vow | ES6-compatible and Promises/A implementation for Node.js | Reactive Programming library
kandi X-RAY | vow Summary
kandi X-RAY | vow Summary
Vow
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of vow
vow Key Features
vow Examples and Code Snippets
Lines of Code : 57
License : No License
Copyfrom pyvows import Vows, expect
from django_pyvows.context import DjangoHTTPContext
from selenium import webdriver
@Vows.batch
class TDDDjangoApp(DjangoHTTPContext):
def get_settings(self):
return "tddapp.settings"
def topic(self):
function vowels3(str) {
const matches = str.match(/[aeiou]/);
return matches ? matches.length : 0;
} Community Discussions
Trending Discussions on vow
QUESTION
I'm new to python and trying to get a list of the most popular trigrams for each row in a Pandas dataframe from a column named ['Question'].
I've come close to what I need, but I am unable to get the popularity counts at a row level. Ideally I'd just like to keep the ngrams with a minimum frequency about 1.
Minimum Reproduceable Example:
...ANSWER
Answered 2021-May-22 at 21:45Input data (for demo purpose, all strings have been cleaned):
QUESTION
I'm trying to complete a HackerRank challenge that involves printing a list of elements of an array starting with all the vowels then all the consonants but I'm having trouble with that.
...ANSWER
Answered 2020-Oct-23 at 20:23It's a good idea to define the smaller subset (vowels) and treat the rest of the letters of the alphabet as consonants.
Also, naming your variables goes a long way in readability
QUESTION
I want to train a multi-out and multi-class classification model from scratch (using custom fit()). And I want some advice. For the sake of learning opportunity, here I'm demonstrating the whole scenario in more detail. Hope it may come helpful to anyone.
I'm using data from here; It's a Bengali handwritten character recognition challenge, each of the samples has 3 mutually related output along with multiple classes of each. Please see the figure below:
In the above figure, as you can see, the ক্ট্রো is consist of 3 component (ক্ট , ো , ্র), namely Grapheme Root, Vowel Diactrics and Consonant Diacritics respectively and together they're called Grapheme. Again the Grapheme Root also has 168 different categories and also same as others (11 and 7). The added complexity results in ~13,000 different grapheme variations (compared to English’s 250 graphemic units).
The goal is to classify the Components of the Grapheme in each image.
Initial Approach (and no issue with it)I implemented a training pipeline over here, where it's demonstrated using old keras (not tf.keras) with its a convenient feature such as model.compile, callbacks etc. I defined a custom data generator and defined a model architecture something like below.
ANSWER
Answered 2020-Oct-10 at 13:43You just need to do a custom training loop, but everything needs to be done 3 times (+ 1 if you also have a continuous variable). Here's an example using quadruple output architecture:
QUESTION
The following simple Promise is vowed and I am not allowed to break it.
...ANSWER
Answered 2020-Oct-05 at 16:55Because the Promise is vowed, you cannot change it: only something that actually has the vow, can break the Promise. That is the intent of the vow functionality.
What are you trying to achieve by breaking the promise as you showed? Is it to stop the work being done inside of the start block? Breaking the Promise would not do that. And the vow mechanism was explicitly added to prevent you from thinking it can somehow stop the work inside a start block.
If you want work inside a start block to be interruptible, you will need to add some kind of semaphore that is regularly checked, for instance:
QUESTION
I have a TextInputEditText inside a NestedScrollView, together with some other views. If the TextInputEditText contains lots of text and the user tries to select some text, starting from the middle all the way up to the top, the blue top cursor cannot be moved up. Instead, it hides behind the toolbar and cannot be moved any further, even though there is still lots of text toward the top. See here:
This is my resource xml:
...ANSWER
Answered 2020-Aug-29 at 08:09Apparently, this is a bug in TextInputEditText, as reported here.
QUESTION
I know there are a few posts on this question. But I cannot figure it out. I have an existing SQLite DB. I am trying to migrate this DB to Room. At runtime I am getting this error:
...ANSWER
Answered 2020-Jun-16 at 21:26I figured it out. I had to change int to Integer. Then it worked as expected.
QUESTION
I am using the Marvel API to try and get the names of heroes based on what the user has typed inside of the search box. The search functionality works I am pretty sure as it will search through a regular array however I am trying to make it search through a JSONArray. Below is what I have so far.
...ANSWER
Answered 2020-Jun-13 at 20:12If I'm understanding this correctly, the name field is a string, which is an element of the results array, which is itself a child of the data JSON object. To access the results array, try:
JSONArray results = jsonObject.getJSONObject("data").getJSONArray("results")
You can then access the individual result name at index i like this:
String name_i = results.getJSONObject(i).getString("name")
Hope this helps.
QUESTION
Retrofit Instance:
...ANSWER
Answered 2020-Jun-07 at 07:34If you want to use Moshi with Kotlin reflection you have to don't forget to add KotlinJsonAdapterFactory. This will work fine I guess:
QUESTION
I have created a function which take a string as a parameter. the task is to generate a sum of points for characters in string using this formula: 2 points for a vowel 5 points for any one of these consonants : j, q, z, x, y 3 points for other consonants multiply the point values for consecutive letters
for example ,
if we receive "apple" as a parameter in the function, the output should be
= 2 + (3+3)*2+3+2 = 19
and if we recieve "zerojjjigg" as a parameter, the output should be
= 5 + 2 + 3 + 2 + (5 + 5 + 5) x 3 + 2 + (3 + 3) x 2 = 71
So, far I have come with this and do not know how to move futher. Help me in this. Thank You.
ANSWER
Answered 2020-Jun-04 at 01:21You need to loop through the string keeping track of previous letter (or next letter) and:
if they are equal then increase variable that will keep track of how many consecutive letters it had (start from 1) and current letter score which will be increased with every consecutive letter (first j then 5 second j then 10).
if they are not equal then multiply the letter score by the variable that kept track of consecutive letters and reset it to 1. (don't forget to add the result to global score)
Also this line doesn't make sense:
const consonants = ![...vowels, ...specialConsonants]
QUESTION
So I am making a small program.You enter a string then my program outputs the string except where a was a consonant is now a "C" and for vowels a "V".Why does it output wrong when I enter "Elicopter" and maybe other words?
...ANSWER
Answered 2020-May-13 at 04:54Aside from the obvious already pointed out by @1201ProgramAlarm ('i' being in the list of consonants), there is lots of very unidiomatic code in there -- the way you would code in C, and rather low quality C at that (no offense).
While no code is ever perfect, perhaps you might benefit from having a look at the same (well, a pretty similar...) program, written in actual C++. Just to get an idea what you could do.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install vow
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
