sagittarius | A set of javascript most used utils | REST library

 by   Gherciu JavaScript Version: Current License: MIT

kandi X-RAY | sagittarius Summary

kandi X-RAY | sagittarius Summary

sagittarius is a JavaScript library typically used in Web Services, REST applications. sagittarius has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i sagittarius-to-number' or download it from GitHub, npm.

A set of javascript most used utils. Site | Getting Started | API | Blog.
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            kandi-support Support

              sagittarius has a low active ecosystem.
              It has 41 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 3 have been closed. On average issues are closed in 44 days. There are 21 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of sagittarius is current.

            kandi-Quality Quality

              sagittarius has 0 bugs and 0 code smells.

            kandi-Security Security

              sagittarius has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              sagittarius code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              sagittarius is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              sagittarius releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.
              sagittarius saves you 43 person hours of effort in developing the same functionality from scratch.
              It has 115 lines of code, 0 functions and 68 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of sagittarius
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            sagittarius Key Features

            No Key Features are available at this moment for sagittarius.

            sagittarius Examples and Code Snippets

            No Code Snippets are available at this moment for sagittarius.

            Community Discussions

            QUESTION

            How can I run my python code on google and give access to public or other users without using any money
            Asked 2021-Mar-18 at 05:45

            I have made a program using python language which tells your Horoscope. I made that on Jupyter-notebook, Anaconda. I opened it on word its code is: {

            ...

            ANSWER

            Answered 2021-Mar-18 at 05:38

            Colab is quite similar to jupyter notebook and is free to use. Just send the link to other once you add your code. https://colab.research.google.com/ is the link. A quick guide is: https://colab.research.google.com/github/jckantor/CBE30338/blob/master/docs/01.01-Getting-Started-with-Python-and-Jupyter-Notebooks.ipynb

            Source https://stackoverflow.com/questions/66685325

            QUESTION

            Is there other way of getting an input like date format?
            Asked 2021-Jan-21 at 17:11

            I was hoping and looking for some other ideas or ways to do this. As you can see, I asked the user for the input which is mmddyyyy (05022001 = May 2, 2001) and used substring in order for me to to take the certain input in the index then parse it. Now, What I want to accomplish is to find another way to do this for example is using the formal date formatter which in my case I didn't use. I think date formatter is alot better than this, but I don't get the idea out of it.

            Here's what I've got so far. Thanks in advance.

            ...

            ANSWER

            Answered 2021-Jan-21 at 17:11

            You should inform the user of what format you expect.

            Take the input string and make a parse attempt. Trap for exception in case of faulty input. No need for you to check the ranges of month and day. LocalDate.parse makes those data entry validation checks for you.

            Source https://stackoverflow.com/questions/65831738

            QUESTION

            IF condition is evaluated wrong for string comparison
            Asked 2020-Nov-09 at 07:52

            When you type the zodiac sign in the parameter, an example is "Leo" or "LEO", the output should appear as "This user is a LEO" but when I do it only shows me the word "INVALID".

            Can someone help me so that when I try to type a specific word it will appear as what the conditions states?

            This is my code:

            ...

            ANSWER

            Answered 2020-Nov-08 at 17:25

            Instead: if zodiac = 'Capricorn''CAPRICORN' You should have: if zodiac = 'Capricorn' or zodiac = 'CAPRICORN'

            Source https://stackoverflow.com/questions/64739555

            QUESTION

            Convert datetime into a zodiac name
            Asked 2020-Oct-11 at 21:32

            I have a date of someone's birth as "12/02/1980 00:00:00" but I want to convert it into a zodiac name. So I want 12/02/1980 to be displayed as Sagittarius. Is that possible to do?

            ...

            ANSWER

            Answered 2020-Oct-10 at 12:34

            Can do something like this

            Source https://stackoverflow.com/questions/64292953

            QUESTION

            How to print a quote based on the inputed Zodiac Sign with Python?
            Asked 2020-Aug-27 at 16:40

            I'm making a console personality test and I want to print a quote for the inputed zodiac sign of the player. I don't want to use tons of if statements, can I do this with dictionaries and loops?

