c3 | : bar_chart : A D3-based reusable chart library | Chart library

 by   c3js JavaScript Version: 0.7.20 License: MIT

kandi X-RAY | c3 Summary

kandi X-RAY | c3 Summary

c3 is a JavaScript library typically used in User Interface, Chart, D3 applications. c3 has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can install using 'npm i c3-labworks' or download it from GitHub, npm.

c3 is a D3-based reusable chart library that enables deeper integration of charts into web applications. Follow the link for more information:
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            kandi-support Support

              c3 has a medium active ecosystem.
              It has 9269 star(s) with 1441 fork(s). There are 278 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 726 open issues and 1515 have been closed. On average issues are closed in 582 days. There are 54 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of c3 is 0.7.20

            kandi-Quality Quality

              c3 has 0 bugs and 0 code smells.

            kandi-Security Security

              c3 has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              c3 code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              c3 is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              c3 releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.
              c3 saves you 6164 person hours of effort in developing the same functionality from scratch.
              It has 12846 lines of code, 4 functions and 418 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed c3 and discovered the below as its top functions. This is intended to give you an instant insight into c3 implemented functionality, and help decide if they suit your requirements.
            • tick axis
            • Update position values
            • Computes a 4 - by - 1 log scale scale .
            • Main entry point .
            • creates an array of logspace
            • this is a helper function
            • The internal Axis class
            • Private constructor .
            • Create a new Chart
            • Verify a new zoom
            Get all kandi verified functions for this library.

            c3 Key Features

            No Key Features are available at this moment for c3.

            c3 Examples and Code Snippets

            F# CPS evaluation order
            Lines of Code : 29dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            k = 0 ->     1     =  1
            k = 1 -> 2 * 1 + 1 =  3
            k = 2 -> 2 * 3 + 2 =  8
            k = 3 -> 2 * 8 + 3 = 19
            
            // unexpanded initial call
            let c3 = (fun res -> res)
            CPSfunc 4 3 c3
            
            // expanded once, k = 3
            let c2 = (
            Handle empty value '' on function numeric variable
            Lines of Code : 15dot img2License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            create or replace function metadata.fn_get_id(a1 text, b2 text, c3 text default null)
            RETURNS integer language plpgsql as
            $$
            declare 
             -- your declarations
            begin
                if nullif(c3, '') is null then
                    return null;
                end if;
             -- your 
            Exclude rows if a column has different values for a combination of other columns
            Lines of Code : 5dot img3License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            SELECT c1, c2, MIN(CAST(c3 AS INT)) AS c3
            FROM YourTable
            GROUP BY c1, c2
            HAVING COUNT(DISTINCT c3) = 1 AND MIN(CAST(c3 AS INT)) = 0
            
            Cannot remove remote branch which name contains diacritics
            Lines of Code : 18dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            LATIN SMALL LETTER D (U+0064)
            LATIN SMALL LETTER E WITH ACUTE (U+00E9)
            LATIN SMALL LETTER F (U+0066)
            LATIN SMALL LETTER I (U+0069)
            LATIN SMALL LETTER N (U+006E)
            LATIN SMALL LETTER I (U+0069)
            LATIN SMALL LETTER R (U+0072)
            
            Pinescript security function for colour boolean with mutable variable
            Lines of Code : 36dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            //@version=5
            
            indicator(title='CT Indi', shorttitle='', overlay=true)
            
            myTickerClose = request.security(syminfo.tickerid, "15", close)
            
            sm = input(21, title='Smoothing Period')
            cd = input(0.4, title='Constant D')
            
            di = (sm - 1.0) / 2.0 + 1
            Dynamic Breakdown Dimension with Mixed Data Type (Text and Number)
            Lines of Code : 8dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            CASE breakdown by parameter
              WHEN "C1" THEN C1
              WHEN "C2" THEN CAST(C2 AS TEXT)
              WHEN "C3" THEN C3
              WHEN "C4" THEN C4
              WHEN "C5" THEN C5
            END
            
