c3 | : bar_chart : A D3-based reusable chart library | Chart library
kandi X-RAY | c3 Summary
kandi X-RAY | c3 Summary
c3 is a D3-based reusable chart library that enables deeper integration of charts into web applications. Follow the link for more information:
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Top functions reviewed by kandi - BETA
- tick axis
- Update position values
- Computes a 4 - by - 1 log scale scale .
- Main entry point .
- creates an array of logspace
- this is a helper function
- The internal Axis class
- Private constructor .
- Create a new Chart
- Verify a new zoom
c3 Key Features
c3 Examples and Code Snippets
k = 0 -> 1 = 1
k = 1 -> 2 * 1 + 1 = 3
k = 2 -> 2 * 3 + 2 = 8
k = 3 -> 2 * 8 + 3 = 19
// unexpanded initial call
let c3 = (fun res -> res)
CPSfunc 4 3 c3
// expanded once, k = 3
let c2 = (
create or replace function metadata.fn_get_id(a1 text, b2 text, c3 text default null)
RETURNS integer language plpgsql as
$$
declare
-- your declarations
begin
if nullif(c3, '') is null then
return null;
end if;
-- your
SELECT c1, c2, MIN(CAST(c3 AS INT)) AS c3
FROM YourTable
GROUP BY c1, c2
HAVING COUNT(DISTINCT c3) = 1 AND MIN(CAST(c3 AS INT)) = 0
LATIN SMALL LETTER D (U+0064)
LATIN SMALL LETTER E WITH ACUTE (U+00E9)
LATIN SMALL LETTER F (U+0066)
LATIN SMALL LETTER I (U+0069)
LATIN SMALL LETTER N (U+006E)
LATIN SMALL LETTER I (U+0069)
LATIN SMALL LETTER R (U+0072)
//@version=5
indicator(title='CT Indi', shorttitle='', overlay=true)
myTickerClose = request.security(syminfo.tickerid, "15", close)
sm = input(21, title='Smoothing Period')
cd = input(0.4, title='Constant D')
di = (sm - 1.0) / 2.0 + 1
CASE breakdown by parameter
WHEN "C1" THEN C1
WHEN "C2" THEN CAST(C2 AS TEXT)
WHEN "C3" THEN C3
WHEN "C4" THEN C4
WHEN "C5" THEN C5
END
for(int i = 0; i < rank.length; i++){
for (int j = 0; j < suit.length; j++){
System.out.println(suit[j] + rank[i]);
}
}
CA
DA
SA
HA
C2
D2
S2
H2
C3
D3
S3
H3
C4
D4
S4
H4
C5
D5
S5
H
0000000000401070 :
401070: eb .byte 0xeb # jmp rel8 consuming the 01 add opcode as a rel8
0000000000401071 :
401071: 01 d0 add eax,edx
# loop entry point on first iteration, ju
public class Complex {
private final double re;
private final double im;
public Complex(double re, double im) {
this.re = re;
this.im = im;
}
// getters and other methods
public Complex add(Comple
row_mask = (df.to_numpy() == l[:, None, None]).sum(axis=0).any(axis=1)
filtered = df[row_mask]
>>> filtered
col1 col2 col3 col4
0 x1 y1 z1 a1
1 x2 y2 z2 b2
2 x3 y3 z3 c3
Community Discussions
Trending Discussions on c3
QUESTION
I looked for solutions here: Multiply columns in a data frame by a vector and here: What is the right way to multiply data frame by vector?, but it doesn't really work.
What I want to do is a more or less clean tidyverse way where I multiply columns by a vector and then add these as new columns to the existing data frame. Taking teh data example from the first link:
...ANSWER
Answered 2022-Mar-31 at 22:15If it is by row, then one option is c_across
QUESTION
Goal: I have a ball in a triangle. The ball has an initial position and velocity. I'm trying to figure out which side of the triangle the ball will hit.
