tacky | Server-side response caching for hapi | Caching library
kandi X-RAY | tacky Summary
kandi X-RAY | tacky Summary
Server-side response caching plugin for hapi. tacky adds a new handler named cache that can be used on any route that is a GET method. tacky will try to serve a value from the server cache first if present. If the value is not in the server cache, it will call hydrate(), reply with the result and then cache the value in the server cache for subsequent requests. tacky stores values in a hapi server cache provision. It does not just set the response cache headers.
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QUESTION
I have a list of tweets (tokenized and preprocessed). It's like this:
...ANSWER
Answered 2022-Feb-25 at 21:51For single words you would need only set() (without defaultdict)
QUESTION
So I'm using cURLlib in C++ so that I can get market data using API's, problem is I'm not able to make head or tails from the documentation given about cURLlib for C++. The API returns a JSON file which I want to parse and take data from to use on my own algorithm. The only solution I see right now is to parse the string that's returned by cURL, but I think that seems too lenghty and tacky, so if there's someway I can get a direct output as a JSON file from cURL instead I could use nlohmann and iterate through it that way.
(I have changed the API key provided and replaced it with "demo" in the code)
this is my code so far
...ANSWER
Answered 2022-Jan-02 at 19:11The only solution I see right now is to parse the string that's returned by cURL
That is exactly what you need to do.
but I think that seems too lenghty and tacky, so if there's someway I can get a direct output as a JSON file from cURL instead
There is no option for that in libcurl.
I could use nlohmann and iterate through it that way
You already know how to get the JSON from libcurl as a string. The nlohmann parser can parse a JSON string via the json::parse() method, eg:
QUESTION
I am currently making a TicTacToe game that uses a Minimax algorithm for Player vs Computer. As of right now, the code only has Hard mode on PvE. It is a working bot that you cant win against using Minimax algorithm. However, I need to find a way to incorporate a special rule...
Each player is only allowed to have 3 'tacs' on the board at a time. Once they reach 3, they have to move a tac from one spot to another. I am not entirely sure how to implement this, could someone give me some ideas?
...ANSWER
Answered 2021-Dec-10 at 22:47You will need to isolate components of gameplay into reusable functions that can be combined to simulate moves for the minimax calculations.
Because you need simulations, it is a good idea to have a self contained data structure that represents the sate of the game (board) including who's turn it is to play (i'm using a 10 character string where the first character is the current player and the other 9 are the current state of the board).
The first thing you'll need to implement is a function to simulate a move (returning a new game state):
QUESTION
#include
#include
#include "Header1.h"
using namespace std;
static const char * const wordDataBase[] = {"test","eee","office","minor","town","wrap","treatment","determined","blue","acrid","itchy","organic","impartial","frame","parallel","inconclusive","agreeable","stiff","obsequious","lonely","extra","large","crash","grease","tacky","bashful","cheap","island","outgoing","open","quick","general","big","related","rich","stain","cable","many","attract","star","governor","receive","four","best","tap","match","dapper","married","invent","coordinated","\0"};
string c;
//
char guess;
int wordPick;
bool crct = 0;
bool inct = 0;
int fails = 0;
//
int main() {
cout << "Pick a number between 1 & 50: ";
cin >> wordPick;
string pickedWord = wordDataBase[wordPick - 1];
int wordLength = pickedWord.length();
char* pch;
char str[] = " ";
for (string::size_type l = 0; l < 6; ++l) {
string::value_type c = pickedWord[l];
cin >> guess;
crct = 0;
inct = 0;
if (guess == c) {
crct = 1;
}
else if (guess != c) {
inct = 1;
fails + 1;
}
if (crct == 1) {
second();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << endl << "You guessed a correct letter!" << endl << "Guess again! ";
for (int i = 0; i < pickedWord.length(); ++i) {
str[i] = pickedWord[i];
}
pch = (char*)memchr(str, guess, strlen(str));
if (pch != NULL)
printf("%d.\n", pch - str + 1);
else
printf("guess not found.\n");
}
else if (inct == 1 && fails <= 6) {
third();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << endl << "You guessed an incorrect letter!" << endl << "Guess again! ";
}
else if (fails == 6) {
third();
for (int guessLength = 0; guessLength < wordLength; guessLength++) {
cout << "_ ";
} cout << endl;
cout << "Sadly, you've lost." << endl;
}
}
return 0;
};
ANSWER
Answered 2021-Mar-16 at 15:56Here is a possible solution. I used std::strings because they're just simpler. I hold the actual word, and the player's progress in two strings. It's simply a matter of going through the solution with the guess, character-by-character.
QUESTION
TL;DR - I need to target and open a single menu from a bunch that are created by map()'ing an array, without a reference.
I have a problem with my React.js code that I can't quite get my head around and could do with another set of eyes, please.
The basic premise of this logic is for a user to be able to pick tasks that need carrying out in rooms of a building. The building can be from a number of sectors and as such can have a number of different rooms, each with their own tasks. In short, it needs to be dynamic.
