declare | dojo.declare optimized for node.js useage | Reflection library

 by   agebrock JavaScript Version: 0.0.3 License: No License

kandi X-RAY | declare Summary

kandi X-RAY | declare Summary

declare is a JavaScript library typically used in Programming Style, Reflection applications. declare has no bugs, it has no vulnerabilities and it has low support. You can install using 'npm i declare' or download it from GitLab, GitHub, npm.

declare is a node.js optimized version of dojo 1.7’s dojo.declare This example shows how to create a namespace and create classes within. No global namespace is violated. declare includes the folloing modified dojo functions. for more information check the dojo docs (with dojo. prefix for sure). var createNamespace = require("../index");. var myCustomNamespace = { "doesNotMatter" : "anyValue" };. var oop = createNamespace(myCustomNamespace);. var MYClass = oop.declare("my.namespace.MYCLASS",[],{ property:"value", constructor:function(){ console.log("I AM ALIVE"); }, methodA:function(){ console.log("methodA called") console.log(this); }, methodB:function(){ console.log("methodB called") } });. oop.declare("MYSubClass",[myCustomNamespace.my.namespace.MYCLASS],{ constructor:function(){ oop.mixin(this,{methodC:function(){ console.log("same mixin like known from dojo @" , this.declaredClass); }}); }, methodA:function(){ console.log("method A from " + this.declaredClass); } }). /* this will end up with the same result…​ / var instance = new MYClass(); / The namespace can be accessed with the object we used to create the "oop" instance. You could create more factories each with a different namespace */ var i2 = new myCustomNamespace.my.namespace.MYCLASS();. var subi = new myCustomNamespace.MYSubClass(); subi.methodA(); subi.methodB(); subi.methodC();.
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            kandi-support Support

              declare has a low active ecosystem.
              It has 2 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              declare has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of declare is 0.0.3

            kandi-Quality Quality

              declare has 0 bugs and 0 code smells.

            kandi-Security Security

              declare has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              declare code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              declare does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              declare releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.

            Top functions reviewed by kandi - BETA

            kandi has reviewed declare and discovered the below as its top functions. This is intended to give you an instant insight into declare implemented functionality, and help decide if they suit your requirements.
            • Declare class .
            • find the current class .
            • Recursively build a list of class names .
            • Chain constructor .
            • Make a constructor
            • Make a new constructor
            • Create a function that creates a class prototype chains .
            • Mixin functions .
            • Class instanceof .
            • Apply a new instance to a constructor .
            Get all kandi verified functions for this library.

            declare Key Features

            No Key Features are available at this moment for declare.

            declare Examples and Code Snippets

            No Code Snippets are available at this moment for declare.

            Community Discussions

            QUESTION

            ESLint: 8.0.0 Failed to load plugin '@typescript-eslint'
            Asked 2022-Mar-31 at 09:08

            Could you help me, I've got this error when I try building a project?

            Oops! Something went wrong! :(

            ESLint: 8.0.0

            TypeError: Failed to load plugin '@typescript-eslint' declared in 'src.eslintrc': Class extends value undefined is not a constructor or null Referenced from: src.eslintrc

            package.json

            ...

            ANSWER

            Answered 2021-Oct-10 at 10:33

            QUESTION

            Why is std::is_copy_constructible_v> true?
            Asked 2022-Mar-26 at 23:21

            In my version of clang and libc++ (near HEAD), this static_assert passes:

            ...

            ANSWER

            Answered 2022-Mar-26 at 23:21

            std::vector and other containers (except std::array) are specified to have a copy constructor. This is not specified to be conditional on whether or not the element type is copyable. Only instantiation of the copy constructor's definition is forbidden if the element type is not copyable.

            As a result std::is_copy_constructible_v on the container will always be true. There is no way to test whether an instantiation of a definition would be well-formed with a type trait.

