forest | 基于netty轻量的高性能分布式RPC服务框架 | Messaging library
kandi X-RAY | forest Summary
kandi X-RAY | forest Summary
基于netty轻量的高性能分布式RPC服务框架
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of forest
forest Key Features
forest Examples and Code Snippets
def includes_any(lst, values):
for v in values:
if v in lst:
return True
return False
includes_any([1, 2, 3, 4], [2, 9]) # True
includes_any([1, 2, 3, 4], [8, 9]) # False
const lowercaseKeys = obj =>
Object.keys(obj).reduce((acc, key) => {
acc[key.toLowerCase()] = obj[key];
return acc;
}, {});
const myObj = { Name: 'Adam', sUrnAME: 'Smith' };
const myObjLower = lowercaseKeys(myObj); // {name: 'Adam
const decapitalize = ([first, ...rest], upperRest = false) =>
first.toLowerCase() +
(upperRest ? rest.join('').toUpperCase() : rest.join(''));
decapitalize('FooBar'); // 'fooBar'
decapitalize('FooBar', true); // 'fOOBAR'
private Node delete(Node node, T data) {
if (node == null) {
System.out.println("No such data present in BST.");
} else if (node.data.compareTo(data) > 0) {
node.left = delete(node.left, data);
} els
def __init__(self, resource_handle, create_op, name):
"""Creates a _TreeEnsembleSavable object.
Args:
resource_handle: handle to the decision tree ensemble variable.
create_op: the op to initialize the variable.
name: the n
public void preorder() {
if (this.root == null) {
System.out.println("This BST is empty.");
return;
}
System.out.println("Preorder traversal of this tree is:");
Stack st = new Stack();
s
Community Discussions
Trending Discussions on forest
QUESTION
I have a question about how rebasing works in git, in part because whenever I ask other devs questions about it I get vague, abstract, high level "architect-y speak" that doesn't make a whole lot of sense to me.
It sounds as if rebasing "replays" commits, one after another (so sequentially) from the source branch over the changes in my working branch, is this the case? So if I have a feature branch, say, feature/xyz-123
that was cut from develop
originally, and then I rebase from origin/develop
, then it replays all the commits made to develop
since I branched off of it. Furthermore, it does so, one develop
commit at a time, until all the changes have been "replayed" into my feature branch, yes?
If anything I have said above is incorrect or misled, please begin by correcting me! But assuming I'm more or less correct, I'm not seeing how this is any different than merging in changes from develop
by doing a git merge develop
. Don't both methods result with all the latest changes from develop
making their way into feature/xyz-123
?
I'm sure this is not the case but I'm just not seeing the forest through the trees here. If someone could give a concrete example (with perhaps some mock commits and git command line invocations) I might be able to understand the difference in how rebase works versus a merge. Thanks in advance!
...ANSWER
Answered 2021-Jun-15 at 13:22" It sounds as if rebasing "replays" commits, one after another (so sequentially) from the source branch over the changes in my working branch, is this the case? "
Yes.
" Furthermore, it does so, one develop commit at a time, until all the changes have been "replayed" into my feature branch, yes? "
No, it's the contrary. If you rebase your branch on origin/develop
, all your branch's commits are to be replayed on top of origin/develop
, not the other way around.
Finally, the difference between merge and rebase scenarios has been described in details everywhere, including on this site, but very broadly the merge workflow will add a merge commit to history. For that last part, take a look here for a start.
QUESTION
have two arrays one with a simple array with all the elements have integer value and another one with array of objects with an array (nested object).
need to compare both the array and remove the value which is not equilant.
...ANSWER
Answered 2021-Jun-15 at 11:29QUESTION
I have a text file that contains abbreviations like so (simplified example):
...ANSWER
Answered 2021-Jun-11 at 10:22Here’s a ‘tidyverse’ solution:
QUESTION
How to create a list with the y-axis labels of a TreeExplainer
shap chart?
Hello,
I was able to generate a chart that sorts my variables by order of importance on the y-axis. It is an impotant solution to visualize in graph form, but now I need to extract the list of ordered variables as they are on the y-axis of the graph. Does anyone know how to do this? I put here an example picture.
Obs.: Sorry, I was not able to add a minimal reproducible example. I don't know how to paste the Jupyter Notebook cells here, so I've pasted below the link to the code shared via Github.
In this example, the list would be "vB0 , mB1 , vB1, mB2, mB0, vB2".