            Where the keys are the zodiac signs and the values are the specific quotes, then using a loop and a short if statement to loop the keys with the given input and print the corresponding value which is the quote.

            Here's my code:

            ...

            ANSWER

            Answered 2020-Aug-27 at 16:35

            You could just get the zodiac sign from the dictionary with

            Source https://stackoverflow.com/questions/63620158

            QUESTION

            How to rename existing xticklabels using dictionary in histagram
            Asked 2020-Jul-22 at 09:37

            Encounter a problem, how to rename existing xticklabels in lineplot using dictionary ? Part of code:

            ...

            ANSWER

            Answered 2020-Jul-22 at 09:24

            I assume your data are in a dataframe like this df:

            Source https://stackoverflow.com/questions/63028733

            QUESTION

            How can I search any item in many list very efficiently?
            Asked 2020-May-17 at 22:38

            I have a problem to find very efficient way to search birthday in many list.

            Here is my horoscope_dates function

            ...

            ANSWER

            Answered 2020-May-17 at 22:38
            from datetime import date
            
            horoscope_dates = {"aries": (date(2020, 3, 21), date(2020, 4, 20)),
                               "taurus": (date(2020, 4, 20), date(2020, 5, 21)),
                               "gemini": (date(2020, 5, 21), date(2020, 6, 22)),
                               }
            
            month = int(input("Enter your month of birth: "))
            day = int(input("Enter your day of birth: "))
            year = 2020
            birthday = date(year, month, day)
            
            for horoscope, (start, end) in horoscope_dates.items():
                if start <= birthday < end:
                    print(horoscope)
                    break
            

            Source https://stackoverflow.com/questions/61859211

            QUESTION

            unfortunately,project has stopped in android studio
            Asked 2020-Apr-24 at 17:04

            The code is all about taking the zodiac sign as the input in the 1st activity and when clicked OK navigates to the next activity where it displays the details as the web view of that particular zodiac sign. When ever I try to run the code in the emulator or in my mobile I get a warning project is continuously stopping and the application closes.

            ...

            ANSWER

            Answered 2020-Apr-24 at 17:04

            You are calling startActivity twice, also .setClass is not needed:

            Source https://stackoverflow.com/questions/61362952

            QUESTION

            SQL Query To Select Zodiac Sign
            Asked 2020-Apr-12 at 02:23

            Plese tell me sql query to select zodiac sign by birth date.

            Here is the table structure.

            ...

            ANSWER

            Answered 2020-Apr-12 at 02:23

            Note that varchar(5) is not going to get you very far with most zodiac signs.

            You can use a join. Most databases have functions such as month() and day(), although they might be named a little differently.

            The idea is:

            Source https://stackoverflow.com/questions/61156817

            QUESTION

            Unexpected input value detection for dates in Zodiac calendar sample
            Asked 2020-Mar-26 at 12:43

            I'm doing a task in Python, which is to create a zodiac calendar judging by input month and day of the month.

            I've made a successful calendar, however, I have no idea how to solve the problem, if I input an incorrect month name or nonexistent date.

            I have tried tons of things: to create a different hierarchy, or under each zodiac sign I wrote else: print ('Entering an incorrect date'). I even tried to register with if day <0 and day> 31 or month! = 'March' or month! = 'April', etc... It turned out to be a huge useless function in the end, and nothing worked either.

            I feel that there is a one-line solution here to detect days < 0 and > 31 and incorrect month name, but I just can't understand it. Could somebody help, please?

            ...

            ANSWER

            Answered 2020-Mar-26 at 10:59

            You might want to look into the datetime module. With it, you can do comparisons between dates and times easily without the need for extraneous if statements.

            For example, if one were to do something like:

            Source https://stackoverflow.com/questions/60865396

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sagittarius

            You can install using 'npm i sagittarius-to-number' or download it from GitHub, npm.

            Support

            Fork it!Create your feature branch: git checkout -b my-new-featureCommit your changes: git commit -am 'Add some feature'Push to the branch: git push origin my-new-featureSubmit a pull request :D
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            https://github.com/Gherciu/sagittarius.git

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            gh repo clone Gherciu/sagittarius

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            git@github.com:Gherciu/sagittarius.git

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