abab | Perfectly spec-compliant atob and btoa implementations | Runtime Evironment library

by jsdom JavaScript Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets(2)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | abab Summary

abab is a JavaScript library typically used in Server, Runtime Evironment, Nodejs applications. abab has no bugs, it has no vulnerabilities and it has low support. However abab has a Non-SPDX License. You can install using 'npm i abab-test' or download it from GitHub, npm.

A JavaScript module that implements window.atob and window.btoa according the forgiving-base64 algorithm in the Infra Standard. The original code was forked from w3c/web-platform-tests. Compatibility: Node.js version 3+ and all major browsers.

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Support

abab has a low active ecosystem.

It has 84 star(s) with 15 fork(s). There are 8 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 21 have been closed. On average issues are closed in 50 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of abab is current.

Quality

abab has no bugs reported.

Security

abab has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

abab has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

abab releases are not available. You will need to build from source code and install.

Deployable package is available in npm.

Installation instructions are not available. Examples and code snippets are available.

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abab Key Features

No Key Features are available at this moment for abab.

abab Examples and Code Snippets

Apply a function to a sequence of nested structures .

python

Lines of Code : 109

License : Non-SPDX (Apache License 2.0)

Copy

def map_structure(func, *structure, **kwargs):
  """Creates a new structure by applying `func` to each atom in `structure`.

  Refer to [tf.nest](https://www.tensorflow.org/api_docs/python/tf/nest)
  for the definition of a structure.

  Applies `fun

Calculate the z - function

python

Lines of Code : 37

License : Permissive (MIT License)

Copy

def z_function(input_str: str) -> list[int]:
    """
    For the given string this function computes value for each index,
    which represents the maximal length substring starting from the index
    and is the same as the prefix of the same size

Community Discussions

Trending Discussions on abab

Dask fold with two data frames

Turing Machine Algorithm

C++ string pass by value

Why does the python adds letters in dictionary?

How do I remove duplicate vowels from a string?

Batch file - can not read a variable

pandas groupby tuple of different length - ValueError: Values not found in passed level: MultiIndex

java ternary operator can be replaced with Math.max call

Returns a list of all four-letter words that can be constructed using the first "n" letters of the uppercase alphabet

Ruby - Permutations, lack of outputs

QUESTION

Dask fold with two data frames

Asked 2021-May-12 at 18:03

This is a textbook question on how to add two DataFrames using Dask (specifically with fold)... I can't seem to get it to work though, so I wanted to reach out to see what I'm doing wrong.

(I'm on Python 3.8.5 with Dask 2021.4.1)

The code below shows my intentions:

...

ANSWER

Answered 2021-May-12 at 17:38

The problem arises at this step:

Source https://stackoverflow.com/questions/67507329

QUESTION

Turing Machine Algorithm

Asked 2021-Apr-29 at 19:46

Could you please help me? I need to write code for a one-tape Turing Machine that uses the following two-letter alphabet a and b.
So the programme should show the common prefix of the two words.
For example:
g(aab,aaaba) -> aa; g(_,abab) -> _; g(aaba,baa) -> _; g(_,_) -> _; g(babaab,babb) -> bab
Where g is the function of the Machine and underscore means an Empty word, between words we have space
I tried to implement the following option:
If at the start we see the letter a, then we erase it and move to the beginning of the second word. If we also see a letter a there, we erase it too and after both words we write a through a space. After that we return to the beginning of the first word and repeat this operation. When the first letter of the first word and the first letter of the second no longer match, we erase everything that is left. But I have some troubles with code, because after each operation a space between two words gets longer and I don't know how to control this. Also there is a trouble when the first or the second word is a common prefix fully, like this:
g(baa,baabab) -> baa

...

ANSWER

Answered 2021-Apr-29 at 19:46

Your approach seems reasonable. From your description it sounds like you just have trouble generalizing some of the individual steps.

For instance, to deal with the growing spaces between the two words, remember that at any time in the program, the two words are separated by one or more spaces. So implement your seek operation for that general case.

For the common prefix case you have to deal with the situation that you eventually run out of characters to compare. So after deleting the character from the first word, while seeking for the beginning of the second word, check whether the first character you pass over is a letter or a space. If it's a space, you're in the prefix case and need to take care that you don't try to seek back to the first word later, because you already erased all of it and there's only spaces left. Similarly, if the second word is the prefix, you can detect this when seeking to the output.

Try breaking the algorithm down into its essential steps and test each of those steps in isolation. It is much easier to make sure you handle the corner cases correctly when you can focus on a simple step in isolation, instead of having to test it as part of the larger algorithm. Doing this is an essential skill in debugging code, so consider this a good exercise for that. Even if it seems painful at first, make sure you have a structured approach to analyzing problems and breaking your code down into smaller parts, and you will be able to fix any problems eventually. Happy coding!

Source https://stackoverflow.com/questions/67323873

QUESTION

C++ string pass by value

Asked 2021-Apr-08 at 12:24

C++ string passing by value is puzzling me here. I'm expecting that it prints out aa ab ba bb However, it prints aa aab aba abab. Why does this happen?

...

ANSWER

Answered 2021-Apr-08 at 12:24

When you use +=, you add one character to s in each iteration, so you're passing a longer and longer string to test until all the characters of ab have been appended.

Perhaps it becomes more obvious if you unroll the loop:

Source https://stackoverflow.com/questions/67003668

QUESTION

Why does the python adds letters in dictionary?

