weigh | command line tool to check the bundle size | Build Tool library
kandi X-RAY | weigh Summary
kandi X-RAY | weigh Summary
A command line tool to check the bundle size of one or more browser compatible npm modules.
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QUESTION
There are multiple ways to pass values to an SSIS package. We could use variables, Package parameters, or Project parameters also we could save values in a table and ask SSIS to pick the values from the table. Now, my way of coding is to use project Parameters and get the variables to use them. When deployed to the SSIS catalog, ENV can be set up to overwrite Param values as user requirements. Now, Am weighing the risks/ease of setting up ENV by the user to pass param values vs setting up a table to save values and code in SSIS to pick the values. Pls, pour in your thoughts on the pros and cons of both these approaches.
For eg: let's assume we have an SSIS package to save data to a CSV file. And Folder path where CSV files must be saved varies depending on servers(DEV/UA/Prod). Is it best to save folder path value in a table along with server name or is it best to set folder Path value as Param and ask the user who executes to set up the folder value in ENV at the time of execution depending on the server?
Update on 23 Mar 2022 - Based on all valuable inputs, I decided to use parameters and variables rather than using SQL table to pick values.
...ANSWER
Answered 2022-Mar-03 at 17:07In my experience variables are best served by using an Execute SQL task and returning the results to a variable. It's modular and means it certain steps can easily be disabled if need be.
For managing connections (without outright hard-coding a connection string) I'd advise saving the CSV file location via a parameter. A parameter can be modified in the deployment environment via your SQL Script Agent and doesn't require changes to the source table. If I can avoid it, I wouldn't ever put file location information in the source table as it makes the table less exportable.
QUESTION
I would like to retrieve a random collection of items paginated with a particular weight on the created_at.
I successfully retrieved a random collection paginated with postgres option setseed.
The thing is, how do I combine some sort of weighing on created_at in my collection (which will give a better chance for the weighed items to be in the random sample) and this setseed option with postgres.
I'm thinking of something like retrieving the items, add them the weight I want and then do my random request but I think it will not be good performance-wise.
I'm in a kind of a dead end there and I don't know how to approach this issue.
Here is what I did for now :
Simply using setseed option to have a different batch of random items on each of my pages :
ANSWER
Answered 2022-Feb-23 at 15:11I would suggest to convert your created_at to a a float. Here is an example
QUESTION
Imagine you have a data set in three dimensions, x, y and z, and you want to show their relation. You could do this for example using a scatter plot in x and y and adding information about z with the help of a colormap:
But such a plot can be hard to read or even missleading, so I would like to use a 2d-histogram in x and y instead and weigh each data point by their z value:
However, as can be seen by the plot above, the magnitude of bin values can now be much higher than the maximum in z, which makes sense of course, as the bin values are usually the sums several z values.
So weighing by their z value is not enough, I also need to "normalize" each bin value by the number of data points within it. But as can be seen on the right plot above, for some reason, this doesn't seem to work. The color value range remains unchanged.
What am I doing wrong and is there a better approach to do this?
Code for reproduction (loosely based on this example):
...ANSWER
Answered 2022-Feb-23 at 10:35Implementing the solution from this very similar post, I managed to make it work, however I'm still not sure why my original approach didn't work.
QUESTION
I'm working on an application with Angular 12, which allows users to store a heavy files, like images, and videos. (There are videos that could be larger than 1GB). Anyway, they are very heavy files.
In this application, it's necessary to place a button "Download everything as ZIP" the problem is that the way I currently have to handle this download is with JSZip and it makes my computer very slow, also it does not report the progress until the file is armed zip, that is, it spends 20 minutes at 0% download and even later it begins to report the progress.
This is the solution that I am currently implementing:
...ANSWER
Answered 2021-Oct-30 at 09:11You can use OneZip instead of JSZip.
OneZip provides some listeners that you can use to improve your UI/UX.
QUESTION
This problem is similar to the classic coin search for a single counterfeit coin that weighs lighter than x number of coins but with a twist in the number of coins that could possibly be fake. The real coins all weigh the same, and the fake coins weigh the same. The fake coins weigh less than the real coins.
The difference in the one I am trying to solve is for when there are at most 2 counterfeits, (i.e There can be possibly, No fake coins, 1 fake coin, or 2 fake coins).