            Java: Questions about using nested loops to create a deck of cards
            Javadot img7Lines of Code : 66dot img7License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
              for(int i = 0; i < rank.length; i++){    
                 for (int j = 0; j < suit.length; j++){
                     System.out.println(suit[j] + rank[i]);
                   }
               }
            
            CA
            DA
            SA
            HA
            C2
            D2
            S2
            H2
            C3
            D3
            S3
            H3
            C4
            D4
            S4
            H4
            C5
            D5
            S5
            H
            copy iconCopy
            0000000000401070 :
              401070:       eb                      .byte 0xeb      # jmp rel8 consuming the 01 add opcode as a rel8
            0000000000401071 :
              401071:       01 d0                   add    eax,edx
            # loop entry point on first iteration, ju
            How do I make a method like int.getRed() in java?
            Javadot img9Lines of Code : 27dot img9License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            public class Complex {
                private final double re;
                private final double im;
            
                public Complex(double re, double im) {
                    this.re = re;
                    this.im = im;
                }
            
                // getters and other methods
            
                public Complex add(Comple
            Iterating over all columns of dataframe to find list of strings
            Lines of Code : 9dot img10License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            row_mask = (df.to_numpy() == l[:, None, None]).sum(axis=0).any(axis=1)
            filtered = df[row_mask]
            
            >>> filtered
              col1 col2 col3 col4
            0   x1   y1   z1   a1
            1   x2   y2   z2   b2
            2   x3   y3   z3   c3
            

            Community Discussions

            QUESTION

            tidyverse solution for multiplying columns by a vector
            Asked 2022-Apr-01 at 09:28

            I looked for solutions here: Multiply columns in a data frame by a vector and here: What is the right way to multiply data frame by vector?, but it doesn't really work.

            What I want to do is a more or less clean tidyverse way where I multiply columns by a vector and then add these as new columns to the existing data frame. Taking teh data example from the first link:

            ...

            ANSWER

            Answered 2022-Mar-31 at 22:15

            If it is by row, then one option is c_across

            Source https://stackoverflow.com/questions/71699503

            QUESTION

            Ball-Triangle Collision
            Asked 2022-Mar-26 at 11:39

            Goal: I have a ball in a triangle. The ball has an initial position and velocity. I'm trying to figure out which side of the triangle the ball will hit.

            What I've Tried: I derived a formula that outputs which side the ball will hit, by parametrizing the ball's path and the triangle's sides, and finding the minimum time that satisfies the parametric equations. But when I implement this formula into my program, it produces the wrong results! I've tried many things, to no avail. Any help is greatly appreciated. The MWE is here: CodePen

            ...

            ANSWER

            Answered 2022-Feb-20 at 08:05

            I couldn't figure out your math. I think you should try annotating this kind of code with explanatory comments. Often that will help you spot your own mistake:

            Source https://stackoverflow.com/questions/71186472

            QUESTION

            List all files touched by commits in git
            Asked 2022-Mar-25 at 08:24

            How to list all the files that were "touched" somewhere between two commits? I am looking for a command similar to git diff COMMIT1..COMMIT2 --name-only but including the files that were modified and reverted later.

            For example, let's say I have a repository with a series of commits (linear history): C0<-C1<-C2<-C3<-C4. The commit C1 introduced a new file F and then the commit C3 removed it from the repository. I am looking for a command that, given C0 and C4, would tell me that somewhere in between there was a file F. Even though there is no such file in C0 and in C4. Therefore git diff wouldn't mention file F at all.

            ...

            ANSWER

            Answered 2022-Mar-25 at 08:24

            git diff ref1 ref2 takes into account only given commits, yes, but git log will find the missing steps and list files for each one, which sort will aggregate :

            Source https://stackoverflow.com/questions/70392361

            QUESTION

            Another "how to deal with NAs in logical statements" question
            Asked 2022-Mar-10 at 20:29

            Short version: I need is to get a results column r like this, ideally using dplyr (but happy for base R as well):

            ...

