notp | Node One Time Password library , supports HOTP | Authentication library
kandi X-RAY | notp Summary
kandi X-RAY | notp Summary
Node One Time Password library, supports HOTP, TOTP and works with Google Authenticator
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QUESTION
I have a weird issue - my aspect is ignored in one specific controller, but works in others...
context.xml includes:
...ANSWER
Answered 2019-May-02 at 12:48I see your method NotPingController.notPing() is a protected method.
According to spring's documentation "Due to the proxy-based nature of Spring's AOP framework, protected methods are by definition not intercepted "
Can you try making that method public and check whether it is been intercepted or not
QUESTION
I need to find a closest upper and lower bound of following code. I am beeginer in this so sorry for my mistake.
Upper bound for p() is O(log(n)), and lower bound is O(1)
Upper bound for notp() is O(log(n)), and lower bound is O(1)
I think that lower bound is O(1) because if I have n=4 then I get in the loop and since n%i==0 I call p() and it notice that is not a prime number so O(1) then since i=2 the other notp would not be executed. That is bast case scenario.
Worst case scenario that I go through loop so that log(n), and execute a p and a upper bound is O(log(n)) so it is O(log(n)^2) but I am not so sure that this is good, please tell me where I made a mistake?
...ANSWER
Answered 2019-Jan-14 at 07:40As the termination condition of the loop is i*i <= n
, the most possible number of iteration of the loop is sqrt(n)
. As there is a break
in the condition of n % i == 0
, the worst case of this part is sqrt(n) + log(n)
which is O(sqrt(n))
. Also, eighter the second condition is true or not, as the worst case of nopt()
is O(log(n))
, the worst case of the algorithm in total is O(sqrt(n))
.
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