What I've Tried: I derived a formula that outputs which side the ball will hit, by parametrizing the ball's path and the triangle's sides, and finding the minimum time that satisfies the parametric equations. But when I implement this formula into my program, it produces the wrong results! I've tried many things, to no avail. Any help is greatly appreciated. The MWE is here: CodePen
...ANSWER
Answered 2022-Feb-20 at 08:05I couldn't figure out your math. I think you should try annotating this kind of code with explanatory comments. Often that will help you spot your own mistake:
QUESTION
How to list all the files that were "touched" somewhere between two commits? I am looking for a command similar to git diff COMMIT1..COMMIT2 --name-only
but including the files that were modified and reverted later.
For example, let's say I have a repository with a series of commits (linear history): C0<-C1<-C2<-C3<-C4. The commit C1 introduced a new file F and then the commit C3 removed it from the repository. I am looking for a command that, given C0 and C4, would tell me that somewhere in between there was a file F. Even though there is no such file in C0 and in C4. Therefore git diff
wouldn't mention file F at all.
ANSWER
Answered 2022-Mar-25 at 08:24git diff ref1 ref2
takes into account only given commits, yes, but git log
will find the missing steps and list files for each one, which sort
will aggregate :
QUESTION
Short version: I need is to get a results column r
like this, ideally using dplyr (but happy for base R as well):
ANSWER
Answered 2022-Mar-09 at 22:51Suboptimal:
QUESTION
I have a dataframe like this:
...ANSWER
Answered 2022-Feb-10 at 23:31You can use a named groupby
:
QUESTION
I have df1
:
ANSWER
Answered 2022-Jan-30 at 21:02If the values are "NULL"
, then we can select
the columns of interest, convert to long format with pivot_longer
and filter
out the "NULL"
elements
QUESTION
Given a df
with the following column,
ANSWER
Answered 2022-Jan-06 at 08:16Lets try filter
QUESTION
I think it is very easy and simple question. but it is very difficult for me. please help! I can write R code
...ANSWER
Answered 2022-Jan-06 at 07:52Shortest way out would be to find what of b is not in a and then append it to a.
QUESTION
I am trying to call C functions inside python and discovered the ctypes library (I'm fairly new to both C and python's ctypes), motive (however stupid) is to make python code's speed on par with c++ or close enough on a competitive website. I have written the C code and made a shared library with the following command cc -fPIC -shared -o lib.so test.c
and imported it into python with ctypes using the following code:
ANSWER
Answered 2022-Jan-04 at 05:31from ctypes import *
# int add(int x, int y)
# {
# return (x+y);
# }
code = b'\x55\x48\x89\xe5\x89\x7d\xfc\x89\x75\xf8\x8b\x55\xfc\x8b\x45' \
b'\xf8\x01\xd0\x5d\xc3'
copy = create_string_buffer(code)
address = addressof(copy)
aligned = address & ~0xfff
size = 0x2000
prototype = CFUNCTYPE(c_int, c_int, c_int)
add = prototype(address)
pythonapi.mprotect(c_void_p(aligned), size, 7)
print(add(20, 30))
QUESTION
C1 & C2 are the multi index. I'm hoping to get a result which gives me only values in C1 which have values both lower than 10 and greater than or equal to 10 in C2.
So in the table above C1 - B should go, with the final result should look like this:
C1 C2 C3 C4 A 12 True 89 9 False 77 5 True 23 C 11 True 10 8 False 08 12 False 09I tried df.loc[(df.C2 < 10 ) & (df.C2 >= 10)] but this didn't work.
I also tried:
filter1 = df.index.get_level_values('C2') < 10 filter2 = df.index.get_level_values('C2') >= 10
df.iloc[filter1 & filter2]
Which I saw suggested on another post that also didn't work. Any one know how to solve this? Thanks
...ANSWER
Answered 2021-Dec-14 at 11:55Use GroupBy.transform
with GroupBy.any
for test at least one condition match per groups, so possible last filter by m
DataFrame:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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