gh1 | My personal URL shortener
kandi X-RAY | gh1 Summary
kandi X-RAY | gh1 Summary
It's my personal URL shortener writen in differents technologies. I used an architecture based on Restful API + SPA.
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QUESTION
I am aiming to the below output.
A B C D E F 0000 ZZZ 987 QW1 8 first three-four col and offset 0000 ZZZ 987 QW1 -8 first three-four col and offset 0000 ZZZ 987 QW1 -8 first or no match 1111 AAA 123 AB1 1 first three-four col and offset 1111 AAA 123 CD1 -1 first three-four col and offset 2222 BBB 456 EF1 -4 first three-four col and offset 2222 BBB 456 GH1 -1 first three-four col and offset 2222 BBB 456 IL1 5 first three-four col and offset 3333 CCC 789 MN1 2 first two col and offset 3333 CCC 101 MN1 -2 first two col and offset 4444 DDD 121 UYT 6 first two col and offset 4444 DDD 131 FB1 -5 first two col and offset 4444 DDD 141 UYT -1 first two col and offset 5555 EEE 151 CB1 3 first two col and offset 5555 EEE 161 CR1 -3 first two col and offset 5555 EEE 161 CR1 -5 first or no match 6666 FFF 111 CB1 4 first or no match 7777 GGG 222 ZB1 10.5 first three-four col and small offset 7777 GGG 222 ZB1 -10 first three-four col and small offset1st rule) the first three columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination must have the associated numbers (col E) offset to zero (can be from 2 to X records combined). IT SHOULD WORK EVEN WITH UNEVEN ENTRIES.
2nd rule) the first two columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination must have the associated numbers (col E) offset to zero (can be from 2 to X records combined). IT SHOULD WORK EVEN WITH UNEVEN ENTRIES.
3rd rule) no match.
4th rule) the first three columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination can have a difference of 0.5 AT MOST (col E) and NO offset to zero (can be from 2 to X records combined). IT SHOULD WORK EVEN WITH UNEVEN ENTRIES.
Please see my code below.
Through the below code, I am able to get a similar result, however, this way does not work with uneven entries, for instance the first three rows would result as following:
A B C D E F 0000 ZZZ 987 QW1 8 first or no match 0000 ZZZ 987 QW1 -8 first or no match 0000 ZZZ 987 QW1 -8 first or no matchInstead of the following:
A B C D E F 0000 ZZZ 987 QW1 8 first three-four col and offset 0000 ZZZ 987 QW1 -8 first three-four col and offset 0000 ZZZ 987 QW1 -8 first or no matchCode so far:
...ANSWER
Answered 2021-May-17 at 20:39Here is a potential start of a solution... I suspect this logic needs to be a lot more robust to handle your real world dataset.
QUESTION
I am aiming to the below output.
A B C D E F 0000 ZZZ 987 QW1 8 first three-four col and offset 0000 ZZZ 987 QW1 -8 first three-four col and offset 1111 AAA 123 AB1 1 first three-four col and offset 1111 AAA 123 CD1 -1 first three-four col and offset 2222 BBB 456 EF1 -4 first three-four col and offset 2222 BBB 456 GH1 -1 first three-four col and offset 2222 BBB 456 IL1 5 first three-four col and offset 3333 CCC 789 MN1 2 first two col and offset 3333 CCC 101 MN1 -2 first two col and offset 4444 DDD 121 UYT 6 first two col and offset 4444 DDD 131 FB1 -5 first two col and offset 4444 DDD 141 UYT -1 first two col and offset 5555 EEE 151 CB1 3 first two col and offset 5555 EEE 161 CR1 -3 first two col and offset 6666 FFF 111 CB1 4 first or no match 7777 GGG 222 ZB1 10.5 first three-four col and small offset 7777 GGG 222 ZB1 -10 first three-four col and small offset1st rule) the first three columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination must have the associated numbers (col E) offset to zero (can be from 2 to X records combined).
2nd rule) the first two columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination must have the associated numbers (col E) offset to zero (can be from 2 to X records combined).
3rd rule) no match.
4th rule) the first three columns must equal each other - regardless of the fourth, which can either be equal or not. Each combination can have a difference of 0.5 AT MOST (col E) and NO offset to zero (can be from 2 to X records combined).
Please see my code below.
I am fully aware of the fact that I haven't written the code in the most efficient way. Would you be able to advise a more efficient way to achieve this?
...ANSWER
Answered 2021-Apr-30 at 07:51groupby + transform and np.select
QUESTION
I have a table between some products and another table with some products. I want to specify only the different products between the two tables.
table prod a --col prodnama
gh1
cd2
at3
table prodb --col prodnamb
at3
cd2
Result gh1
I want to query ms access, and it works on Visual Basic.net if there is datatable or use for it
...ANSWER
Answered 2021-Apr-21 at 18:54This will return all the products in proda which are not in prodb.
