Push-It | JavaScript push server and client | Runtime Evironment library
kandi X-RAY | Push-It Summary
kandi X-RAY | Push-It Summary
Push-It gives you an API for realtime pub/sub in the browser. On the server, it gives you hooks for security and message routing. It is fast and cross-browser compatible.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Push-It
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Push-It Examples and Code Snippets
Community Discussions
Trending Discussions on Push-It
QUESTION
Recently (I cannot pinpoint the exact moment), Chrome started doing weird things to some of the divs on our site. Not all, just some. Which is awesome. (/sarcasm) Here's an example URL of where things are wacky: https://hightowerlowdown.org/article/we-have-a-moment-for-historic-progress-if-we-push-it/
But, some of the other divs have giant breaks in them.
Image: This is further down the page, and text is incorrectly wrapped.
I can't figure out why this is happening. If I change the css of the paragraphs to overflow: hidden, all wrapped text extends beyond the floated div, as expected.
Image: Example of css changed to overflow: hidden;
This is only happening in Chrome (tested on macOS Big Sur and Windows 10, v88 so far). Ideas? Halp?
...ANSWER
Answered 2021-Feb-19 at 16:29In your CSS file
https://hightowerlowdown.org/wp-content/themes/valenti-child/style.css?ver=1.0.0
at line 41:
QUESTION
Suppose I have three commits
A --> B' --> B
Commit B'
represents an intermediate state, where work is unfinished and tests aren't passing. I may have made commit B'
in order to switch from working on my home machine to my work machine.
Let's say I'm on a topic branch that no one is looking at but me. But all three commits are in the remote, otherwise I couldn't use B'
to pass changes from one machine to another.
If I do git rebase -i
(or if A
is the first commit, then git rebase i --root
), and I choose to fixup
or squash
commit B'
, then the changes in B'
will be folded into commit A
.
But this isn't appropriate. I want commits A
and B
to to represent reasonable checkpoints in the work, where changes aren't in a half-assed state that no one would understand but me. If I fixup
the B'
commit, then that will leave commit A
with the half-baked changes that B'
used to have. I want commit B'
to be folded into B
, since B'
represented intermediate work towards commit B
.
Possible solutions:
1a. Just leave commit B'
and name it "dummy commit" so no one pays attention to it. It's on my topic branch (even though it's pushed to remote), so who cares.
1b. If I think people might potentially look at my current topic branch and judge me for being unprofessional, give B'
its own branch that I'm sure no one cares about, then as soon as B
is ready, commit it and merge it back into the original branch, then delete the temporary branch. So it looks like
ANSWER
Answered 2020-Dec-22 at 21:54Use git rebase -i
to squash B
into B'
. Use the squash
instruction so that you get an opportunity to edit the commit message.
After the operation, others (and you) will only see a new commit B"
, and B
and B'
will soon be forgotten, and you do not have to worry that you "cheated" and folded B
into B'
instead of the other way round.
Of course, you will have to force-push the branch, but that does not matter, as you said, you are the only one looking at it. Under these circumstances, frequent force-pushing is not bad habit at all.
QUESTION
I am using Mongoose with Javascript (NodeJS) to read/write to MongoDB. I have a Document (Parent) that has a bunch of Subdocuments (Children) in it. Both my Document and Subdocuments have validation (required: true
and a function that validates that the user puts text in the field) defined in their Model.
When attempting to push a new Subdocument into the database, Mongoose rejects my push because validation fails on the Document. This has perplexed me as I am not trying to create a new Document with Subdocument, I am simply trying to push a new Subdocument into an existing Document.
Here is my (example) Mongoose Model:
...ANSWER
Answered 2020-Nov-26 at 08:11You can push the children into the parent using a mongo query because into the update
, the first object is to find the document where do the push.
The syntaxis is like: update({query},{update},{options})
. So you are looking for a document with firstName: 'Willard'
and adding the children into it.
Here everything is ok, all fields exists, the parent exists into collection so there is no problem.
But using
QUESTION
I am getting the following error while push/add items to an array in groovy.