This is simplified overview of my data structure:
- There are a number of Sectors
- Each Sector has multiple RoomGroups
- Each RoomGroup has multiple Rooms
- Each Room has multiple Tasks
- Each RoomGroup has multiple Rooms
- Each Sector has multiple RoomGroups
When a user clicks a Property type, it has a sector associated with it.
Upon selection, the RoomGroups are rendered by passing the roomGroup array in to a map().
This is a basic example of the code used for this (minus the CSS for clarity)...
...ANSWER
Answered 2021-Feb-04 at 16:49You need to show the menu only for the correct room. Try this:
QUESTION
Apologies in advance for any tacky code (I'm still learning Swift and SwiftUI).
I have a project where I'd like to have multiple timers in an Array count down to zero, one at a time. When the user clicks start, the first timer in the Array counts down and finishes, and a completion handler is called which shifts the array to the left with removeFirst() and starts the next timer (now the first timer in the list) and does this until all timers are done.
I also have a custom Shape called DissolvingCircle, which like Apple's native iOS countdown timer, erases itself as the timer counts down, and stops dissolving when the user clicks pause.
The problem I'm running into is that the animation only works for the first timer in the list. After it dissolves, it does not come back when the second timer starts. Well, not exactly at least: if I click pause while the second timer is running, the appropriate shape is drawn. Then when I click start again, the second timer animation shows up appropriately until that timer ends.
I'm suspecting the issue has to do with the state check I'm making. The animation only starts if timer.status == .running. In that moment when the first timer ends, its status gets set to .stopped, then it falls off during the shift, and then the new timer starts and is set to .running, so my ContentView doesn't appear to see any change in state, even though there is a new timer running. I tried researching some basic principles of Shape animations in SwiftUI and tried re-thinking how my timer's status is being set to get the desired behavior, but I can't come up with a working solution.
How can I best restart the animation for the next timer in my list?
Here is my problematic code below:
MyTimer Class - each individual timer. I set the timer status here, as well as call the completion handler passed as a closure when the timer is finished.
...ANSWER
Answered 2021-Jan-28 at 23:16I may have found one appropriate answer, similar to one of the answers in How can I get data from ObservedObject with onReceive in SwiftUI? describing the use of .onReceive(_:perform:) with an ObservableObject.
Instead of presenting the timer's status in a conditional to the ContentView, e.g. if timer?.status == .running and then executing the timer animation function during .onAppear, instead I passed the timer's status to .onReceive like this:
QUESTION
I have an array $description[0] that contains the following:
ANSWER
Answered 2021-Jan-18 at 22:50I would make an array of the option descriptors and their relevant images; then you can just iterate over the array to output all the required images for the given description:
QUESTION
This image gets stacked side by side in a single row. I'd like to force it into stay in a row, whether that's changing image size to perhaps a scroll(I think this will look tacky), or another suggestion.
The example shows 11 images and 2 rows of 11 images. The images spill to an unwanted 2nd row if it fills the space. I don't want this. I want it to stay in one row no matter the window size or amount of images (3-40+) per row. I know bootstrap grid works on 12 columns... but I'm not sure how to make this work when I need a dynamic amount of columns per row.
I've provided images examples. How do I do this?
UPDATE: The 1st answer fixed the row with many images, but introduced spacing that I need to be eliminated when there are few images. I made padding and margin 0 but it's still spacing them evenly instead of right next to each other on the left like I'd like.
...ANSWER
Answered 2020-Dec-31 at 05:23Call d-inline bootstrap class and set a max-width on picture div. For example, I have given
.col{ max-width: 100px; }
Code below-
QUESTION
I am using Spacy library matcher to extract negative sentences in French which contains specific pattern. The key word is a connector "mais" but the negation can be at the beguinning or ending of the sentences. My problem is that , I do not know in advance the numbers of words which seperate the negative pattern from the connector. Is there a way in spacy to tell him that they can be 0 to infinite words which can seperate the negative pattern from the connector ?
exemple :
...ANSWER
Answered 2020-Nov-10 at 13:41You will need to replace 5 lines of
QUESTION
I've been trying to create a way to tell my (running) macOS app to open some files and supply some additional arguments to the command.
For cold-start apps, using the
...ANSWER
Answered 2020-Jun-29 at 12:56A command-line tool which ingests its arguments and turns them in to Apple Events is the way to go. You can see how this works from the user's point of view by installing the BBEdit command-line tools and then running man bbedit or man bbdiff in a Terminal window.
From your command-line tool's point of view, the "interesting" parts are:
Figure out whether the application is running:
+[NSRunningApplication runningApplicationsWithBundleIdentifier:]will help with that.If the application is not running, then use
-[NSWorkspaceURLForApplicationWithBundleIdentifier:]to first locate the application by bundle ID, then-[NSWorkspace launchApplicationAtURL:options:configuration:error:]to launch the application. This will return anNSRunningApplicationinstance, or NIL and an error. (Make sure to handle the error case.)Using the
NSRunningApplicationinstance obtained from either step 1 or step 2, you can now use either theNSAppleEventDescriptorAPIs or the low-level AppleEvent C APIs to construct an event. (The higher-level API is probably easier to use.)
That would go something like this:
Construct a target descriptor using the
processIdentifierfrom your running application:
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