harmonic | The next static site generator | Runtime Evironment library
kandi X-RAY | harmonic Summary
kandi X-RAY | harmonic Summary
Harmonic is being developed with some goals:. Check out the full Harmonic documentation.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of harmonic
harmonic Key Features
harmonic Examples and Code Snippets
Lines of Code : 28License : Permissive (MIT License)
Copydef harmonic_mean(series: list) -> float:
"""
return the harmonic mean of series
>>> harmonic_mean([1, 4, 4])
2.0
>>> harmonic_mean([3, 6, 9, 12])
5.759999999999999
>>> harmonic_mean(4)
T def harmonic_series(n_term: str) -> list:
"""Pure Python implementation of Harmonic Series algorithm
:param n_term: The last (nth) term of Harmonic Series
:return: The Harmonic Series starting from 1 to last (nth) term
Examples:
License : No LicenseCopydef harmonic(number: int) -> float:
"""Calculate the harmonic number of the given number.
Args:
number (int): input integer
Returns:
float: harmonic number
>>> harmonic(2)
1.5
>>> harmon namespace AudioKitCore
{
// WaveStack represents a series of progressively lower-resolution sampled versions of a
// waveform. Client code supplies the initial waveform, at a resolution of 1024 samples,
// equivalent to 43.6 HCommunity Discussions
Trending Discussions on harmonic
QUESTION
I have a data frame that looks like below. Wordsrefers to the number of words per email sent.
ANSWER
Answered 2021-May-25 at 18:31you can use groupby:
QUESTION
I am trying to plot the DC component of the Fourier Series together with the harmonics in the first panel. But the first panel only outputs the harmonics. Please help me in solving this one. Below is my code and output plot.
...ANSWER
Answered 2021-May-24 at 20:18The problem is the line
plot(xx,ao) %Plotting of DC component
Here xx is a vector and ao is a number. From the documentation, in this case the plot function plots discrete points; and these are not even visible because no marker has been specified.
To obtain a horizontal line of height ao, you need to replace the above by the following, so that both inputs to plot are vectors:
QUESTION
I'm writing a code that allows you to run 3 separate spring simulations where you can adjust the mass, spring constant and damping coefficient independently with input boxes. They all come out one after another like box box box box . . . box 9 times. how can I shift them to have them 3 by 3. 3 on the left, 3 in the middle and, 3 on the right? box box box box box box box box box
...ANSWER
Answered 2021-May-21 at 21:32Apply display:inline-block to the p tags that contain the inputs, then insert linebreaks when needed.
QUESTION
Contain the necessary files. Add this to your "My Drive". https://drive.google.com/drive/folders/1epROVNfvO10Ksy8CwJQdamSK96JZnWW9?usp=sharing Google colab link with a minimal example: https://colab.research.google.com/drive/18sMqNn8IpTQLZBlInWSbX0ITd2GWDDkz?usp=sharing
This basic block 'module', if you will, is part of a larger network. It all boils down to this block, however, as this is where the convolutions are performed (in this case depthwise separable convolution). The network is seemingly able to train, however, while training (and during all the epochs) a WARNING is thrown out:
...ANSWER
Answered 2021-May-15 at 17:12Solved by reworking the network and putting all the layers one after the other rather than having multiple instances of a model. So everything from beginning to end is in one single subclassed model.
QUESTION
For the 1D cosine transform the documentation is clear in here, and I can reproduce it easily:
The formula is:
and here it is reproduced manually, for example for the third harmonic:
...ANSWER
Answered 2021-May-05 at 19:00You can't find the formula for the multidimensional mode because the function doesn't do multidimensional cosine transforms. The axis keyword should be suspicious: in NumPy, SciPy it typically determines the direction along which lower-dimensional operations should be performed.
