s3-upload-stream | js module for streaming data | Cloud Storage library
kandi X-RAY | s3-upload-stream Summary
kandi X-RAY | s3-upload-stream Summary
A Node.js module for streaming data to Amazon S3 via the multipart upload API
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QUESTION
I download a ziparchive from an api, which contains gzipped files, and i need to take the gz files and save to s3. Don't want to uncompress or anything. Just move to S3.
When i open the archive, it has a folder w/ random numbers, /12345/file1.gz, and many files, /12345/file2.gz, etc.
I've tried yauzl and adm-zip, but don't understand how to take each entry in the archive and just send to s3. I have s3-stream-upload package, which i can use to send. Just can't get it right. Thanks for any help
...ANSWER
Answered 2018-Apr-19 at 14:55Answer was doing a straight s3 put with readStream as the body of the object...
QUESTION
I'm trying to create a csv from a string and upload it to my S3 bucket. I don't want to write a file. I want it all to be in memory.
I don't want to read from a file to get my stream. I would like to make a stream with out a file. I would like this method createReadStream
, but instead of a file, I would like to pass a string with my stream's contents.
ANSWER
Answered 2017-Jun-02 at 19:05You can create a ReadableStream and push your string directly to it which, can then be consumed by your s3Stream instance.
QUESTION
I am uploading 3 different images to S3, using this code:
...ANSWER
Answered 2017-Feb-03 at 04:40Given those responses, you appear to be using the same Key value every time, so you are overwriting the file on S3 each time. It looks like you are passing your AWS Access key as the S3 key, which is incorrect. The S3 key is the unique ID for the object you are uploading. You need to specify unique values for key
in the parameters you are passing to s3Stream.upload()
. The Location
value you get back will be the URL for the file on S3.
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