Example of my attempt: My attempt at an earlier part of this problem was figuring out how to find the fake coins if any, when x = 9 # of coins, however you were only allowed to use the weight scale at most 6 times to figure it out.
I started by separating x = 9 coins into groups of 3 and comparing the groups to check for equality (if all groups are = there are no fake coins, since there could be at most 2 fake coins and at least 0 fake coins.) Then going from there to checking inequalities for group 1 with group 2 and group 1 again with group 3. With the possibilities of there being 2 fake coins in group 1,2, or 3, and the other possibility of there being 1 fake coin each in 2 groups such as group 1,2, 1,3 or 2,3. Considering these cases I followed the comparisons, thereby breaking down the comparing of groups into thirds until I get to the final few coins and find the fake coins.
The problem is:
In a pile of coins where x amount of coins is ">= 3", how would I go about finding the fake coins while making sure the number of times weighed is O(log base 2 of (n)). And How would I find a generic formula to find the number of weighings required to find at most 2 fakes from an x amount of coins.
Programming this is easy when I can consider all cases and compare each one at a slower speed. However it gets significantly more difficult when considering the amount of times weighed has to be O(log base 2 (n)). I have considered using the number of coins to differentiate how the comparisons will be made such as checking if x amount of coins is an odd or even number of coins, then deciding how to compare. If odd, divide x-1 into 3 groups and put the last coin into a fourth group, then continue down the spiral of comparisons to finally find the fake coins, if there are any at all. I also considered dividing say 100 coins into 33 each and comparing the 3 groups, then getting rid of 1/3 of the coins and running comparisons on the 66 left. I still can't wrap my head around solving how to design a generic algorithm procedure to find the fake coins, and then how to even find a generic formula for comparing the amount of times weighed to log base 2 (n).
Even when n = prime/odd numbers it is difficult to split those coins and check for weight in a general procedure that works with any number n >= 3.
To clarify, I need help with figuring out if/how my earlier attempt/example can be applied to create a general comparison algorithm that will apply to any number of coins where x>=3, while the amount of times weighed is O(log base 2 (n)).
...ANSWER
Answered 2022-Feb-05 at 01:04Since O(log_2 n) is the same as O(log_b n) for any base b>1, the recursive breakdown into thirds suggested by user @n.1.8e9 in the comments fits that requirement. There's no need to consider prime/odd numbers, as long as we can solve for some specified constant number of coins with a constant number of weighings.
Here, let 3 coins be our base case. After weighing all 3 pairings (technically, we can get away with 2 weighings), we will know exactly which of the 3 coins are light, if any. So if we split a pile of 11 coins into thirds of 3 each, we can take the 2 leftover coins, borrow any other coin from the other piles, perform the 3 weighings, and then discard the 2 leftover coins since we know their status. As long as there are O(log n) splitting stages, dealing with the leftovers won't affect the asymptotics.
The only complex part of the proof is that after the first step, we go from the '0, 1 or 2 fakes' problem to either two 'exactly 1 fake' subproblems or a '1 or 2 fakes' subproblem. Assuming you know the solution to the original 'exactly 1 fake' problem with 1 + log_3 n weighings, the proof should look fairly similar.
The procedure for 'at most 2 fake' and '1 or 2 fakes' is the same. Given n coins, we divide them into three groups of floor(n/3) coins (and treat any leftovers as we did above). If n <= 3, stop and just perform all weighings. Otherwise, given piles A, B and C, perform the 3 pair weighings (A, B), (A, C) and (B, C).
If they all weigh the same (A=B=C), there are no fake coins.
If one pile is different, there are two cases: the single pile is lighter or heavier than the other two.
If it is lighter (say, A < B, A < C, and B = C), then pile A has exactly 1 or 2 fake coins and we have a single problem instance on n/3 coins (discard piles B and C).
If the outlier is heavier (say, A = B, A < C, and B < C), then piles A and B have exactly one fake coin each, which is the standard counterfeit problem.
To prove the bound on number of weighings, you probably need to use induction. Each recursion level requires at most 6 weighings, so an upper bound formula for the number of weighings required when there may be up to 2 fake coins remaining is T(n) = max(T(n/3), 2 * (1 + log_3(n/3))) + 6, where the 1 + log_3 (n/3) term is the standard upper bound with perfect strategy to find one light coin among n/3 coins (where we take the floor of all divisions to get integers).