            ANSWER

            Answered 2022-Mar-09 at 22:51

            QUESTION

            Pandas groupby and count numbers of item by conditions
            Asked 2022-Feb-10 at 23:31

            I have a dataframe like this:

            ...

            ANSWER

            Answered 2022-Feb-10 at 23:31

            QUESTION

            How to create a single column from multiple?
            Asked 2022-Jan-30 at 22:10

            I have df1:

            ...

            ANSWER

            Answered 2022-Jan-30 at 21:02

            If the values are "NULL", then we can select the columns of interest, convert to long format with pivot_longer and filter out the "NULL" elements

            Source https://stackoverflow.com/questions/70918854

            QUESTION

            How to select a set of multiindex column based on top index
            Asked 2022-Jan-06 at 08:16

            Given a df with the following column,

            ...

            ANSWER

            Answered 2022-Jan-06 at 08:16

            QUESTION

            change value by key of another dataframe
            Asked 2022-Jan-06 at 07:52

            I think it is very easy and simple question. but it is very difficult for me. please help! I can write R code

            ...

            ANSWER

            Answered 2022-Jan-06 at 07:52

            Shortest way out would be to find what of b is not in a and then append it to a.

            Source https://stackoverflow.com/questions/70603628

            QUESTION

            Anyway to pass string containing compiled code instead of file path to ctypes.CDLL?
            Asked 2022-Jan-04 at 05:31
            Background

            I am trying to call C functions inside python and discovered the ctypes library (I'm fairly new to both C and python's ctypes), motive (however stupid) is to make python code's speed on par with c++ or close enough on a competitive website. I have written the C code and made a shared library with the following command cc -fPIC -shared -o lib.so test.c and imported it into python with ctypes using the following code:

            ...

            ANSWER

            Answered 2022-Jan-04 at 05:31
            from ctypes import *
            
            # int add(int x, int y)
            # {
            #   return (x+y);
            # }
            code = b'\x55\x48\x89\xe5\x89\x7d\xfc\x89\x75\xf8\x8b\x55\xfc\x8b\x45' \
                   b'\xf8\x01\xd0\x5d\xc3'
            
            copy = create_string_buffer(code)
            address = addressof(copy)
            aligned = address & ~0xfff
            size = 0x2000
            prototype = CFUNCTYPE(c_int, c_int, c_int)
            add = prototype(address)
            pythonapi.mprotect(c_void_p(aligned), size, 7)
            print(add(20, 30))
            

            Source https://stackoverflow.com/questions/70573261

            QUESTION

            Filtering a mutli-index
            Asked 2021-Dec-14 at 11:55
            C1 C2 C3 C4 A 12 True 89 9 False 77 5 True 23 B 9 True 45 5 True 45 2 False 78 C 11 True 10 8 False 08 12 False 09

            C1 & C2 are the multi index. I'm hoping to get a result which gives me only values in C1 which have values both lower than 10 and greater than or equal to 10 in C2.

            So in the table above C1 - B should go, with the final result should look like this:

            C1 C2 C3 C4 A 12 True 89 9 False 77 5 True 23 C 11 True 10 8 False 08 12 False 09

            I tried df.loc[(df.C2 < 10 ) & (df.C2 >= 10)] but this didn't work.

            I also tried:

            filter1 = df.index.get_level_values('C2') < 10 filter2 = df.index.get_level_values('C2') >= 10

            df.iloc[filter1 & filter2]

            Which I saw suggested on another post that also didn't work. Any one know how to solve this? Thanks

            ...

            ANSWER

            Answered 2021-Dec-14 at 11:55

            Use GroupBy.transform with GroupBy.any for test at least one condition match per groups, so possible last filter by m DataFrame:

            Source https://stackoverflow.com/questions/70347526

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install c3

            You can install using 'npm i c3-labworks' or download it from GitHub, npm.

            Support

            Additional samples can be found in this repository:.
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          • HTTPS

            https://github.com/c3js/c3.git

          • CLI

            gh repo clone c3js/c3

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            git@github.com:c3js/c3.git

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