            It would be possible to specify that the copy constructor is not declared or excluded from overload resolution if the element type is not copyable. However, that would come with a trade-off which is explained in detail in this blog post: https://quuxplusone.github.io/blog/2020/02/05/vector-is-copyable-except-when-its-not/.

            In short, if we want to be able to use the container with an incomplete type, e.g. recursively like

            Source https://stackoverflow.com/questions/71632098

            QUESTION

            Action requested: Declare your Ad ID permission
            Asked 2022-Mar-15 at 13:37

            Today i have got this email:

            Last July, we announced Advertising policy changes to help bolster security and privacy. We added new restrictions on identifiers used by apps that target children. When users choose to delete their advertising ID in order to opt out of personalization advertising, developers will receive a string of zeros instead of the identifier if they attempt to access the identifier. This behavior will extend to phones, tablets, and Android TV starting April 1, 2022. We also announced that you need to declare an AD_ID permission when you update your app targeting API level to 31 (Android 12). Today, we are sharing that we will give developers more time to ease the transition. We will require this permission declaration when your apps are able to target Android 13 instead of starting with Android 12.

            Action Items If you use an advertising ID, you must declare the AD_ID Permission when your app targets Android 13 or above. Apps that don’t declare the permission will get a string of zeros. Note: You’ll be able to target Android 13 later this year. If your app uses an SDK that has declared the Ad ID permission, it will acquire the permission declaration through manifest merge. If your app’s target audience includes children, you must not transmit Android Advertising ID (AAID) from children or users of unknown age.

            My app is not using the Advertising ID. Should i declare the AD_ID Permission in Manifest or not?

            ...

            ANSWER

            Answered 2022-Mar-14 at 20:51

            QUESTION

            What are sealed classes in Java 17
            Asked 2022-Feb-16 at 15:31

            Today I updated my java version from 16 to 17 and I found that sealed class is a new feature in it. I think it can be declared like this -

            ...

            ANSWER

            Answered 2021-Sep-17 at 15:04

            You can follow this link for examples.

            In short sealed classes gives you the control of which models, classes etc. that can implement or extend that class/interface.

            Example from the link:

            Source https://stackoverflow.com/questions/69218585

            QUESTION

            "Invalid use of non-static data member" when initializing static member from global variable
            Asked 2022-Feb-07 at 22:01
            class A {
                int x;
                static int i;
            };
            
            
            int x = 10;
            int A::i = x;
            
            ...

            ANSWER

            Answered 2022-Feb-07 at 10:07

            This is a peculiar language quirk - the scope resolution on the left, in int A::i, affects the lookup scope on the right, so that actually refers to the x member of A.

            Either rename one of the variables, or specify the scope of the desired x explicitly:

            Source https://stackoverflow.com/questions/71016630

            QUESTION

            Clarification on difference in ODR rules for structs in C and C++
            Asked 2021-Nov-02 at 13:15

            I am aware of how ODR, linkage, static, and extern "C" work with functions. But I am not sure about visibility of types since they cannot be declared static and there are no anonymous namespaces in C.

            In particular, I would like to know the validity of the following code if compiled as C and C++

            ...

            ANSWER

            Answered 2021-Oct-20 at 09:43

            For C. The program is valid. The only requirement that applies here is "strict aliasing rule" saying that the object can be accessed only via a l-value of a compatible type (+ a few exception described in 6.5p7).

            The compatibility of structures/unions defined in separate translation units is defined in 6.2.7p1.

            ... two structure, union, or enumerated types declared in separate translation units are compatible if their tags and members satisfy the following requirements: If one is declared with a tag, the other shall be declared with the same tag. If both are completed anywhere within their respective translation units, then the following additional requirements apply: there shall be a one-to-one correspondence between their members such that each pair of corresponding members are declared with compatible types; if one member of the pair is declared with an alignment specifier, the other is declared with an equivalent alignment specifier; and if one member of the pair is declared with a name, the other is declared with the same name. For two structures, corresponding members shall be declared in the same order. For two structures or unions, corresponding bit-fields shall have the same widths. For two enumerations, corresponding members shall have the same values.

