana France, Lille ,str.3,N4 Lille Lille str.3 1 Ann France,Paris,str.2,N5 Paris Paris str.2 3I want to count customer group by city,district and street_name, not detail_str_name.
I try:
...ANSWER
Answered 2021-Dec-17 at 08:23I haven't been able to check this so it might not be totally correct but I think the query below should get the data you require.
This SQLTutorial article on the partition by clause might be useful.
QUESTION
I know I am relatively close to getting this but I can't seem to work out why when I add another bidder the list only contains the latest dictionary even though I am appending to that list. I also tried .copy() to no avail, what am I missing here?
...ANSWER
Answered 2021-Nov-30 at 00:01You initialize silent_dict to an empty list at the beginning of each loop iteration, which would erase the previous one the next time you enter a bid. You should run silent_dict = [] before you enter your while loop.
QUESTION
First Javascript code for a couple of years, I try to load the Google Maps Javascript API npm package to try to load a map and draw a direction between 2 points (Lille and Biarritz, passing by Paris and Bordeaux). I ended with an error from the Google API which code is UNKNOWN_ERROR and the message is
A directions request could not be processed due to a server error. The request may succeed if you try again.
Unfortunately, I've tried several times in the last 48h without success.
config.js
...ANSWER
Answered 2021-Sep-16 at 07:37Eventually, the problem was on the bundler side which was Parcel. I've built a SvelteKit version of this code and it works like a charm. As SwelteKit uses Rollup as a bundler (and Vite), I guess it's just the way to go at the time of writing.
QUESTION
Trying to access key value inside dictionary, inside, dictionary, inside dictionary. This should print: "In Paris, France you visited Resturaunt 1, 5 times." How can I fix this?
...ANSWER
Answered 2021-Aug-05 at 00:30Change the following in your code:
From:
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