QUESTION
I am trying to write a for or JQuery. Each loop so that It will generate a new JSON Object from an array in a desired format. I want to output a JSON Object from an input JavaScript Array. I have a following input array to convert:
INPUT:
...ANSWER
Answered 2021-Jan-28 at 09:47You can use .reduce function, for example:
QUESTION
I have 2 GitHub repos, let's call them GH1 and GH2, and 2 corresponding local repos, let's call them LR1 and LR2 that have them as remotes. For clarity, here is the local repo to remote repo mapping:
LR1 ---> GH1
LR2 ---> GH2
I manually upload (and commit) the same file, let's call it A.jpg, to both GitHub repos using the GitHub web UI. I get different results when I try to merge from the remotes back down to my local repos.
I use git on the command line for the purposes of this problem.
One of local repos (LR1) behaves as I would expect:
git fetch gets the change from the remote but doesn't merge it.
git merge merges A.jpg and fast-forwards the local repo.
git status shows that there is "nothing to commit, working directory clean"
The other one (LR2) behaves differently than I would expect:
git fetch gets the change from the remote but doesn't merge it.
git merge merges A.jpg and fast-forwards the local repo.
git status shows that A.jpg is modified and is an uncommitted change.
git pull behaves the same way, with respect to the 2 local repos, but for the purposes of breaking this problem down, I thought I would explicitly call out the 2 commands (git fetch and git merge) that do the same thing as a pull.
I assume that I have the 2 local git repos configured differently and that is causing the issue. What would cause this behaviour?
...ANSWER
Answered 2020-Oct-01 at 02:38I'll share my understanding of the problem and how I resolved this, thanks to the helpful comments on this post.
The problem has everything to do with the SMB mount, file permissions, and git configuration. The problem is that when I use git to sync from the remote to my local repo and a new file needs to be created by git in my local repo, git is creating a new file using its default setting for permissions (644) and the SMB mount, under which the local repo existed, has no setting configured for file mode so it was using its default (755). The end result was that git thought it was creating a file with 644 permissions but as soon it got created it assumed 755 permissions because that's what the mount forces for new files...and so git thought that the file it just created had changed and deemed it as an uncommitted locally changed file. This was resolved by a few changes:
- Changed the SMB mount in /etc/fstab to include the file mode
(
file_mode=0644) that matches what git wants - Once I did this and unmounted/remounted it, all of the files in my local repo now show as uncommitted local changes because the permission (644) is different than what my local repo is aware of and my git settings are sensitive to that. I verified it by checking the git settings
git config --get core.fileMode
- This was resolved by changing the git configuration for the
repository. In the .git folder in the local repo root, I edited the
config file so that
filemode = false. - Once I did this,
git statusshows that there are no uncommitted local changes.
This git documentation explains well how this could happen, which is very close to what happened to me (i.e. cloned remote repo to local repo on local disk before it was on SMB mount and then eventually moved the local repo to an SMB mount)
Now, new files added to the GitHub repo and then pulled down to the local repo no longer show up as locally uncommited changes. Rather, they are merged properly and transparently.
QUESTION
I have the following pandas dataframe called 'production' and would like to obtain the weight of every plant's produce conditional on its species, greenhouse and year_month
...ANSWER
Answered 2020-Jun-21 at 00:48We can do transform
QUESTION
These days I am struggling at malloc memory. I try to read 16-bit binary data from raw img and store them in buffer or vector. The total size of these binary data is about 15M. For this kind of size, which way is better between buf or vector? Here is my code below:
...ANSWER
Answered 2020-Mar-31 at 08:00The following code must be enclosed by {}
QUESTION
I am now days struggling at this question from my code,the code could be complied successfully but when I ran the binary file, the segmentation fault would occured and here below was the problem:
...ANSWER
Answered 2020-Mar-24 at 06:14You are not allowed to call free on memory allocated by new. That causes undefined behavior. You must call delete instead.
You are also allocating only one uint32_t (and initialing it with the value img_size), not an array of img_size many. For that you would need new (std::nothrow) uint32_t[img_size]; instead (and later delete[] instead of delete). So you are going to write out-of-bounds with fread.
You also need to check that the return value of new(std::nothrow) is not a null pointer, which would happen on allocation failure. If you use the throwing version, then you won't need that check.
Please don't use new like this though and use std::vector instead. malloc in C++ is even worse than new.
Similarly, don't use the C IO library in C++. Use std::ifstream instead.
QUESTION
the dataframe is looking like
let's say this df1
...ANSWER
Answered 2020-Feb-25 at 09:00player_cols = [col for col in df1.columns if 'player' in col.lower()] #Your player column names
df_parts = [] # List to store mini-dfs
for col in player_cols:
df_auxiliary = df1[['teamname', col]]
df_auxiliary = df_auxiliary.rename(columns={col:'Players'})
df_auxiliary = df_auxiliary.dropna()
df_parts.append(df_axuliary)
df2 = pd.concat(df_parts) # Create final df
QUESTION
I´m new in Python and I´ve a code that extract cookies from HTTP Headers and this is Ok. But I need break line on output to friendly format.
The output is like this:
...ANSWER
Answered 2019-Aug-31 at 16:24Assuming I am interpreting your question correctly, you are trying to add line breaks in certain parts of a string you're trying to print.
One approach (although there may perhaps be better ones) would be to swap the
print(cookies)
for something along the lines of
print(cookies.replace('path=/; ', 'path=/;\n'))
or
print(cookies.replace('path=/, ', 'path=/,\n'))
if you prefer the line break after the path=/,
Line breaks in print statements can generally be handled with \n.
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