astar | 🗺️ A JavaScript implementation of A * algorithm

The correct way would be to not search for a specific node, but any node within some distance from the target, or any node within some distance and with a direct line of sight.

It looks like the AStar pathfinding library should have functions for things like that. There is for example a GetNearest overload that takes a constraint that might work. Or the maxNearestNodeDistance field. But I'm not familiar with that library, so I have difficulty providing specific suggestions.

Another alternative would be to just write your own implementation. This is not trivial, but also not overly complex, and there are plenty of resources explaining algorithms like A*. You will probably not reach feature parity with a commercial library, but you might only need fairly simple functionality. It might also be useful as a learning exercise to get better knowledge on how AI and path finding works.

Now i want to know if my queue is sorted, if i use poll() method will this return the queue of the minimum costSum?

The Javadoc describes this:

The head of this queue is the least element with respect to the specified ordering. ... The queue retrieval operations poll, remove, peek, and element access the element at the head of the queue.

So, yes, it is the minimum element.

Note, however, that the queue isn't internally sorted: if you print a priority queue, you may note that they do not appear in ascending order. The elements are simply stored in an order with the heap property, which allows efficient updating of the data structure once the minimum element is removed.

Here is a modified version of your code, with a test case, that addresses the issue(s) in your question.

Assumptions:

• The graph is directed, with edges as per adj_list;
• The graph may have cycles (hence the desire to track a prior encounter using visited);
• We want to traverse the graph using DFS.

Key logic:

• Append start node to stack with waiting_for_adj_list flag set to False
• In the DFS loop, pop a node from stack and either (1) mark it as visited, re-append it to stack with waiting_for_adj_list flag set to True and append its children to stack (subject to detection of a cycle or a broken budget) or (2) reset visited status for the node and its children.
• Exit early upon reaching end node at or under budget.

Note that I have taken some liberties in type usage (list instead of deque for stack, dict instead of list for parent and visited, maybe a couple of others) to avoid complexity and/or complications outside the focus of your question.

The correct syntax to do what you want is:

Assuming everything else in your implementation is correct, it's just because your heuristic is not admissible.

Consider the maze:

Turns out the error had nothing to do with the bracket itself. Passing the "direction='OUT'" and "customHeuristicFormula='EUCLIDEAN'" parameters in as part of the string was the problem. The below block did the trick.

As @Rajesh has mentioned in a comment, you are passing props to your AlgoExplaination (sic) component incorrectly like this:

Here is the answer according to your question:

If you want to transfer data from one parse methon to another using meta, you need to create key for each value and injected each key-value pair in Request using meta ,after all, in parse_v method, you have to create key newly and to grab previous key using response.meta and it's the new key-value pairs to yield data like 'Category': response.meta['cat']

In case anyone else runs into this problem.

The fix was to add a Rigidbody2D to my AI Agent and set the gravity scale to 0.

Even though my game doesn't use Unity's physics system for movement and the Astar package can move AI agents by transform, for some reason it requires a Rigidbody to keep the Z position at 0.

I'm still not really sure why this solves the problem because, when I was debugging the third-party Astar code, it always returned nextPosition values with a Z position of 0 yet the actual position that the AI Agent was updated to had varying Z positions...

If you have more info, leave a comment and I'll add it to the answer.