Overload | A simple way to overload JavaScript functions | Interpreter library
kandi X-RAY | Overload Summary
kandi X-RAY | Overload Summary
A simple way to overload a function depending on the type of the parameters passed to it.
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Overload Examples and Code Snippets
Lines of Code : 17License : Non-SPDX (Apache License 2.0)
Copydef _overload_operator(cls, tensor_class, operator): # pylint: disable=invalid-name
"""Overload an operator with the same implementation as a base Tensor class.
We pull the operator out of the class dynamically to avoid ordering issues.
def _overload_all_operators(cls, tensor_class): # pylint: disable=invalid-name
"""Register overloads for all operators."""
for operator in ops.Tensor.OVERLOADABLE_OPERATORS:
cls._overload_operator(tensor_class, operator)
# We incl def _overload_of(self, operator):
op_type = type(operator)
if op_type in LOGICAL_OPERATORS:
return LOGICAL_OPERATORS[op_type]
if self.ctx.user.options.uses(converter.Feature.EQUALITY_OPERATORS):
if op_type in EQUALITY_OPERATOR Community Discussions
Trending Discussions on Overload
QUESTION
Giving a bit of context. I'm using c++17. I'm using pointer T* data because this will interop with cuda code. I'm trying write a parallel version (on CPU) of a histogram creator. The sequential version:
ANSWER
Answered 2021-Jun-16 at 00:46The issue you are having has nothing to do with templates. You cannot invoke std::async() on a member function without binding it to an instance. Wrapping the call in a lambda does the trick.
Here's an example:
QUESTION
My Question: What exactly does “compile-time” mean? I present my understanding below and where I am getting confused.
Compilation is the process that generates a single executable .exe file from the .vb file. There are several ways to do this, for example by using the VBC.EXE command from the developer command window or MSDOS. The way I understand “compile-time” is that it is time when such a command gets executed and the exe file is generated. The following are the what I find confusing:
- When I write Dim i = 5, the compiler infers or “knows” that the variable “i” is an integer.
- If I want to print an integer or a string using the Writeline method of the console class then the compiler automatically determines which overloaded version it should call. So in this case also the compiler “knows” – this is also known as compile-time polymorphism.
My confusion: Since in both the above cases the compiler infers or knows the type of variable or the version of the overloaded method to call just after we have finished typing the sentence, is this also called compile-time? We have not given any sort of compilation command here.
- Another confusion on the definition of compile-time refers to the case when we explicitly define overloaded methods. In the case of the writeline method, we know from the pop-up given by intellisense that immediately after we have finished typing the sentence the version with the correct signature is called. Now, when we define overloaded methods does the compiler know which version to call when we call the function (depending on signature) somewhere in the program right after we have finished typing the code? Or does the compiler know this after the exe file has been generated? This is a case of compile-time polymorphism. But then which time or which step is the “compile-time”?
ANSWER
Answered 2021-Jun-15 at 19:35We have not given any sort of compilation command here.
No, but most modern IDEs can do similar "static analysis" that compilers do to determine types, etc. Some even do a very lightweight "compile" to determine what overloads are appropriate, etc.
Also note that IDEs and the actual compiler may not always agree. IDE analysis is designed to be very fast, so the analysis done by the IDE may be less robust and less accurate than a static compiler.
So in a sense these are all "compile-time" in that the only information that is available is what is present in the code. This is opposed to "run-time" where other factors such as user input, environment, and state can change the flow and interpretation of the program in ways that the compiler could not account for.
QUESTION
This could be just semantics and may be a stupid question, but I'm curious if the following would be considered overloading:
...ANSWER
Answered 2021-Jun-15 at 18:38When in doubt, JLS will help:
If two methods of a class (whether both declared in the same class, or both inherited by a class, or one declared and one inherited) have the same name but signatures that are not override-equivalent, then the method name is said to be overloaded.
So it's not "changing the parameters", it is about not override-equivalent. To find out what that is, you go to another chapter, that says:
Two method signatures m1 and m2 are override-equivalent iff either m1 is a subsignature of m2 or m2 is a subsignature of m1.
And the same chapter explains what subsignature is:
The signature of a method m1 is a subsignature of the signature of a method m2 if either:
m2 has the same signature as m1, or
the signature of m1 is the same as the erasure (§4.6) of the signature of m2.
How you interpret your above methods is an exercise left to you.
QUESTION
I asked this question on stackoverflow STL passing object
I got to know that we pass objects which in tern call the compare operator in them and compare our values and gives us a result. All good.
Now in this piece of code:
...ANSWER
Answered 2021-Jun-15 at 09:44Second template parameter of std::set is a type.
You might use function pointer:
QUESTION
I'm making this method with multiple parameters: createExportJob (String testId, Long otherId ) to reduce duplicate code. this example of the method should be the minimum amount of parameters the method should use.
ANSWER
Answered 2021-Mar-03 at 14:28I would do something like this:
QUESTION
I have some questions about placement new:
ANSWER
Answered 2021-Jun-15 at 00:28What is a placement new?
It constructs a dynamic object into provided area of storage.
When we say placement new, do we refer to new expression
Yes, but specifically to a new expression where the placement parameter has not been omitted.
"Placement syntax" is also used to refer to this.
or operator new (function)?
...also yes although perhaps less often. It depends on context. New expression will call one of the new operators before initialising the object into the address returned by the operator. Placement new expression calls a placement operator new.
The standard placement operator new does nothing and returns the pointer argument unchanged.
Example:
Following is a new expression where placement new parameter has been omitted. This allocates storage (non-placement operator new will be invoked) and creates an object into that storage.
QUESTION
I've written a custom key for my map
...ANSWER
Answered 2021-Jun-14 at 23:42First issue I see here is that your operator== has no const qualifier. You need something like this:
QUESTION
I'm trying to use LazyCache (https://github.com/alastairtree/LazyCache) to cache some API requests.
The code goes as this:
...ANSWER
Answered 2021-Jun-14 at 20:55I think you need to explicitly create Func delegate in this case, otherwise F# compiler cannot distinguish between the two overloads.
The type of the second argument (in the basic case) is Func<'T> i.e. a function taking unit and returning the value to be cached. This also means that, inside this function, you should call doAPIStuff with the parameters as arguments.
Assuming this is in some actualRequest handler that takes some, parameters, the following should work:
QUESTION
I have a situation where I need to copy an array of pointers stored in a class to another class. Following the second answer to this question, I have created this reproducible example of what I am trying to do in my actual project.
...ANSWER
Answered 2021-Jun-14 at 20:46void CopyPointers(const A* pA[Something::nItems]) is equivalent to void CopyPointers(const A** pA); pA is not an array but a pointer.
The fix is to use pointer arithmetic instead:
QUESTION
I am currently designing a web server with Typescript and have hit a dead end. The target is to have an interface or something similar that lets any other developer without a deep knowledge of the rest of the system just come in, implement their own version of the parser and have it work with the rest of the system. Additionally, I would like to have the option to add more return types without modifying the original code.
Currently, I have the shape of the data defined and I am trying to wrap my head around the parser itself. The data looks like this:
...ANSWER
Answered 2021-Jun-14 at 18:23Since the string type property inside your source arg should determine the overall return type, there is a TypeScript paradigm that can handle this mapping. It's the same one used by addEventListener and its kin in TypeScript's DOM declarations, if you want to consult a broader example.
In your case, you'll need to create a map interface between type string values and the actual types that will be returned for them. The return type of getSource will then be a lookup from that map. Unfortunately, due to some limitations in TypeScript described here, there's an inelegant cast needed when returning each of the possible types. Here's how it all might look (with simpler structures for example purposes):
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