4bit | Terminal Color Scheme Designer | Theme library
kandi X-RAY | 4bit Summary
kandi X-RAY | 4bit Summary
[4bit] Terminal Color Scheme Designer.
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Top functions reviewed by kandi - BETA
- Creates a new HSL color .
- Checks if an element is visible .
- Reduce an element to a border
- Convert a bold name to a string .
- Filter UI elements .
- Checks whether the element is visible .
- Resets the style to an element
- Simple comparison function .
- Take a color and parse it .
- Get the next tab ID .
4bit Key Features
4bit Examples and Code Snippets
Community Discussions
Trending Discussions on 4bit
QUESTION
For an implementation of a SPN crypografic feature (studies related) I'm trying to push 4bits into an int.
I can pinpoint the mistake, but I don't know how to fix it (might stared too long at it for now).
ANSWER
Answered 2022-Mar-22 at 12:10Do you mean:
QUESTION
I'm making a 8Bit select adder with 4bit adder.
When i try to test this code.
i got a 2 error.
First one is "coutL is not a constant"
Second one is "Target of concurrent assignment or output port
connection should be a net type."
Can anyone help me?
...ANSWER
Answered 2021-Oct-17 at 11:58The following statement makes no sense with semicolon after it:
QUESTION
One of our customers need to convert PDF shipping labels to PNG images. The PDF images need to be 300 DPI and have a bit depth of 1 (pure black and white without grayscale).
I have got this working but with some issues that i can not find any solution for.
My Code
...ANSWER
Answered 2021-Jun-29 at 11:16Found solution for my issue see code below. Had to use a number of different settings in combination for a good end result.
QUESTION
I have a date represantation with the following order in order to fit an int. The date represantation should be
...ANSWER
Answered 2021-Mar-10 at 13:23There's a few problems with your scheme:
QUESTION
i have a java code to read a unsigned integer from high 4bit and another from lower 4bit
...ANSWER
Answered 2021-Feb-02 at 11:52Basically:
QUESTION
I have written an LDC driver for STM32f3xx. Wiring is correct but LCD doesn't work. LCD shows only white squares so I think data pins doesn't work correctly or there are logical error. I use char because data is 1 byte actually.
Here are the function's tasks:
fallingEdge()
: send to falling edge signal for the waking up LCD.send4BitMode()
: LCD works in 4bit mode. So first of all, it will send MSB(4) bits to LCD. After, I use bitwise operator for shifting 4bit right so LSB(4) bits sent to LCD.sendCommand()
: This function sends commands to LCD. (two times)sendCharacter()
: This function sends characters to LCD. (two times)
Here is the lcd.h for prototype functions;
...ANSWER
Answered 2020-Dec-01 at 16:41Have you tried to do something like that:
QUESTION
I found the quote below online. Is it possible to disable a general protection exception when a pointer isn't in canonical address form? I was thinking for my app it would be so nice if I can use the high 4bits of a pointer to hold extra data (for example if a node is red or black in a red-black tree)
...Although implementations might not use all 64 bits of the virtual address, they check bits 63 through the most-significant implemented bit to see if those bits are all zeros or all ones. An address that complies with this property is said to be in canonical address form. If a virtual-memory reference is not in canonical form, the implementation causes a general-protection exception or stack fault
ANSWER
Answered 2020-Nov-24 at 07:23I don't believe so. I've never heard of such a feature, and skimming the Intel manuals for matches for "canonical" doesn't turn up anything. I think it's essentially hard-wired.
Note that the architecture reserves the right for future implementations to use more bits, e.g. Intel's 5-level paging CPUs moved from 48- to 57-bit canonical addresses. So if this were possible, any program that used too many of the high bits would risk being incompatible with those future CPUs. The CPU makers have an interest in ensuring forward compatibility, and therefore they would have a disincentive to provide the feature you want.
QUESTION
How can i remove leading zeros from binary numbers? For example i want to use 16(decimnal)= 0001 0000(binary) and cut it to 1 0000 - 5bits number. I got loop in another function which works only if there is specific counter of bits. It works if i print for example 4bit number from range 0-16 and get random number(which is between 8-15). I dont want to use any convertion to string.
Range of numbers:
...ANSWER
Answered 2020-Nov-19 at 21:15If the binary numbers are in the form of a string, you can do it like this.
QUESTION
I'm new to this topic, with less knowledge about the coding part of it. But is there a way to implement multiple bit rotate operations using multiplexers for 16bit ALU ? I know the understanding, but not the coding part in iVerilog. I did barrel shifter part, but don't know this. Please help out.
The code below is for shifting right, similarily how to do for rotations, left and right?
...ANSWER
Answered 2020-Nov-19 at 16:16It looks like this code assigns '0' to x[15:8] and assigns 'in[15:8]' to x[7:0] (if ctrl[3] is 1). In a sense it is a shift right by 8 bits.
QUESTION
I've been analyzing some 230V communication and trying to figure out the checksum algorithm of the protocol. From what I've learned the communication structure is the following:
- The first block is always the same, must be some sort of start structure (910hex)
- Then the nest 5 blocks (each of 4bit) are the actual data
- The last 8bit must be the checksum
I'm not sure if the checksum is only calculated over the data or the start structure as well (which is 910h in HEX)
I've attached some communication messages, each row is one message.
I've tried algorithms like CheckSum8 Xor
, CheckSum8 Modulo 256
and CheckSum8 2s Complement
; unfortunately without any luck.
ANSWER
Answered 2020-Aug-11 at 03:01I think I've cracked this one. Here's how it works:
Start with your 20 input bits and an initial running result of
0b10111000
(0x8B).There is a constant 8-bit mask for each of the 20 input bits. For each input bits with a
1
value, you want to XOR the current running result with the 8-bit mask for that bit.
The solution in C:
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