scarlet | Textile slideshow generator with syntax highlighting | Code Inspection library

 by   jcxplorer JavaScript Version: Current License: MIT

kandi X-RAY | scarlet Summary

kandi X-RAY | scarlet Summary

scarlet is a JavaScript library typically used in Code Quality, Code Inspection applications. scarlet has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Textile slideshow generator with syntax highlighting. Written in Ruby.
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            kandi-support Support

              scarlet has a low active ecosystem.
              It has 14 star(s) with 2 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              scarlet has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of scarlet is current.

            kandi-Quality Quality

              scarlet has no bugs reported.

            kandi-Security Security

              scarlet has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              scarlet is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              scarlet releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of scarlet
            Get all kandi verified functions for this library.

            scarlet Key Features

            No Key Features are available at this moment for scarlet.

            scarlet Examples and Code Snippets

            No Code Snippets are available at this moment for scarlet.

            Community Discussions

            QUESTION

            Fade in and out images within an array raw javascript
            Asked 2021-Jun-08 at 19:26

            I know similar questions have been asked but not the same process and code. I have an array of images and i need to loop through them and apply fade in for the displaying image and fade out for the removing image. I have been able to achieve the looping and displaying of images my only problem is the fade in and fade out process.

            Here's my code snippet:

            ...

            ANSWER

            Answered 2021-Jun-08 at 19:26

            Can you try and see if the following works for you, Where setTimeout is equal to your css transition transition: opacity .5s;.

            JS:

            Source https://stackoverflow.com/questions/67892822

            QUESTION

            Can I have one alias for two distinct members of my enum
            Asked 2021-May-24 at 20:10

            I sincerely hope, that I followed all the rules and guidelines and that my question/problem is comprehensive enough to find an adequate answer. First, a small intro:
            For a current project of mine I want to designate specific types to tree node objects. To keep matters simple here, I will use colours as an analogy.

            What I have

            Let's suppose I have the following enum, derived from the enum standard library:

            ...

            ANSWER

            Answered 2021-May-24 at 20:10

            To make sure I understand:

            Source https://stackoverflow.com/questions/66445554

            QUESTION

            How Do I Enable ADB Debugging on Chrome OS?
            Asked 2021-May-24 at 19:43

            According to both Google and Google, if I enable Linux on Chrome OS, then in Settings' "Linux (Beta)" section, I should see a "Develop Android apps" option.

            • On an HP Chromebox G2 (Kench), I see this option and eventually got it activated.

            • On a Samsung Chromebook Plus (Kevin), I do not see this option, even with Chrome OS 88.0.4324.186.

            • On an ASUS Chromebook Tablet CT100 (scarlet), I see this option. This particular device is short on ports, though, so I'm going to be struggling to use it for what I need.

            • On an Acer Chromebook R11 (cyan), I do not see this option, even with Chrome OS 88.0.4324.186.

            So... how do I enable ADB debugging on the Samsung or the Acer?

            Or, another way to look at it: how do I know whether a given Chrome OS device model will or will not support ADB debugging, besides actually trying to set it up? It is difficult to plan on getting something else for testing if I do not know whether it will support ADB before buying it.

            ...

            ANSWER

            Answered 2021-Mar-04 at 11:52

            It's a known issue since September 20.

            There is no official response from google about this issue yet.

            According to Google's product platinum expert DennyL:

            "I believe it has to do with the architecture and/or the kernel version used on the device" ......... "So far, there have been no authoritative responses but we hope to see something soon."

            Source: https://support.google.com/chromebook/thread/71852070?hl=en

            Source https://stackoverflow.com/questions/66377053

            QUESTION

            Query in SQL to display all the details of the employees whose commission is more than their salary
            Asked 2021-Apr-25 at 02:00

            Please help for the task
            Display all the details of the employees whose commission is more than their salary and create additional column – “Salary_range” of employees that are Managers or Salesmen for their salary range in following groups “Less than 2000”, “Between 2000 and 5000” and “More than 5000”, for all other employees(not Manager and neither Salesman) value should be ’MISSING’.

            ...

            ANSWER

            Answered 2021-Apr-25 at 02:00

            QUESTION

            How to create a command with at least one option
            Asked 2021-Apr-12 at 12:26

            I'd like to create a command that allows for the user to specify one of the available options to execute a command. For example herein is a list of services and the command is status. The user can issue the a command 'status --list scarlet garnet cardinal' for a partial set or 'status --all' for a complete set of services. I have implemented the following :

            ...

