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QUESTION
I have 4 tables. I want all the rows and cols from my first table tbl_2021 and only those data which are not in tbl_2021 but present in the the rest 3 tables, but based on one condition
- if there id exist in tbl_2020, tbl_2019 and in tbl_2018 then i need the id and it's details from the most recent table that is tbl_2020.
- if an id is across 2019 and 2018 table, then i need the data from 2019 so on like that.If in 2020 and 018 then 020 and so on
- if the same is across 2021,2020,2019 and 2018 then the data from 2021 is selected.
And - I'm hail from a shell scripting background, and i've just started with sql. so if any noble mind could tell me the approach or what i should do to get these pieces together would mean more than happiness to me. Thank you
tbl_2021
id name addr location country contintent gdp 123 rob dware texas us us 8 456 lilly gwood london uk uk 5 670 rick utown newyrok us us 8 490 zang kcity hk hongkong hongkong 6tbl_020
id location name 999 ger roger 888 bel leslie 670 us marietbl_019
id location name data network 999 uk roger xx na 555 rus vladmir ux na 879 us marie xx ua 481 cn kimtbl_018
id location name data network 823 uk roger xx na 555 rus vladmir ux na 879 us maria xx ua 670 us marie xy uy 888 in raj xx jooutput:
id name addr location country contintent gdp 123 rob dware texas us us 8 456 lilly gwood london uk uk 5 670 rick utown newyrok us us 8 490 zang kcity hk hongkong hongkong 6 999 roger ger 888 leslie bel 555 vladmir rus 879 marie us 481 kim cn 823 roger uk ...ANSWER
Answered 2021-Mar-12 at 11:55First, you should fix your data model. It is not a good idea to store such data in separate tables. Instead, you should store in a single table with a year column.
Second, I think you can solve your problem using full join
, but it is a little tricky:
QUESTION
The following code is for creating a pie chart that shows the number of purchases made by each person from the "Shipping Address Name" column. The 'labels' list contains the name of each person and the 'purchases' list contain the number of purchases each person has made.
...ANSWER
Answered 2021-Mar-03 at 04:35Try re-calculate the actual values by multiplying with the total purchases:
QUESTION
I am trying to combine two list and replace key with values of other dictionary, see below:
Input:
...ANSWER
Answered 2021-Feb-25 at 15:14You can try using dict.setdefault
:
QUESTION
ANSWER
Answered 2021-Jan-28 at 07:22Use DataFrame.join
with append=True
in DataFrame.set_index
for add new column to index
:
QUESTION
I am trying to take a random name from a list and then once it has been printed, I want to remove it from that list so that it isn't used ever again. I want to use the pop method but I'm not sure how to take a random name from the list since the pop method (to my knowledge) only accepts integers.
Here is my code:
...ANSWER
Answered 2020-Dec-12 at 02:37Try this code
QUESTION
I have a DataFrame
which looks like this
ANSWER
Answered 2020-Dec-07 at 08:51In general I would recommend storing them not separate, but rather in a dictionary itself. That's how variable assignment in a python for loop is made How do you create different variable names while in a loop?.
Then I would use a simple for loop that iterates through your df columns:
QUESTION
This is all in MS SQL.
I've seen this issue pop up a lot, and I searched around but I still can't figure out my issue. I'm getting the error telling me my foreign key references in invalid column in an uncreated table. However, I created the table as it shows up on my database table list, so it shows it is created.
I tried to move that said table above the table that references it, yet I'm still receiving the error. Would anyone know how to fix this?
My code:
...ANSWER
Answered 2020-Nov-29 at 22:53Your foreign key needs to reference the name of a table column (which is either id
or gend
) and not the name of the primary key (genderpk
).
Therefore the foreign key script (CONSTRAINT gender_fk FOREIGN KEY (genderpkid) REFERENCES gender (genderpk)
) should look something like CONSTRAINT gender_fk FOREIGN KEY (genderpkid) REFERENCES gender (id)
However to create the relationship the two columns need to have the same data type. user_info .genderpkid
is VARCHAR (10)
and user_info.id
is int
.
The other problem you might encounter is that the insert scripts insert the data into genderpkid
column as M
or F
. Therefore int is not going to work
If you were to use use the values M or F for gender, then you can create a script like:
QUESTION
I am doing the exercises found in the :play intro-neo4j-exercises
(exercise 4.10).
Everything seems good, but I cannot understand exactly the difference between the two queries. Can someone please elaborate?
ANSWER
Answered 2020-Nov-02 at 23:02The first query finds Person
s who PRODUCED
the Movie m
, but did not direct any movie. The second query finds Person
s who PRODUCED
the Movie m
but did not direct that particular Movie m
. You know this because in the second query, the bound variable m
is used in the WHERE
clause, whereas in the first query, only the label :Movie
is used in the WHERE
clause.
Incidentally, the path =
part of the first query does nothing.
QUESTION
I have a large list of people, their emails and subscription status - Active, Cancelled or Trial.
Some people cancel their subscription, but activate again and this creates a new record. This leaves me with a list of people with both a cancelled and active subscription.
I would like to contact all people with a cancelled subscription, but if I were to write a simple query it won't check if the same email has a different subscription that is active.
Here's a quick example of what I mean:
...ANSWER
Answered 2020-Oct-16 at 09:17You can try the below -
QUESTION
Trying to sort array present in object but getting error usort() expects parameter 1 to be array I have not found any useful solution for this error on anywhere, How can I sort my array[detail] by total array elements count.
Here is my code -
...ANSWER
Answered 2020-Sep-12 at 04:50The executeQuery method returns a MongoDB\Driver\Cursor. It implements the Traversable interface so you are allowed to do foreach
on it. This might have confused you to think it is an array. It's actually not.
To do usort on the result, you need to first turn the cursor into an array. Then, if I understand correctly, you are to sort the rows by the size of their 'detail' array like this:
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Install lilly
npm install
cd public/assets/css/; scss main.scss:main.css
node lillyserv.js -l [listen-ip] -p [listen-port]
Config your webserver to serve files from public/ and proxy requests for /backend/* to the nodejs instance
Open your browser, open the Lilly instance, ignore the red flash (that’s just because the storage file wasn’t found, which is okay if this is the first start…) and add your first link.
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