            Therefore the structures are not compatible in the example.

            However, it is not an issue because the f object is created and accessed via locally defined type. UB would be invoked if the object was created with Foo type defined in one translation unit and accessed via other Foo type in the other translation unit:

            Source https://stackoverflow.com/questions/69642941

            QUESTION

            Function default argument value depending on argument name in C++
            Asked 2021-Oct-06 at 22:12

            If one defines a new variable in C++, then the name of the variable can be used in the initialization expression, for example:

            ...

            ANSWER

            Answered 2021-Oct-06 at 22:12

            According to the C++17 standard (11.3.6 Default arguments)

            9 A default argument is evaluated each time the function is called with no argument for the corresponding parameter. A parameter shall not appear as a potentially-evaluated expression in a default argument. Parameters of a function declared before a default argument are in scope and can hide namespace and class member name

            It provides the following example:

            Source https://stackoverflow.com/questions/69461415

            QUESTION

            Is it allowed to name a global variable `read` or `malloc` in C++?
            Asked 2021-Oct-04 at 09:43

            Consider the following C++17 code:

            ...

            ANSWER

            Answered 2021-Oct-03 at 12:09

            The code shown is valid (all C++ Standard versions, I believe). The similar restrictions are all listed in [reserved.names]. Since read is not declared in the C++ standard library, nor in the C standard library, nor in older versions of the standard libraries, and is not otherwise listed there, it's fair game as a name in the global namespace.

            So is it an implementation defect that it won't link with -static? (Not a "compiler bug" - the compiler piece of the toolchain is fine, and there's nothing forbidding a warning on valid code.) It does at least work with default settings (though because of how the GNU linker doesn't mind duplicated symbols in an unused object of a dynamic library), and one could argue that's all that's needed for Standard compliance.

            We also have at [intro.compliance]/8

            A conforming implementation may have extensions (including additional library functions), provided they do not alter the behavior of any well-formed program. Implementations are required to diagnose programs that use such extensions that are ill-formed according to this International Standard. Having done so, however, they can compile and execute such programs.

            We can consider POSIX functions such an extension. This is intentionally vague on when or how such extensions are enabled. The g++ driver of the GCC toolset links a number of libraries by default, and we can consider that as adding not only the availability of non-standard #include headers but also adding additional translation units to the program. In theory, different arguments to the g++ driver might make it work without the underlying link step using libc.so. But good luck - one could argue it's a problem that there's no simple way to link only names from the C++ and C standard libraries without including other unreserved names.

            (Does not altering a well-formed program even mean that an implementation extension can't use non-reserved names for the additional libraries? I hope not, but I could see a strict reading implying that.)

            So I haven't claimed a definitive answer to the question, but the practical situation is unlikely to change, and a Standard Defect Report would in my opinion be more nit-picking than a useful clarification.

            Source https://stackoverflow.com/questions/69424363

            QUESTION

            What does `0+ptr` (0 plus a pointer) mean?
            Asked 2021-Sep-20 at 22:49

            I found the following macro in the source code of Perl:

            ...

            ANSWER

            Answered 2021-Sep-03 at 09:35

            I guess it is used to make it an R-value, what makes it read-only in practice.

            Example: One can write

            Source https://stackoverflow.com/questions/69040993

            QUESTION

            Why does std::initializer_list in ctor not behave as expected?
            Asked 2021-Aug-30 at 14:11
            #include 
            
            int main()
            {
                auto v = std::vector{std::vector{}};
                return v.front().empty(); // error
            }
            
            ...

            ANSWER

            Answered 2021-Aug-30 at 07:46

            auto v = std::vector{std::vector{}}; actually creates a std::vector because it uses std::vector copy constructor. It is interpreted by the compiler as:

            Source https://stackoverflow.com/questions/68980250

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install declare

            You can install using 'npm i declare' or download it from GitLab, GitHub, npm.

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