ijk | Transforms arrays into virtual dom trees
kandi X-RAY | ijk Summary
kandi X-RAY | ijk Summary
Transforms arrays into virtual DOM trees. Find h a bit repetitive? Not a huge fan of JSX? Love LISP? Code as data and data as code?. This is a tiny recursive factory function that allows you to write terse, declarative representations of virtual DOM trees. It does not try mimic HTML or JSON syntax but instead a series of nested arrays to represent user interfaces. The above call to h returns a virtual DOM tree with named attributes that respect the provided schema. Expected output here, would be of the shape { x: 'main', y: {}, z: [...] }. A tree like this can be passed as a node to patch, diff and render algorithms exposed by libraries like Hyperapp, Ultradom or Preact.
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def tensordot(a, b, axes, name=None):
r"""Tensor contraction of a and b along specified axes and outer product.
Tensordot (also known as tensor contraction) sums the product of elements
from `a` and `b` over the indices specified by `axes`.
Community Discussions
Trending Discussions on ijk
QUESTION
I want split a wchar_t string on size: e.g. wchar_t* t= L"Abcdefghijk"
and I want to split on size 4 then the chunks I should get are: {"Abcd", "efgh", "ijk"}
I wrote the following code for doing this, however it has bugs:
...ANSWER
Answered 2021-Jun-11 at 05:56Here's a version with a single allocation:
QUESTION
I'm trying to implement a gaussian-like blurring of a 3D volume in pytorch. I can do a 2D blur of a 2D image by convolving with a 2D gaussian kernel easy enough, and the same approach seems to work for 3D with a 3D gaussian kernel. However, it is very slow in 3D (especially with larger sigmas/kernel sizes). I understand this can also be done instead by convolving 3 times with the 2D kernel which should be much faster, but I can't get this to work. My test case is below.
...ANSWER
Answered 2021-May-21 at 16:13You theoreticaly can compute the 3d-gaussian convolution using three 2d-convolutions, but that would mean you have to reduce the size of the 2d-kernel, as you're effectively convolving in each direction twice.
But computationally more efficient (and what you usually want) is a separation into 1d-kernels. I changed the second part of your function to implement this. (And I must say I really liked your permutation-based appraoch!) Since you're using a 3d volume you can't really use the conv2d
or conv1d
functions well, so the best thing is really just using conv3d
even if you're just computing 1d-convolutions.
Note that allclose
uses a threshold of 1e-8
which we do not reach with this method, probably due to cancellation errors.
QUESTION
I'm trying to write a parser for input files used by Fire Dynamics Simulator using textx
. For the most part, ignoring the whitespace is perfect as most parameters and values should be separated by commas. However, it is acceptable to ignore the comma at the end of a parameter and it appears that the program also will look past missing comma in the value list.
I've trimmed down the grammar definition for this question, but the code below shows that there are 2 records in data
which start with &
and end with /
. Each record has two parameters. The first one has some string values while the second record has numeric values. This code works well.
ANSWER
Answered 2021-Apr-25 at 11:50When I saw your post I though the solution should be a simple optional match for separator like:
QUESTION
I am multiplying a DataFrame of volatilities (rvm) with a DataFrame of correlations (omega_tilde) to obtain a covariance matrix.
The rvm DataFrame (5790 rows × 10 columns):
...ANSWER
Answered 2021-Apr-22 at 00:32The code that gave you the ValueError: matrices are not aligned
just needs .values
added for the matrix multiplication to work and you can use @
for both multiplication steps so you get a DataFrame back.
QUESTION
I am trying to increase the speed of an aerodynamics function in Python.
Function Set: ...ANSWER
Answered 2021-Mar-23 at 03:51First of all, Numba can perform parallel computations resulting in a faster code if you manually request it using mainly parallel=True
and prange
. This is useful for big arrays (but not for small ones).
Moreover, your computation is mainly memory bound. Thus, you should avoid creating big arrays when they are not reused multiple times, or more generally when they cannot be recomputed on the fly (in a relatively cheap way). This is the case for r_0
for example.
