airports | Analysis of domestic flights for Data Day Austin | Data Visualization library
kandi X-RAY | airports Summary
kandi X-RAY | airports Summary
Analysis of domestic flights for Data Day Austin 2011
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of airports
airports Key Features
airports Examples and Code Snippets
Lines of Code : 3License : Permissive (MIT License)
Copyfunction TrafficTower() {
this.airplanes = [];
} Community Discussions
Trending Discussions on airports
QUESTION
i am working on a map app with some overlays (annotations, circles, polygons). And i also have UISwitches to appear/disappear them. For the annotation is easy: .add / .remove, it works.
...ANSWER
Answered 2021-Jun-15 at 19:49You can use MKMapView.removeOverlays call to do this.
QUESTION
I looked up iterative Graph DFS and it showed using a stack for the edges but this is producing a different order vs recursive DFS. I tried using a queue for the iterative DFS as well but the only way I could get the same order as recursive DFS was using a stack of Map iterators come back to and resume the iteration over edges, but I feel like there is probably a better way to do it.
I've included each DFS method, recursive, iterative stack, iterative queue, and iterative Map iterators with the order of each being logged:
...ANSWER
Answered 2021-May-30 at 23:12Your stack of map iterators has the same result order as the recursive version because it accurately represents the state of the for loop in the recursive function.
To contrast your simple stack version, look at the order in which edges are processed after all of them have been pushed onto to the stack: the next iteration takes the top one, which was pushed last; then the second-to-last and so on, essentially processing the edges in reverse order.
If you want to reproduce the same result as the recursive version, you have to stack the neighbors of each node in reverse. Also you'll want to skip processing them again if they have been visited in the meantime (i.e. if they had been put on the stack multiple times).
QUESTION
Rvest output is inserting a long string of extra data in one of the cells:
...ANSWER
Answered 2021-May-28 at 08:07You can use
QUESTION
"Find Word Count"- Instructions: Given an input string (assume it's essentially a paragraph of text) and a word to find, return the number of times in the input string that the word is found. Should be case agnostic and remove space, commas, full stops, quotes, tabs etc while finding the matching word.
=======================
My code doesn't work properly.
...ANSWER
Answered 2021-May-25 at 17:41In your code you are not checking complete word. So, its matching both 'be' and 'because'. You're checking if there are any sub-strings contains the word 'be'. Could you please try below solution using regex? It will solve your purpose:
QUESTION
The broken method: hasPathDFSBroken
Working version: hasPathDFS
The working version has a contrived param added to make it work which I'd rather avoid.
I'm trying to understand why in the broken version when the call stack starts unwinding at LIM as currNode and it gets back to MEX as the currentNode, why does it not resume the unfinished for loop over MEX's neighbors?
Any help would be greatly appreciated. Thanks!
...ANSWER
Answered 2021-May-24 at 23:17why doesn't the unfinished for loop resume over MEX's neighbors?
Because the return statement you have inside the loop immediately breaks from the loop and the function.
Instead, you need to look at the return value and continue with the loop if the recursive call hasn't found the destination:
QUESTION
ANSWER
Answered 2021-May-16 at 06:46Replace this line of code -->
annexure2page1_df2 = annexure2page1_df1[['एयिपोर्च\rAIRPORT','वायुयाि प्रर्ालि (संख्या में)\rAIRCRAFT MOVEMENTS (IN NOS.)','Unnamed: 4','Unnamed: 8','Unnamed: 10']]
with --> annexure2page1_df2 = annexure2page1_df1.iloc[:,[3,5,7,11,13]]
The error that you got ( KeyError: "['वायुयाि प्रर्ालि (संख्या में)\\rAIRCRAFT MOVEMENTS (IN NOS.)', 'एयिपोर्च\\rAIRPORT'] not in index") is becuase of keys not found.
So , I have bypassed it by directly providing the index location of the columns that you want to subset. Check out the screenshot
QUESTION
I am working with airports dataset from nycflights13 package. I want to find the word with longest length from the second column i.e. name
I tried 2 ways
using strsplit + boundary frunction from stringr on airports$name but somehow now able to get this done effectively.
use word function but it only takes first word from the name
...
ANSWER
Answered 2021-May-11 at 17:48Here's an approach with purrr::map. First, split the name column by space. Then apply a custom function to the list that is created. We can use [ to subset the vector in each list element to be the longest word. We can determine the longest word by applying nchar to each element. which.max can tell us which one is longest.
The _char version of map will return a character vector.
QUESTION
I'm trying to test out the parent/child relationship but havent throuble getting any results back for has_child queries. I have this mapping
...ANSWER
Answered 2021-Apr-23 at 18:04When you are indexing the child document, the name for the field for the join data type is written wrong. It should be "join_field" and not "join_filed"
Update your child document as shown below
QUESTION
I have a SQLite database with a list of all airports in the world with their respective data (code, country, name, etc). I'm trying to create a method where an ATC will login with their airport's code. The program will then check if the airport code exists, and return true so the ATC can login and will be able to see all the information of their airport. If it doesn't exist, it returns false and doesn't let the ATC login.
I'm trying to see if a specific "item" exists in the database, not a row or column.
By looking online this is the "closest" I've gotten, but I'm getting an error and can't figure out how else to do it right now.
...ANSWER
Answered 2021-Apr-21 at 02:30First, the raw SQL query you want would look something like this:
QUESTION
I got an email today about upcoming changes to the Flight Inspiration and Flight Destination searches. It sounds as if the JSON response will now be more granular with results showing specific airports. But I am unclear about whether I have to change my POST requests to use airport codes. Will requests continue to be city codes, or now only airport code requests, or are both acceptable? Again, from the linked blog post, it sounds as if only the response is changing, but API POST requests will remain the same, i.e., city codes. Can someone confirm that?
...ANSWER
Answered 2021-Apr-19 at 08:49At this new version, the Flight Inspiration Search and Flight Cheapest Date APIs will still accept city code as input but will return airport codes at the destination field rather than city codes. Thus you won't have to change anything in the query parameter of the APIs.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install airports
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
