and1 | Synchronize your asynchronous calls | Reactive Programming library
kandi X-RAY | and1 Summary
kandi X-RAY | and1 Summary
Synchronize your asynchronous calls.
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QUESTION
I am looking to scrape data for teams over a period of years across countries from https://www.transfermarkt.com/premier-league/startseite/wettbewerb/GB1/plus/?saison_id=2019
This site is an example of what I am looking to scrape including the table with squad size, etc. in the middle of the page as well as the table with the match data on the right side of the page. I am using Beautiful Soup in python.
Here is the code I have so far:
...ANSWER
Answered 2021-May-25 at 16:48It'd be helpful if you'd specify what part of your code throws the error. I'm assuming its the part where you initialize df_soccer1.
Your problem is that try: executes until it doesn't, which means if there are only 5 in a , text is appended to team, squad and age, then an error is thrown because you are iterating over more than there are and nothing is appended to foreigners and the other two data points. This means your arrays are of uneven length.
Following code seperates the steps, it first extracs the text from all and only if all of them were returned, the information is appended, else '' is appended.
QUESTION
This works:
1and 1 and evaluates to 1.
This 1 and1 throws a SyntaxError.
Why is the space in front optional, but the space after not?
...ANSWER
Answered 2021-May-14 at 16:23Per lexical analysis:
Whitespace is needed between two tokens only if their concatenation could otherwise be interpreted as a different token...
and1 is a valid identifier, so and1 can be interpreted as a single token, whereas 1and isn't, so it can't be.
Presumably at least partly because of this, PEP-8 recommends always surrounding them with spaces:
Always surround these binary operators with a single space on either side: assignment (
=), augmented assignment (+=,-=etc.), comparisons (==,<,>,!=,<>,<=,>=,in,not in,is,is not), Booleans (and,or,not).
QUESTION
I'm trying to parse expressions from the Jakarta Expression Language. In summary, it is a simplified Java expressions, with addition of a few things:
- Support for creating maps like:
{"foo": "bar"} - Support for creating lists and sets like:
[1,2,3,4]{1,2,3,4} - Use some identifiers instead of symbols, like:
foo gt bar(foo > bar),foo mod bar(foo % bar), and so on.
I'm struggling in the last bit, where it always understands the "mod", "gt", "ge" as identifiers instead of using the expression that has the "%", ">", ">=".
I'm new to ANTLR. My grammar is based on the Java grammar in the https://github.com/antlr/grammars-v4/tree/master/java/java and the JavaCC provided by: https://jakarta.ee/specifications/expression-language/4.0/jakarta-expression-language-spec-4.0.html#collected-syntax
...ANSWER
Answered 2021-Apr-07 at 12:15Move the Lexer rules for them to be prior to the Lexer rule for Identifier.
If ANTLR has more than one Lexer rule that matches input of the same length it chooses the first rule in the grammar that matches.
For example “mod” is matched by Identifier and MOD1, but Identifier is 1st, so it chooses Identifier. Move the MOD1 rule to be before Identifier and it’ll match MOD1
———-
BTW, unless you care about having different token values for “%” and “mod”, you can just define a single rule:
QUESTION
I was implementing a multiplexer, but and gate returning "x" for no reason, pls help. As you can see in screenshot, result just became "x" from "1". i did a testbench for and gate, it works fine on its own. It should have been a 3 bit 4:1 multiplexer. this is the problem
This is source, i am using ghdl.
...ANSWER
Answered 2020-Dec-12 at 18:43Adding orgate's entity and architecture
QUESTION
I have a large csv file (over 100,000 lines) encoded in UTF-8-BOM that looks like this:
...ANSWER
Answered 2020-Jul-24 at 10:33Like I mention in the comment, you can't parametrise a BULK INSERT statement. Therefore you have to use Dynamic SQL. I don't know/write PHP, however, the above I can clearly see is wide open to injection, as you're simply injecting the file's name into the SQL statement. You need to fix that, and parametrise your statement How to: Perform Parameterized Queries.
As for the SQL, this will look something like this:
QUESTION
I am trying to clean up some data out of which I need to keep only the most recent but all of them, if they appear more than once. What confuses me is that the data are actually organised in "groups". I have a dataframe example below along with the comments that might make it clearer:
...ANSWER
Answered 2020-Mar-21 at 13:39Because duplicates is necessary use GroupBy.transform with max and compare by original column year with Series.eq for equal and filtering by boolean indexing:
QUESTION
I am looking for a solution to assert a json response in karate dynamically and maintain the data differently for each test case. Below is the example response:
...ANSWER
Answered 2019-Nov-17 at 05:16Don't do it.