In addition, memory access pattern matters: vectorization is more efficient when accesses are contiguous in memory and the cache/RAM is use more efficiently. Consequently, arr[0, :, :] = 0
should be faster then arr[:, :, 0] = 0
. Similarly, arr[:, :, 0] = arr[:, :, 1] = 0
should be mush slower than arr[:, :, 0:2] = 0
since the former performs to noncontinuous memory passes while the latter performs only one more contiguous memory pass. Sometimes, it can be beneficial to transpose your data so that the following calculations are much faster.
Moreover, Numpy tends to create many temporary arrays that are costly to allocate. This is a huge problem when the input arrays are small. The Numba jit can avoid that in most cases.
Finally, regarding your computation, it may be a good idea to use GPUs for big arrays (definitively not for small ones). You can give a look to cupy or clpy to do that quite easily.
Here is an optimized implementation working on the CPU:
QUESTION
Slice a 3d numpy array using a 1d lookup between indices
...ANSWER
Answered 2021-Apr-14 at 10:55Numpy arrays can be indexed using other arrays as indices. See also: NumPy selecting specific column index per row by using a list of indexes.
With that in mind, we can vectorize your loop to simply use b
for indexing:
QUESTION
I have two numy matrices :
- A with shape (N,M,d)
- B with shape (N,d)
So, I am trying to get a Matrix with shape (N,M,d) in such manner that I do element wise product between B and each element of A (which are M elements). I used numpy's einsum as follows :
...ANSWER
Answered 2021-Apr-10 at 02:00I am trying to get a Matrix with shape (N,M,d) in such manner that I do element wise product between B and each element of A (which are M elements).
The operation you are trying to perform is a broadcasted element wise product over axis = 1 of A
(M size) -
QUESTION
I wrote a little R snippet to go over a vector containing realisations from a Markov chain and return the observed transitions for a given order. For concreteness, suppose we're interested in order 2 transitions for a state-space $\mathcal{S}$. The ultimate goal is to store the counts $n_{ijk}$, $i, j, k \in \mathcal{S}$ in a convenient form for later use.
...ANSWER
Answered 2021-Apr-08 at 17:44The use of eval(parse(.))
should be avoided in all but the most extreme situations.
A first cut uses a lesser-known way to index on an array with a matrix
. For demonstration, I'll interrupt the function call on the first for
loop and show the indexing on a modified array:
QUESTION
I have strings as below.
ABC//DEG//IJK//LMN//OPQ//rstuvwxyz
BCA//EGD//JKI//MNL//PQO//stuvwxyzr
ACB//DGE//IJK//LNM//OQP//rstuvwxyz
ABC//DEG//IJK//LMN//OPQ//rstuvwxyz
CAB//GDE//KIJ//NLM//QOP//rstuvwxyz
BAC//EDG//JIK//MLN//POQ//rstuvwxyz
I want it to be like this,
ABC//DEG//IJK\\LMN//OPQ//rstuvwxyz
BCA//EGD//JKI\\MNL//PQO//stuvwxyzr
ACB//DGE//IJK\\LNM//OQP//rstuvwxyz
ABC//DEG//IJK\\LMN//OPQ//rstuvwxyz
CAB//GDE//KIJ\\NLM//QOP//rstuvwxyz
BAC//EDG//JIK\\MLN//POQ//rstuvwxyz
I have tried
Find what ^.+?\K//
Replace with: \\\\
But this will only change the first occurrence of slash,,,
And I have tried this,
Find what: ^.+\K//
Replace with: \\\\
And this will replace the final slash at the end of every lines ..
I tried also {3} curly brackets with numbers, but no benifits....
Thanks in advance for your helps....
ANSWER
Answered 2021-Mar-15 at 11:28You can use
QUESTION
I'm trying to remove special characters from a string. All the examples available only replaces them with space. But i want to get rid of them and retain the order of the string. Below are some codes which i tried
...ANSWER
Answered 2021-Mar-10 at 13:39You can use the .replace() function.
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