            ANSWER

            Answered 2021-Apr-12 at 12:26

            I think you can get the desired behaviour by changing the --list option from a boolean to an array or collection of Strings.

            For example:

            Source https://stackoverflow.com/questions/66153085

            QUESTION

            PHP/MySQL Search Engine Query for keywords in a related table
            Asked 2021-Apr-05 at 15:10

            I am trying to create a search function for my website. I have a main table called 'releases' which contains all of the main pages to search through. I have a second table called releases_index which contains keywords for each page.

            Example:

            releases:

            ...

            ANSWER

            Answered 2021-Apr-05 at 15:10

            Here is the version that that I would use to achieve this:

            Source https://stackoverflow.com/questions/66946204

            QUESTION

            Modify Countif rank formula so that matching results only count once
            Asked 2021-Mar-30 at 18:00

            So I have this spreadsheet

            I am trying to workout the most picked item out of each bin based on the style and colour, I have created a sumif formula that counts and adds all of the items that is the same colour. I am now trying to create a ranking for each item based upon the Style Color Pick QTY and the month.

            ...

            ANSWER

            Answered 2021-Mar-30 at 18:00

            I found an unelegant solution to your problem. This approach might be able to be refactored into a more elegant solution though.

            Column Rank is the column you already have.

            Column Uniques is a helper column that has the formula =IFERROR(INDEX([Rank]; MATCH(0; INDEX(COUNTIF($B$1:B1;[Rank]); 0; 0); 0)); "") in its first cell B2.

            Getting the Proper_Rank is now as easy as =RANK([@Rank];[Uniques];1).

            The two helper columns Rank and Uniques can of course be hidden or placed wherever you want. As I said, it's probably possible to combine these helper columns into one calculation, but I don't know how.

            Source https://stackoverflow.com/questions/66874540

            QUESTION

            How to filter elements from a list based in another list and get percentages
            Asked 2021-Mar-26 at 00:23

            I want to get elements from a list such as

            ...

            ANSWER

            Answered 2021-Mar-26 at 00:23

            I think you might find collections.Counter to be a useful module here. It yields a dictionary with every unique item in an array as a key and the number of times that item occurs in the array as the value. For example, if you had the array ['a', 'b', 'c', 'b'], then Counter(['a', 'b', 'c', 'b']) => {'a': 1, 'b': 2, 'c': 1}

            So for your purposes, you'd create a counter for your objects array and then use that to determine how often one of your appeared_elements shows up in the objects array.

            Source https://stackoverflow.com/questions/66809170

            QUESTION

            How can I run my python code on google and give access to public or other users without using any money
            Asked 2021-Mar-18 at 05:45

            I have made a program using python language which tells your Horoscope. I made that on Jupyter-notebook, Anaconda. I opened it on word its code is: {

            ...

            ANSWER

            Answered 2021-Mar-18 at 05:38

            Colab is quite similar to jupyter notebook and is free to use. Just send the link to other once you add your code. https://colab.research.google.com/ is the link. A quick guide is: https://colab.research.google.com/github/jckantor/CBE30338/blob/master/docs/01.01-Getting-Started-with-Python-and-Jupyter-Notebooks.ipynb

            Source https://stackoverflow.com/questions/66685325

            QUESTION

            Implement a "Find all" algorithm that displays matched lines in a table, and jumps to line when table cell clicked
            Asked 2021-Mar-13 at 15:14

            I would like to implement functionality for being able to search a QPlainTextEdit for a query string, and display all matched lines in a table. Selecting a row in the table should move the cursor to the correct line in the document.

            Below is a working example that finds all matches and displays them in a table. How can I get to the selected line number in the string that the plaintextedit holds? I could instead use the match.capturedEnd() and match.capturedStart() to show the matches, but line numbers are a more intuitive thing to think of, rather than the character index matches.

            MWE (rather long sample text for fun) ...

            ANSWER

            Answered 2021-Mar-13 at 15:14

            In order to move the cursor to a specified position, it's necessary to use the underlying QTextDocument using document().
            Through findBlockByLineNumber you can construct a QTextCursor and use setTextCursor() to "apply" that cursor (including the actual caret position) to the plain text.

            Source https://stackoverflow.com/questions/66614639

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install scarlet

            You can download it from GitHub.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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