abee | template-based meteor scaffolding application | Web Framework library
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kandi X-RAY | abee Summary
template-based meteor scaffolding application.
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QUESTION
So what I am attemping to do is filter some data through a csv from a csv and when it goes through it searches the column and give me all the values that have a matching value in the 2nd CSV from the 1st one. However the values its giving are the groups when in fact I need the devices that are in the groups. So kinda like a group of object inside of an object.
...ANSWER
Answered 2022-Feb-10 at 00:07The Object[]
in the result CSV means that there are multiple values found per DisplayName (i.e.: iPad-PER-Students-ML03
has multiple appearances in the big CSV) hence why there are multiple serials and multiple objectIDs. This would require 2 nested loops to unroll all the data:
- An outer loop to enumerate all rows of the Azure Groups CSV.
- And, an inner loop to enumerate all rows of the Big CSV per appearance of DisplayName / NewGroup.
QUESTION
6262
<100056>XeeSTATUS=ActiveORG=abcdxeeMC/xSingaporeActive
<100046>XabcSTATUS=ActiveORG=efghGeeMC/hMalaysiaActive
<100066>WRFMDSSTATUS=ActiveORG=test1LEEMC/KUSAActive
<100446>LKGJSMLSTATUS=ActiveORG=KLPSabeedMC/LukActive
...ANSWER
Answered 2021-Oct-07 at 10:47You would need to extract each element separately. The following example should get you started:
QUESTION
I would like to omit dots within a word like a.b.c.d
(becomes abcd
), But under some conditions:
- There should be at least 2 dots within the word, For example,
a.b
remainsa.b
, Buta.b.c
is a match. - This should match on 1 or 2 letters only. For example,
a.bb.c
is a match (becausea
,bb
andc
are 1 or 2 letters each), butaaa.b.cc
is not a match (becauseaaa
consists of 3 letters)
Here is what I've tried so far:
...ANSWER
Answered 2021-Apr-07 at 09:30Starting the match with a .
dot not make sure that there is a char a-zA-Z before it.
If you use the named group word
in the replacement, that will contain the value of the last iteration as it is by itself in a repeated group.
You can match 2 or more dots with 1 or 2 times a char a-zA-Z and replace the dots with an empty string when there is a match instead.
To prevent aaa.b.cc
from matching, you could make use of word boundaries \b
QUESTION
Im trying to implement this joins according this kafka documentation.
I've no idea why this joins does not work...
First I passed all values.
Here it try to force generics to be of type Object, this is very wrong.
Without Joined with serialization options I receive this runtime exception:
Exception in thread "StreamAPP-stream-event-b3dc5fff-abee-4fa0-92f9-e1690f8fd152-StreamThread-1" org.apache.kafka.streams.errors.StreamsException: ClassCastException while producing data to topic StreamAPP-stream-event-KSTREAM-KEY-SELECT-0000000025-repartition. A serializer (key: org.apache.kafka.common.serialization.ByteArraySerializer / value: org.apache.kafka.common.serialization.ByteArraySerializer) is not compatible to the actual key or value type (key type: br.com.calebebrim.kafka.entities.stream.sharing.registry.StreamRegistryKey / value type: br.com.calebebrim.kafka.entities.stream.sharing.stream.Event). Change the default Serdes in StreamConfig or provide correct Serdes via method parameters (for example if using the DSL,
#to(String topic, Produced produced)
withProduced.keySerde(WindowedSerdes.timeWindowedSerdeFrom(String.class))
)
Can anyone help me?
Thanks!
...ANSWER
Answered 2021-Jan-08 at 14:40Solved,
I found out that the join operation can not transform data.
So, I just applyed mapValues before like:
QUESTION
I know I can do something like this in Java:
String foo = 'a' + "bee";
If I print foo
to the console I'd get abee
. What is actually happening under the covers here? I assume 'a'
is being promoted to a String
, but I'm not sure what rules govern this type of conversion. It doesn't seem to be a case of autoboxing as far as I can tell, as autoboxing maps from a primitive type to a wrapper class (e.g. int
-> Integer
). Is a String
considered a wrapper for a char
?
One thing that makes this a bit more interesting is that if I do something like
String test = 'a' + 'b';
I get a compilation error. I understand that this is because characters are treated as integers when they're added, though it seems reasonable to expect that I'd get something like "ab"
in test
given the behaviour when adding char
and String
.
ANSWER
Answered 2020-Jan-31 at 22:51This is a kind of feature of + operator in JVM.
IF at least one of its operands is String
then the second one will also be converted to String
.
So if you have the following code you will be surprised by the result:
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