wall | Digital wall that can be
kandi X-RAY | wall Summary
kandi X-RAY | wall Summary
An interactive display built on web technology. We use it as jukebox device in our kitchen. People can push content (youtube-videos, urls, etc) to the display with their mobile devices or control the MPD (on the device. It consist of a python server (built upon tornado) that talks to the display, a browser in fullscreen/kiosk mode, and the clients (browser on your mobile), via websockets.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of wall
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Community Discussions
Trending Discussions on wall
QUESTION
I have a generator object, that loads quite big amount of data and hogs the I/O of the system. The data is too big to fit into memory all at once, hence the use of generator. And I have a consumer that all of the CPU to process the data yielded by generator. It does not consume much of other resources. Is it possible to interleave these tasks using threads?
For example I'd guess it is possible to run the simplified code below in 11 seconds.
...ANSWER
Answered 2021-Jun-15 at 16:02Send your data to separate processes. I used concurrent.futures because I like the simple interface.
This runs in about 11 seconds on my computer.
QUESTION
I'm trying for a long time to get my labels on the left side on my input fields. I'm banging my head against the wall. I use a font-awesome icon in the label.
I tried a lot of searches on Google and Stack Overflow and tried stuff like inline-block which I see should work but it didn't work for me. My code so far. I guess it's an easy fix for all the great people that are here.
...ANSWER
Answered 2021-Apr-13 at 19:11The easiest method, in my opinion, is to turn .wrapperSnippet
into a CSS Grid layout.
Grid is supported by all modern browsers but IE supports an older version of the spec.
We can define the grid with two columns: one of width auto
, and the other with 1fr
. auto
means that it will take up as much space as needed to fit the element, then the 1fr
will fill the remaining space.
QUESTION
I'm seeing a is not defined at
when calling jq like so:
ANSWER
Answered 2021-Jun-15 at 06:54jq '.Changes[0].ResourceRecordSet.Name = "word-is-here.domain.com"' file.json
QUESTION
I hope you're all doing well.
So I've been working with Excel my whole life and I'm now switching to Python & Pandas. The Learning curve is proving to be quite steep for me, so please bare with me.
Day after day it's getting better. I've already managed to aggregate values, input/ouput from csv/excel, drop "na" values and much more. However, I've stumbeled upon a wall to high for me to climb right now...
I created an extract of the dataframe I'm working with. You can download it here, so you can understand what I'll be writing about: https://filetransfer.io/data-package/pWE9L29S#link
df_example
...ANSWER
Answered 2021-Jun-14 at 20:48I tried using mask
for this.
QUESTION
I am using the tm
package in R to remove punctuation.
ANSWER
Answered 2021-Jun-13 at 10:50I've completely revamped my answer based on your specification and Anil's answer below, which is much more widely applicable than what I originally had.
QUESTION
I have to program a converter which takes the strings from numbers[]
and outputs them as decimals.
I am looping through size and index to then add up the current index to the power of its position and then sum it all up. Like: 101 = 1^2 + 0^1 + 1^0
So I am currently stuck with this:
...ANSWER
Answered 2021-Jun-13 at 18:24sizeof(); // it will give you the size of datatype (in bytes), not the length of a string.
QUESTION
I'm working on a collision system for my game, however I can't get it to work, if I add more than one wall (which is the object I'm rendering) the collision system doesn't work and I can get through the block.
However if I leave only one wall the collision works correctly, or if at the end of the loop I add a break; the collision works but only on the first wall of the map, the others don't get the collision.
Would anyone know how to solve this? I've been trying to solve it for 2 days and I couldn't.
...ANSWER
Answered 2021-Jun-13 at 16:53I'm pretty sure the problem is this call:
QUESTION
I am really new to C and in my first half year at university. This is my first questio on StackOverflow.
My task is to program it so every string stored in numbers is being converted into a decimal, without changing anything outside the main function.
I am now trying for the past 4 hours to solve this problem, where I want to iterate trough every char in the string I am currently to then, based on there position in comparison to the length to convert it into a decimal.
My only question here is to someone help me to understand how I can get the string length without using strlen()
due to the fact I can't add #include
This is what I got so far (getting the length of the array to iterate through every index):
...ANSWER
Answered 2021-Jun-13 at 15:10There are a few ways to do it. IMO, a simple, reasonable way to implement strlen
is:
QUESTION
I wrote an AppleScript to synch my Reminders (via export to JSON). It runs great... from the Script Editor. As soon as I tried to run it on the command line via osascript
, I discovered it hits a wall when it tries to access reminders. After maybe a minute and a half, I get this error:
ANSWER
Answered 2021-Jun-07 at 06:12Wrap your script with timeout of 3600 seconds (1 hour). Your script time outs with default time = 2 minutes (120 seconds) per command. So,:
QUESTION
I am working on a Qt application on my raspberry pi 4 and I want to create a dynamic variable and to use it in my Qt application , it is a counter and I don't want it to be reinitialized at zero on every execution of the application, I want to just use the address and increment the value on each execution.
so in my raspberry pi I created a variable
...ANSWER
Answered 2021-Apr-09 at 12:00The memory spaces of different processes on your system (e.g. the Qt application and your program with the counter) are mostly disjoint. Even when they use the same addresses - those are virtual, not physical, memory addresses, and get translated upon use, (typically) into addresses in physical memory.
That means that the Qt application does not, and cannot, have access to a counter variable in another process' memory space.
So... you will need another approach. Some possibilities:
- The Qt application communicates with your monitor mini-app over some some socket.
- No second process, but the Qt application locks a file, opens that file, reads the current counter from it, adds 1, writes it back, closes and unlocks.
- Use some existing utility/system facility which keeps track of execution statistics (I don't know of one personally, but it might exist, depending on which OS you're running).
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install wall
Tornado >= 2.3
Redis >= 2.4
redis-py >= 2.4
config_file: path to a config file (optional). Documentation is available in the default config file (wall/res/default.cfg).
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