QUESTION
This is my first mini project (I'm intermediate c++ programmer)
I wanted to practice using if statements because I wanted to find the extent of the command, and what I could use it for.
However, throughout my program, I constantly became very annoyed that I'm having to write all this code, to perform a simple task.
The basics of the code is that the user inputs their birth month, and the program outputs their astrology related sign and meaning. My question is, Is there a way, that I could perform the same task, but in less code? Is there a command I could use, or something?
------extra-------------------------------------
In my cs1 class, we recently learned about switch cases. I was thinking that I could use switch cases to fix 1 problem I had, accuracy
Improving the accuracy of the users b-day. Instead of using tons of if statements which can only look for a specific month (or with even more if's month and day) I could use a case that said "1. January 1-20th" However, now this just makes me want to be more accurate about the month. ***Could I possible use more if statements or perhaps something in the case that basically says if the user says <20 then they are Aquarius?
Is there also a different way I could do the program other than switch cases?
...ANSWER
Answered 2022-Jan-31 at 15:56Here's how I would set this up.
I would use a std::map to map from month names to the output you want to associate with it.
std::map::find will perform a lookup and return an iterator for a key-value pair of month and associated output, or an end iterator if it is not found.
A std::optional is a nice way of either having a value or not and it a little less heavy-handed than throwing an exception.
And finally, make good use of functions to describe your program in understandable pieces.
QUESTION
class test1;
function test_randcase();
for (int idx=0; idx < 10; idx++) begin
randcase
50: begin
$display("displaying from first cases");
end
50: begin
$display("displaying from second case");
end
endcase
end
endfunction
endclass
program main;
initial begin
test1 t1=new();
t1.test_randcase();
end
endprogram
ANSWER
Answered 2022-Jan-27 at 18:19Looking at this problem another way, suppose you had to choose a completely random 10-bit number where each bit has a 50% chance of being 0 or 1. There are 1024 possible numbers with a 1/1024 chance of having 10 1's and a 1/1024 chance of having 10 0's. And the odds of choosing a number with exactly 5 1's and 5 0's is around 25%. If you run more iterations, your randcase distribution would approach 0.50, but the odds of getting an exact 0.5 distribution diminish.
If your requirement is getting an exact distribution, you need to know upfront how many iterations you plan to have. There are several approaches you could take, one of which I can show you
QUESTION
I want to remove url's from a column in a data-frame. The column I am interested in is called comment, and example entry in comment is:
...ANSWER
Answered 2022-Jan-25 at 08:42You can try to perform a substitution using a regular expression, use re.sub.
For example:
QUESTION
I'm doing an exercise of which statement is below:
You are responsible for a rail convoy of goods consisting of several boxcars. You start the train and after a few minutes you realize that some boxcars are overloaded and weigh too heavily on the rails while others are dangerously light. So you decide to stop the train and spread the weight more evenly so that all the boxcars have exactly the same weight (without changing the total weight). For that you write a program which helps you in the distribution of the weight.
Your program should first read the number of cars to be weighed (integer) followed by the weights of the cars (doubles). Then your program should calculate and display how much weight to add or subtract from each car such that every car has the same weight. The total weight of all of the cars should not change. These additions and subtractions of weights should be displayed with one decimal place.
You may assume that there are no more than 50 boxcars.
Example 1 In this example, there are 5 boxcars with different weights summing to 110.0. The ouput shows that we are modifying all the boxcars so that they each carry a weight of 22.0 (which makes a total of 110.0 for the entire train). So we remove 18.0 for the first boxcar, we add 10.0 for the second, we add 2.0 for the third, etc.
Input 5 40.0 12.0 20.0 5.0 33.0
Output -18.0 10.0 2.0 17.0 -11.0
For that I have done so far:
...ANSWER
Answered 2021-Dec-28 at 05:34Go with for loops to subtract it with your array.
QUESTION
In my Symfony project, I created a controller and a function to retrieve the content of an APi.json from a site.
I am using HttpClient to grab the content and embed it into a new file in the project.
However when I call this function, I have an error writing the new file:
Http2StreamException> Http2StreamException> TransportException
Body size limit exceeded
this error comes from this piece of code :
...ANSWER
Answered 2021-Nov-27 at 01:42So the limit you are facing comes from the $bodySizeLimit property of the Request class, which has a default value from a const there.
But you can "unlock" it, as this example in the repo itself tries to explain
so basically, you might adjust your code like this:
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