$groovy main.groovy
Caught: groovy.lang.MissingMethodException: No signature of method: [LProgressNotes;.push() is applicable for argument types: (ProgressNotes) values: [ProgressNotes@d35dea7]
Possible solutions: sum(), plus(java.util.Collection), plus([Ljava.lang.Object;), plus(java.lang.Object), use([Ljava.lang.Object;), plus(java.lang.Iterable)
groovy.lang.MissingMethodException: No signature of method: [LProgressNotes;.push() is applicable for argument types: (ProgressNotes) values: [ProgressNotes@d35dea7]
Possible solutions: sum(), plus(java.util.Collection), plus([Ljava.lang.Object;), plus(java.lang.Object), use([Ljava.lang.Object;), plus(java.lang.Iterable)
at main$_buildOutNotes_closure2.doCall(main.groovy:82)
at main.buildOutNotes(main.groovy:75)
at main$buildOutNotes.callCurrent(Unknown Source)
at main.run(main.groovy:64)
Here is the function:
...ANSWER
Answered 2019-Dec-19 at 20:51You use an array in your code (ProgressNotes[]
), not a list (List
). Any of the mentioned methods (add
and push
) does not exist for Java (and thus Groovy) arrays. An array is fixed size, so once initialized, you can't add any new elements to it - you can only replace existing elements. If you try to add a new element to the array, you will get IndexOutOfBoundsException
. Just look at this simple example:
QUESTION
my professor doesn't explain much and just gives tasks to complete. I saw similar task here Push Item into Stack with C ,but I wish I could see full code, since I don't understand what top and node refers to.
...ANSWER
Answered 2019-Nov-15 at 13:11The function
QUESTION
Suppose I have a new club created by a user and this user has chosen many users as the members of the club.
so after creating the club I should find all the members and add club._id
to their clubs
field. like so
await User.updateMany({_id : {$in: newClub.members}}, {clubs: [...user.clubs, newClub._id]});
Notice! the
user.clubs
is an imaginary variable that I need.
I was wondering if there is a way I can push the new club to their existing clubs without looping over them and pushing club._id
to their clubs
field and saving them.
Thanks
...That's right that in this case I aim to use push on an existing document, but my question differs from Push items into mongo array via mongoose since I generally want to know how to access a field from an existing document when updating it.
ANSWER
Answered 2019-Oct-03 at 08:04You can use MongoDB aggregation pipeline to push the new value to the array
QUESTION
I want to update document with rather complex scheme.
I want to do it with atomic update (not modify it in memory, and then call the .save() ).
Push items into mongo array via mongoose - actually explains how to push items into array. But my case is more complex.
const eventSchema = new Schema( { name: { type: 'String' },
...ANSWER
Answered 2019-Jul-23 at 01:12So you want to add/remove items in your voters array, that is located in your sessions array. You would use the positional operator $ for the array (https://docs.mongodb.com/manual/reference/operator/update/positional/)
QUESTION
I've imported my Database from Firebase so I have few limitations in my schema. as My structure is like this
...ANSWER
Answered 2019-Jul-02 at 03:04 var uniqueId = new mongoose.mongo.ObjectId();
uniqueId = uniqueId.toString(); //Convert to string type
var key = 'pictures.' + uniqueId; // if key is constant we can directly add that.
User.findOneAndUpdate({'_id': userId}, {$set:{[key]: {'pictureName': pictureName, 'pictureNumber': pictureNumber}}}, {new: true}, (err, user) => {
// Try using $set instead of $push as $push works on arrays
});
QUESTION
I have created my POST request using AJAX, then checked my request URL /ajax/order-ratings/list in the web.php, and included this in the VerifyCsrfToken.php. In the controller part, my eloquent syntax seems to be correct, but when I checked the Google DevTools, it returned error 500, so the json response is Response {type: "basic", url: "https://quickenow.com/ajax/order-ratings/list", redirected: false, status: 500, ok: false, … My objective is to get the data from the request like order id, where do I get wrong in this ajax request?
order.blade.php
...ANSWER
Answered 2019-Mar-26 at 09:13Okay, for how many days until I discovered this variable $model doesn't exist, so returned a 500 error. I just removed this line: if($model === null){
return response()->json(['models' => $models, 'errors' => []]);
}
and it ran smoothly, so thanks for your advice @jens. Now, I continue creating the request to display individual order data. =)
QUESTION
I'm trying to flash the NXP i.MX7D with a simple custom image which has the default boot animation and a simple launcher. For whatever reason, after flashing, the default Android Things launcher is always launched and when I query for installed packages, my custom launcher is missing in the list.
My bundle:
...ANSWER
Answered 2018-Feb-13 at 21:57If bundle
is actually a top-level directory inside of your archive, then the problem is that the archive format is incorrect. The artifacts that you wrap up into the console bundle must be files at the top-level (not nested in subdirectories).
Here is an example of a command you could run to package the bundle archive properly for the single APK and boot animation.
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