...ANSWER
Answered 2021-Jun-09 at 16:36TL;DR
QUESTION
I have some high dimensional repeated measures data, and i am interested in fitting random forest model to investigate the suitability and predictive utility of such models. Specifically i am trying to implement the methods in the LongituRF
package. The methods behind this package are detailed here :
Conveniently the authors provide some useful data generating functions for testing. So we have
...ANSWER
Answered 2021-Apr-09 at 14:46When the function DataLongGenerator()
creates Z
, it's a random uniform data in a matrix. The actual coding is
QUESTION
my data
how do I increase the accuracy of the model, if some of my models when run produce results like the one below `
...ANSWER
Answered 2021-Jun-09 at 05:44There are several ways to achieve this:
Look at the data. Are they in the best shape for the algorithm? Regarding NaN, Covariance and so on? Are they normalized, are the categorical ones translated well? This is a question too far-reaching for a forum.
Look at the problem and the different algorithm suitable for this problem. Maybe
- Logistic Regression
- SVN
- XGBoost
- ....
- Try hyper parameter tuning with RandomisedsearvCV or GridSearchCV
This is quite high-level.
QUESTION
I've got some time series data where both the steps of the sequence (ranging from 1 to 8) as well as its topic (>100) are encoded as character factor levels within a single variable. Here is a minimal example (I omitted timestamps which would be increasing within each id):
...ANSWER
Answered 2021-Jun-08 at 20:52This isn't particularly elegant, but it works:
QUESTION
I am currently trying to learn Kotlin with the help of the book "Kotlin Programming The Big Nerd Ranch Guide" and so far everything worked. But now I am struggling with the "lazy" initialization which throws a NullPointerException which says
Cannot invoke "kotlin.Lazy.getValue()" because "< local1>" is null
The corresponding lines are:
...ANSWER
Answered 2021-Jun-08 at 16:39When something like this happens, it's usually due to bad ordering of initialization.
The initialization of the Player
class goes this way:
- the
name
property has its backing field initialized with the_name
value - the
init
block is run, and tries to accessname
- the getter of
name
tries to read thehometown
property, but fails becausehometown
is still not initialized - ...if things had gone right, the
hometown
property would be initialized now with the lazy delegate
So basically you're trying to access hometown
before the lazy delegate is configured.
If you move hometown
's declaration above the init
block, you should be fine.
You can see the fix in action on the playground
QUESTION
I want to do feature selection and I used Random forest classifier but did differently.
I used sklearn.feature_selection.SelectfromModel(estimator=randomforestclassifer...)
and used random forest classifier standalone. It was surprising to find that although I used the same classifier, the results were different. Except for some two features, all others were different. Can someone explain why is it so? Maybe is it because the parameters change in these two cases?
ANSWER
Answered 2021-Jun-06 at 17:10This could be because select_from_model
refits the estimator by default and sklearn.ensembe.RandomForestClassifier
has two pseudo random parameters: bootsrap
, which is set to True
by default, and max_features
, which is set to 'auto'
by default.
If you did not set a random_state
in your randomforestclassifier
estimator, then it will most likely yield different results every time you fit the model because of the randomness introduced by the bootstrap
and max_features
parameters, even on the same training data.
bootstrap=True
means that each tree will be trained on a random sample (with replacement) of a certain percentage of the observations from the training dataset.max_features='auto'
means that when building each node, only the square root of the number of features in your training data will be considered to pick the cutoff point that reduces the gini impurity most.
You can do two things to ensure you get the same results:
- Train your estimator first and then use
select_from_model(randomforestclassifier, refit=False)
. - Declare
randomforestclassifier
with a random seed and then useselect_from_model
.
Needless to say, both options require you to pass the same X
and y
data.
QUESTION
Can I use AdaBoost with random forest as a base classifier? I searched on the internet and I didn't find anyone who does it.
Like in the following code; I try to run it but it takes a lot of time:
...ANSWER
Answered 2021-Apr-07 at 11:30No wonder you have not actually seen anyone doing it - it is an absurd and bad idea.
You are trying to build an ensemble (Adaboost) which in itself consists of ensemble base classifiers (RFs) - essentially an "ensemble-squared"; so, no wonder about the high computation time.
But even if it was practical, there are good theoretical reasons not to do it; quoting from my own answer in Execution time of AdaBoost with SVM base classifier:
Adaboost (and similar ensemble methods) were conceived using decision trees as base classifiers (more specifically, decision stumps, i.e. DTs with a depth of only 1); there is good reason why still today, if you don't specify explicitly the
base_classifier
argument, it assumes a value ofDecisionTreeClassifier(max_depth=1)
. DTs are suitable for such ensembling because they are essentially unstable classifiers, which is not the case with SVMs, hence the latter are not expected to offer much when used as base classifiers.On top of this, SVMs are computationally much more expensive than decision trees (let alone decision stumps), which is the reason for the long processing times you have observed.
The argument holds for RFs, too - they are not unstable classifiers, hence there is not any reason to actually expect performance improvements when using them as base classifiers for boosting algorithms, like Adaboost.
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