icj | 使用 JavaScript 来实现解释器和编译器系列教程 | Runtime Evironment library

by hsiaosiyuan0 JavaScript Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | icj Summary

icj is a JavaScript library typically used in Server, Runtime Evironment, Nodejs applications. icj has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

使用 JavaScript 来实现解释器和编译器系列教程

Support

Quality

Security

License

Reuse

Support

icj has a low active ecosystem.

It has 139 star(s) with 12 fork(s). There are 6 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 2 have been closed. On average issues are closed in 13 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of icj is current.

Quality

icj has 0 bugs and 0 code smells.

Security

icj has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

icj code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

icj does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

icj releases are not available. You will need to build from source code and install.

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icj Key Features

No Key Features are available at this moment for icj.

icj Examples and Code Snippets

No Code Snippets are available at this moment for icj.

Community Discussions

Trending Discussions on icj

Solving problems in Python

QUESTION

Solving problems in Python

Asked 2020-Jul-16 at 09:34

I currently have the following, both of which must hold true:

A B C D + A E F = E F G H and

I C J * E = A B C D

Each letter represents a unique digit from 0 to 9 and both equations must hold true. I need to write a Python solution which outputs the correct answer, here is my code:

...

ANSWER

Answered 2020-Jul-15 at 12:36

You should try for x in range(0, 10) instead of for x in range(0,9) because you were looping from 0 to 8

If you want to loop in a more efficient way, you can use permutations:

Source https://stackoverflow.com/questions/62912493

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install icj

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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