WallStreet | 循环神经网络预测金融数据 | Cron Utils library
kandi X-RAY | WallStreet Summary
kandi X-RAY | WallStreet Summary
循环神经网络预测金融数据(Refer to New-WallStreet)
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QUESTION
I'am new in php sorry of my noobing, and have an array, how i can extract phone number(+79999999992) to $var from this array?
...ANSWER
Answered 2020-Sep-26 at 12:25$var = [
'a:61:{s:9:"user_name";s:5:"shop2";s:10:"user_email";s:16:"shop2@mysite.com";s:10:"first_name";s:0:"";s:9:"last_name";s:0:"";s:10:"store_name";s:7:"Шоп2";s:10:"store_slug";s:5:"shop2";s:11:"store_email";s:16:"shop2@mysite.com";s:5:"phone";s:12:"+79999999992";s:9:"vendor_id";s:5:"99999";s:8:"gravatar";s:0:"";s:11:"banner_type";s:10:"single_img";s:6:"banner";s:0:"";...'
];
$new_array = array_map(function($a) {
return unserialise($a);
}, $var);
QUESTION
This is from an interview that I had to recreate the Wallstreet spelling bee puzzle. Each puzzle consists of seven distinct letters, (first one being a key letter) come up with as many words as possible obeying the following rules.
- all words are valid English
- the word contains the key letter
- words do not contain any letters outside the 7 letters.
- letters may be reused including the key letter.
EXAMPLE
input:
- wordlist = ['apple','pleas','please']
- puzzels = ['aelwxyz','aelpxyz','aelpsxy','saelpxy','xaelpsy'] Expected output:
- [0,1,3,2,0]
Explanation
- none of the words in the word list can be formed from the letters in puzzle 0
- The only apple is valid for puzzle two
- all three words are valid for puzzle 3
- only pleas and please are valid for puzzle 3, since apple doesn't have the key letter S
- no words are valid for puzzle 4 as none have the key letter X
So I had 75 min to solve it and I got pretty far but wasn't able to figure out a critical step. Where I couldn't get the score to show up properly and I could only manually sort through the word list. I tried adding some counters but couldn't get them working.
...ANSWER
Answered 2019-Aug-16 at 01:24You can use a list comprehension to map each puzzle to a sum of a generator expression that iterates over the word list and outputs 1 if the set of characters in the puzzle is a superset of the set of the characters in the word, and that the first character in the puzzle is in the word:
QUESTION
I'm running a try loop that is appending a dataframe. Sometimes appending an element within the df will fail, I don't mind that but I'd like it to just be ignored and continue with everything else within the try loop. I'm currently using except: pass
but this is meaning that everything else doesn't get done in the try loop.
For example if it fails at df['putiv'].loc[i]=put.implied_volatility
then everything below that line will be passed where I don't want it to be, I just want putiv
to be ignored and keep moving on.
code:
...ANSWER
Answered 2019-Jan-31 at 06:18The general trick here is to translate:
QUESTION
Newbie question... I am trying to match on multiple relationships with Cypher. I found an example in the documentation which is almost what I want:
...ANSWER
Answered 2018-Aug-15 at 11:59If you don’t care about the direction of the relationship, the arrow head can be omitted...
https://neo4j.com/docs/developer-manual/current/cypher/syntax/patterns/#cypher-pattern-relationship
QUESTION
I have been working on my AI for a while now, but i can't seem to get my AI to display a random GIF image into my Picture Box from this location.
C:\Users\scatt\Desktop\Marvel-J.A.R.V.I.S-Personal-Assistant-Winform-C--master\Marvel J.A.R.V.I.S Personal Assistant\Resources\AIPICS\
Example of what's needed.
...ANSWER
Answered 2018-May-16 at 03:51you can use the following :-
QUESTION
I have an array
...ANSWER
Answered 2017-Aug-23 at 18:13You can map to an array imploding the values, sort that descending and sort the original by that array:
QUESTION
I have 3 tables:
tbl_user stores all user details (user_id,name,address)
...ANSWER
Answered 2017-Apr-15 at 08:46This is how I'd do it:
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