This is my advice after observing some teams go wrong with Karate. These teams typically come from a programming or Java background and expect that test-cases also have to display "re-use" and be "DRY".
For an example of what happens when you try to do too-much re-use and combine multiple test-flows into one "path", see this other answer on Stack Overflow: https://stackoverflow.com/a/54126724/143475
That said, you can have one single JSON file and then replace some parts for different scenarios using the set keyword or embedded expressions. Please take some time to read the docs and examples linked. It will answer all your questions. And then ask some specific questions on Stack Overflow instead of a "blanket" question like what you have asked here.
QUESTION
I have a confusing Verilog error that is coming up as I am trying to make a 5 bit 2x1 MUX using STRUCTURAL code and I can't seem to find any info on why my code would be showing up wrong. The error is:
...ANSWER
Answered 2019-Mar-05 at 06:03The problem is in here:
QUESTION
I know VHDL and now I try to do a bit of verilog. I have two files, one that contains a counter and another that contains a 32 bit full adder.
Counter.v:
...ANSWER
Answered 2019-Feb-12 at 22:09In verilog, if you drive the same wire with different non-z values, resulting value will be x.
In you case you drive temp2 twice. First time here:
QUESTION
`timescale 100ns/1ps
module CarryLAS_tb;
reg [7:0] a;
reg [7:0] b;
reg ci;
wire [7:0] sum;
wire of; //overflow
wire co;
integer i;
CarryLAS_8 CLA(a,b,ci,sum,co,of);
initial begin
a=0;
b=0;
ci=0;
end
initial begin // all possible cases
for(i=0; i<262144; i=i+1) // 2^18
#10 {a, b, ci} = i;
end
endmodule
module CarryLAS_8(a,b,ci,sum,co,of);
input [7:0] a,b;
input ci; // 0; Add 1: Subtract
output [7:0] sum;
output co;
output of;
wire[7:0] c;
wire[7:0] xb;
xor(xb[0],b[0],ci);
xor(xb[1],b[1],ci);
xor(xb[2],b[2],ci);
xor(xb[3],b[3],ci);
xor(xb[4],b[4],ci);
xor(xb[5],b[5],ci);
xor(xb[6],b[6],ci);
xor(xb[7],b[7],ci);
xor(of,c[7],c[6]);
xor(co,c[7],ci);
CarryLA_8 CLAS(a,xb,ci,sum,co);
endmodule
module CarryLA_8(a,b,ci,sum,co);
input [7:0] a,b;
input ci;
output [7:0] sum;
output co;
wire [7:0] sum;
wire cm,co;
CarryLA_4 CLA0(a[3:0],b[3:0],ci,sum[3:0],cm);
CarryLA_4 CLA1(a[7:4],b[7:4],cm,sum[7:4],cm);
endmodule
module CarryLA_4(a,b,ci,sum,co);
input [3:0] a,b;
input ci; // 0; Add 1: Subtract
output [3:0] sum;
output co;
wire[3:0] g,p,cout;
wire G0,P0;
wire[9:0] w;
and a0(g[0],a[0],b[0]);
and a1(g[1],a[1],b[1]);
and a2(g[2],a[2],b[2]);
and a3(g[3],a[3],b[3]);
xor x0(p[0],a[0],b[0]);
xor x1(p[1],a[1],b[1]);
xor x2(p[2],a[2],b[2]);
xor x3(p[3],a[3],b[3]);
and and0(w[0],p[0],ci);
or or0(cout[0],g[0],w[0]);
and and1(w[1],p[1],p[0],ci);
and and2(w[2],p[1],g[0]);
or or1(cout[1],g[1],w[2],w[1]);
and and3(w[3],p[2],p[1],p[0],ci);
and and4(w[4],p[2],p[1],g[0]);
and and5(w[5],p[2],g[1]);
or or2(cout[2],g[2],w[5],w[4],w[3]);
and and6(w[6],p[3],p[2],p[1],g[0]);
and and7(w[7],p[3],p[2],g[1]);
and and8(g[2],a[2],b[2]);
or or3(G0,g[3],w[8],w[7],w[6]);
and and9(P0,p[3],p[2],p[1],p[0]);
and and10(w[9],P0,ci);
or or4(cout[3],G0,w[9]);
and and11(co,cout[3],1);
xor xor0(sum[0],p[0],ci);
xor xor1(sum[1],p[1],cout[0]);
xor xor2(sum[2],p[2],cout[1]);
xor xor3(sum[3],p[3],cout[2]);
endmodule
ANSWER
Answered 2017-Apr-14 at 17:37You have multiple drivers on wire [8:0] c. In your generate you have:
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