In other words, dct(z, axis=0) is just a columnwise 1d cosine transform:
QUESTION
I'm new at Digital signal processing. I have to do this exercise using Python:
Analysis of vocal traces with the STFT trying to identify the parts of the signal related to harmonic (vocalized) and non (consonant) sounds. In the case of non-harmonic sounds, you can try to estimate the AR model and then filter out some random noise with the same model. Listening should be able to recognize the original sound.
I'm having a hard time figuring out what to do! I don't really know where to start! I was wondering what the difference was between harmonic (vocalized) and non (consonant) sounds. what is an example of these two types? What topics do I need to know to do this exercise? Can anyone explain this exercise to me please?
...ANSWER
Answered 2021-May-03 at 10:48Check these pages
http://hyperphysics.phy-astr.gsu.edu/hbase/Music/vowel.html http://my.ilstu.edu/~jsawyer/consonantsvowels/consonantsvowels_print.html
In a very plain answer I would say that vowels have peaks in the spectrum, while the consonants are filtered continuous spectrum noise. This will be clearer for the unvoiced fricative consonants, like /f/, /s/. Not so much for the plosives (due to the relatively short duration).
QUESTION
In the code taken from: https://tutorials.sciml.ai/html/models/01-classical_physics.html as given below:
...ANSWER
Answered 2021-Apr-24 at 15:17I don't understand the usage of .= operator in the function harmonicoscillator. [...] It is not vectorizing ddu because RHS is all scalar.
It is; u, du, and ddu are not scalars, they are length-1 vectors.
You can ask Julia what the .= syntax means:
QUESTION
Can healpy compute the spherical harmonic transform of a complex-valued map?
When I try this using healpy.sphtfunc.map2alm, there is no warning, but the function gives a_{l,m} only for m>0. This makes sense for real-valued maps, for which a_{l,-m} = (-1)^m * a_{l,m}^*. But for complex-valued functions, this symmetry does not exist.
Thanks!
...ANSWER
Answered 2021-Apr-07 at 16:04Asked Martin Reinecke, developer of HEALPix C++, here his answer:
What you can do is to run map2alm separately on the real and imaginary
parts of your map; the resulting a_lm coefficients are then simply
a_lm,real + i*a_lm,imag. If you want the coefficients with negative m
as well, you need to use the symmetry relation separately on a_lm,real
and a_lm, imag first and then combine them as described.
The reason why there is no direct support for complex-valued maps is
that this would make a_lm handling and spherical harmonic transforms
much more complicated, just to cover a case that is rarely needed (at
least in the area where healpy was originally used) and that can be
emulated by the workaround above if really needed.
All a_lm objects in Healpix and healpy are designed in a way that there
is the mentioned symmetry between +m and -m. For quantities with spin!=0
this symmetry doesn't exist either, so we introduce the linear
combinations alm_E and alm_B, for which it exists again.
QUESTION
this is my website that I am developing, and I trying to develop a calculator which depending on the subject and equation your are trying to use, the calculator will give you an answer.
I made two dropdown menus, however, when I hover over the "Physics" menu, for some reason the "Maths" menu is covered. Also, the list for "Physics" is a bit too long and I wanted to make a scroll bar, but I don't know how to.
I tried to look on w3schools and other resources, but I couldn't find a solutions which solved my problem.
...ANSWER
Answered 2021-Apr-05 at 11:21You had a lot of errors in the code. Like in li, you gave css as display: inline;; and the sub-menu you didn't give any positions like position: absolute;
I have applied my changes below.
Thanks me later.
QUESTION
I'm trying to construct the position and momentum operators in order to calculate the Hamiltonian of a harmonic oscillator in MATLAB, but I am uncertain if they way I'm doing it is correct.
For the ladder operators I have this code:
...ANSWER
Answered 2021-Mar-28 at 10:15In Matlab, (ad*a + 1/2) means ad*a plus 1/2*ones(size(ad*a)), i.e., 1/2*ones(D+1,D+1). You probably wanted (ad*a + 1/2*eye(D+1)), adding the 1/2 only on the diagonal. Then the two forms will match (except for the final row/column where you cut off the matrix).
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install harmonic
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
