gnirts | Obfuscate string literals in JavaScript code | Security library
kandi X-RAY | gnirts Summary
kandi X-RAY | gnirts Summary
Obfuscate string literals in JavaScript code. gnirts mangles string literals more than hexadecimal escape like "\x66\x6f\x6f". String literals that were escaped by the hexadecimal escape can be found out too easily, and those can be decoded too easily. Those stand out in the code. Stealers can get secret text (e.g. password) easily by pasting that on a console (e.g. Developer Tools of web browser). gnirts mangles string literals by using some codes instead of hexadecimal escape. gnirts might not be able to protect the string from stealers perfectly, but it forces a troublesome work upon them. (See Note.).
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QUESTION
Lua has a piece of syntactic sugar that allows for OOP methods to be implemented: the operator :
when used as foo:bar(biz)
is equivalent to foo.bar(foo,biz)
. However, what I've noticed is that it is also actively used by the standard string library in this manner:
ANSWER
Answered 2021-Apr-09 at 22:56Every string in Lua (5.1 - 5.4) has a metatable with metamethod __index.
Thats the place where all string functions are present.
Here is a function that shows it...
QUESTION
s = "Some string"
for i in s.split():
print(i)
word += i[::-1]
word += " "
...ANSWER
Answered 2021-Jan-28 at 20:22What I usually do is put an if
statement comparing the iterable's length to the iteration number. Like this:
QUESTION
I'm having an issue creating a function that both reverses the input string AND preserves any extra spaces in it. For example:
...ANSWER
Answered 2020-Aug-20 at 00:49You'll want to split on space, then map each entry to the string-reversed version of itself before joining the new array back together
QUESTION
I don't understand where I went wrong
Write a function that takes in a string of one or more words, and returns the same string, but with all five or more letter words reversed (Just like the name of this Kata). Strings passed in will consist of only letters and spaces. Spaces will be included only when more than one word is present.
Examples:
...ANSWER
Answered 2020-Jun-15 at 14:49Try this,
QUESTION
I want to print a string in reverse and build it by printing letter by letter.
E.g - Word is: string
Ideal output is:
...ANSWER
Answered 2020-Feb-25 at 04:14s='string'
r=''
for char in reversed(s):
r+=char
print(r)
QUESTION
I need to remove all the numbers from the string recursively and then return the reversed string.
...ANSWER
Answered 2019-Nov-08 at 11:37For Removing number try below approach:
1. using join and isdigit
QUESTION
I'm trying to figure out from an array of strings how to compare strings based on characters. So for example there's the following:
...ANSWER
Answered 2019-May-17 at 18:48input = [4, "string", "gnirts", "strign", "ta", "atc"]
input.
drop(1).
group_by { |str| str.chars.sort.join }.
values.
map(&:first)
# => ["string", "ta", "atc"]
QUESTION
I wrote this function to reverse a string in Python but it doesn't work, I just get the output: "gnirts tupni"
Any idea where I'm going wrong?
...ANSWER
Answered 2019-Feb-11 at 04:41You should use the variable input_string
instead of the literal input string
:
QUESTION
I'm looking to reverse a set of strings while keeping them in the same positions and also trying not to use slicing or reverse(). So if I had:
...ANSWER
Answered 2019-Feb-07 at 00:22Guess you want:
QUESTION
let word = "String to be reverse"
var reversed = ""
for char in word.characters {
reversed.insert(char, at: reversed.startIndex)
}
print(reversed)
...ANSWER
Answered 2018-Jul-17 at 02:51You can use enumerateSubstrings in range using options .byWords
, get all substrings range and replace them with the substring of the same range reversed:
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