LZMA-JS | JavaScript implementation of the Lempel-Ziv-Markov | Compression library
kandi X-RAY | LZMA-JS Summary
kandi X-RAY | LZMA-JS Summary
LZMA-JS is a JavaScript implementation of the Lempel-Ziv-Markov (LZMA) chain compression algorithm.
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Top functions reviewed by kandi - BETA
- Gets the current position at the specified index .
- Code block .
- Retrieves the next match in this vector .
- Merge and minified files
- Decompress byte data .
- Code - code .
- Compress a string
- Compress files .
- Decompress files .
- Parse the buffer from the buffer
LZMA-JS Key Features
LZMA-JS Examples and Code Snippets
Community Discussions
Trending Discussions on LZMA-JS
QUESTION
I have an LZMA zip archive that I want to decompress using LZMA-JS, the issue is that the decompress method only accepts a byte array or node Buffer object and I do not know how to convert my zip file to a buffer object without loading the whole file to memory - so its best if it is some kind of read stream as the files I am trying to convert are huge.
It would be great if someone could suggest a way to create a byte array stream from zip file using Javascript - thank you so much! :)
...ANSWER
Answered 2019-Jun-14 at 10:31just an update for everyone who has the same issue. I ended up using 7zip-min (https://www.npmjs.com/package/7zip-min) to get around this issue. Hope that helps! :)
QUESTION
I have large json files on the server, which I compressed with xz
. I thought I'd be a good idea to request them as such, i.e. compressed, and decompress them in javascript on the client side. I'm trying to use the LZMA-JS library, but I haven't been able to get it to work.
Here's the relevant HTML snippet:
...ANSWER
Answered 2018-Aug-28 at 06:08You're mixing up formats.
XZ is an archive format. LZMA is the underlying stream compressor. LZMA-JS can only uncompress an LZMA stream, not an XZ archive.
Use the lzma
command-line tool to create a raw LZMA stream.
QUESTION
I am trying to compress a string using the LZMA-JS library found here. Here is my javascript:
...ANSWER
Answered 2017-Dec-26 at 01:18The documentation is perhaps confusing - the function's role, not name, is on_finish
, so use this instead to indicate you are creating an in-line function:
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