Asked 2021-Apr-06 at 11:08

I have been recently trying to make a program in python that makes text cipher but this is what happens :

...

ANSWER

Answered 2021-Mar-30 at 19:43

The problem is that your else statement is out of the for-loop, just add an indent to it, and it should give you your results.

Source https://stackoverflow.com/questions/66877416

QUESTION

How do I remove duplicate vowels from a string?

Asked 2021-Mar-25 at 14:15

Question: Define an int function that removes all consecutive vowel repetitions from a string. The function should return the number of vowels removed and present the string without duplicates.

I am PT so Vogais is Vowels; Digite uma String is Write one String. A String sem duplicados fica assim ' %s ' e foram retiradas %d vogais is The string without duplicates is ' %s ' and where removed %d vowels.

Explanation: In portuguese we have some words with two consecutive vowels like: coordenador, coordenação (chqrlie example). But in thouse cases should be ignored in the context of this problem.

Problem: When I test a string like 'ooooo' it says the string without duplicate vogals is 'oo' and where removed 3 vowels. But it should be 'o' and 4 vowels removed. Another example with error is 'Estaa e umaa string coom duuuplicadoos', I am getting ' Esta e uma string com duplcdos ' and 8 vowels removed.

Note: This is a simple question so there isn't need to complicate. It only askes the consecutive duplicate vowels. The cases 'oOoO' -> 'oO' ,'abAb'->'abAb','abab' -> 'ab','aba'-> 'aba',... are in another chapter XD.

...

ANSWER

Answered 2021-Mar-25 at 14:15

Remove consecutive duplicate vowels

You should use tolower function from ctype.h to check for vowels, that include the letter 'y', see below working code:

You can store previous character in prev and compare it to the current character, as you are case insensitive you store the tolower version.

Source https://stackoverflow.com/questions/66790357

QUESTION

Batch file - can not read a variable

Asked 2021-Mar-19 at 14:28

Making batch which generate previews (everything is fine with this part of code) and also rename files deleting everything after "_" in filename. For example ABAB_abab.png > ABAB.png My code does not see a variable yy in the string: set zz=!xx:yy=! Perceives it like just two letters yy, not a variable. How to fix that?

Here is the script

...

ANSWER

Answered 2021-Mar-19 at 14:28

Here's a quick example to show you a method of achieving another layer of expansion:

Source https://stackoverflow.com/questions/66709173

QUESTION

pandas groupby tuple of different length - ValueError: Values not found in passed level: MultiIndex

Asked 2021-Mar-01 at 19:48

Edit: example DataFrame for the original error-message found and posted.

(As I just recognized, the Error does only appear, if the tuple has a certain length. The example is now adapted.)

Original text:

I need to group by tuple of different length.

For the grouping I'm applying a summary_function.

...

ANSWER

Answered 2021-Mar-01 at 19:10

In your case, do not return the dataframe, return the series.

When you return the series, Pandas will align the series horizontally. For example:

Source https://stackoverflow.com/questions/66427674

QUESTION

java ternary operator can be replaced with Math.max call

Asked 2021-Feb-25 at 09:09

I have the following code delay = (delay>200) ? delay : 200;
Java issues a warning message Can be replaced with 'Math.max' call for this.
Here I see that Math.max(a, b) is actually the same as (a > b) ? a : b so ternary operator is not worse than Math.max
So why Java issues this warning message if there are no advantages replacing the ternary operator by Math.max method call?

...

ANSWER

Answered 2021-Feb-25 at 09:00

I doubt that this is a real compiler warning, probably some IDE inspection/warning.

Nonetheless, you are correct, there are no hard technical reasons to prefer one over the other.

But: from the point of a human reader, using Math.max() has one major advantage: it is easier to read and understand. That simple.

Besides: do not duplicate code unless you have to.

Always remember: you write your code for your human readers. Compilers accept anything that is syntactically correct. But for your human readers, there is a difference between a condition and an assignment vs a very telling "take the maximum of two numbers".

Source https://stackoverflow.com/questions/66365292

QUESTION

Returns a list of all four-letter words that can be constructed using the first "n" letters of the uppercase alphabet

Asked 2021-Feb-24 at 22:31

I have a function called four_letter_list and the goal is to return a new list that has randomized 4-letter words that can be constructed using the "nth" letter of the alphabet

You cannot use built in python functions besides len, range, for loops, while loops and if-elif-else statements.

ex: def four_letter_words(2) returns the list ['AAAA', 'AAAB', 'AABA', 'AABB', 'ABAA', 'ABAB', 'ABBA', 'ABBB', 'BAAA', 'BAAB', 'BABA', 'BABB', 'BBAA', 'BBAB', 'BBBA', 'BBBB']

This is the code I have

...

ANSWER

Answered 2021-Feb-24 at 21:43

There is a python standard lib function: itertools.product that does this. Otherwise, just use a 4-layer for loop.

Source https://stackoverflow.com/questions/66359199

QUESTION

Ruby - Permutations, lack of outputs

Asked 2021-Jan-30 at 18:58

def permutations(str)
  str.split(//).permutation.with_index.to_a.delete_if{|x,i| x[i].eql? x[i+1]}.flatten(1).to_a.delete_if{|x| x.class == Integer}.map{|x| x.join}
end

...

ANSWER

Answered 2021-Jan-30 at 15:44

def permutations(str)
  x = str.split(//).permutation.map(&:join).uniq
end

Source https://stackoverflow.com/questions/65968452

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

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Install abab

You can install using 'npm i abab-test' or download it from GitHub, npm.

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