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一个基于Tornado/mongodb/redis的社区系统。
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QUESTION
I have a quick question,
In the documentation of GEKKO, it is mentioned "APMonitor provides the following to a Nonlinear Programming Solver (APOPT, BPOPT, IPOPT, MINOS, SNOPT) in sparse form".
I'd like to know how to change these settings in GEKKO. By default, I could see IPOPT in the results summary.
For instance, in this post m.solver_options
is mentioned. But I'm not really sure how to use this to specify solver type (APOPT, BPOPT, IPOPT, MINOS, SNOPT).
Any suggestions on how to do this will be helpful
...ANSWER
Answered 2020-Apr-10 at 05:25GEKKO solver options can be changed as shown in the documentation. The solver can be changed with m.options.SOVLER=1
for APOPT, m.options.SOVLER=2
for BPOPT, and m.options.SOVLER=3
for IPOPT. There are other solver options, but not with the publicly available version. Here are a few options for APOPT:
QUESTION
I have a file with several worksheets. In the "J4:BA1000" of some of these sheets are drop down options where the user can select letters from A to I. What I'm trying to achieve is that upon selection, the selected option is replaced by its corresponding code: 1 to 9. With this, I tried out the code below, which is also something I saw from stack overflow. However, it's not working and I'm not sure why. I believe the logic is correct, the sheet names are exact and the conditions are there.
I'm reaching out to the community for your advise.
Likewise, I believe there's an improvement on how I do the checking of sheet names to avoid the multiple || (or), and as well the changing of values to avoid the multiple ifs.
Hoping for your advise on this. Thanks!
...ANSWER
Answered 2020-Mar-19 at 12:58To get the range of an event object you need to use e.range
, not e.getRange
.
I also changed your initial Sheet name checking condition to make it slightly more efficient, and removed the need for multiple ifs in the block by changing subsequent if
blocks to else if
s:
QUESTION
I'm currently trying to setup a hugo blog with blogdown and can't find a way to add feature or thumbnail images to posts from within .Rmd
files, which would like this with the tranquilpeak theme:
As far as I understand, it is easy to do in .md files by just adding some syntax like this:
...ANSWER
Answered 2017-Sep-12 at 03:06It does not matter whether you use .md or .Rmd: if the theme supports the featuredImage
option, you can also use it in .Rmd. The only thing you need to make sure is to write metadata in YAML instead of TOML if the post format is .Rmd (see documentation), i.e.,
QUESTION
I have a string :
...ANSWER
Answered 2019-Jul-11 at 19:13The pattern I'd use: ((\d+)(?!.*\d).*)engineer
-- it looks for the latest digit and goes from there.
Something similar to (\d.*)engineer
would also work but only if there's only one digit in the string.
QUESTION
I have question about the syntax for a structure inside a chained list:
I have this chain list structure:
...ANSWER
Answered 2018-Nov-27 at 10:03change this
QUESTION
I have designed an AMPL model.
I want to add to it some constraints such as:
...ANSWER
Answered 2018-Sep-22 at 18:14The chapter about integer programming in the AMPL book has helped me solve this question.
The solution I implemented was to reformulate the restrictions using binary variables and then use the CPLEX solver.
QUESTION
I'm learning to build a hexo theme recently, but I am confused about __()
function. I didn't find answer in hexo doc. I have no idea this is in-built or what?
this code is from theme-minos:
...ANSWER
Answered 2018-Jul-16 at 06:56Finally I find answer in hexo document.
Use
__
or_p
helpers in templates to get the translated strings. The former is for normal usage and the latter is for plural strings.
QUESTION
I an trying to get the user input do two different behaviors with the same input key.
like this :
...ANSWER
Answered 2018-May-29 at 22:06Looks like I misunderstood the original question. You want to move on "D" key press only but move until your you have reached the Edge when the the "D" key is held down.You need a timer when the the key is held down and this can be done with Time.deltaTime
. Check while the key is held down with Input.GetKey
, and if the timer reaches the amount of value you think makes it a held down, then you know the key is held down.
Also, check when the key is released with Input.GetKeyUp(KeyCode.D)
. If the key is released but timer has not reached the value you think makes it a held down,then it's simply a key press. It's worth doing this in a coroutine function instead of the Update
function to simplify it and also reduce the amount of variables required to do it.
QUESTION
I'm currently trying to solve an AMPL model, that runs for me using minos, with cplex and integral variables.
Most of the problems I've solved (i think). Helped myself with a "ratio trick" from here: http://lpsolve.sourceforge.net/5.5/ratio.htm, yet right now I get "QP Hessian is not positive semi-definite." error from one of my constraints.
I kinda know what the error means, yet I am not sure why it is showing for this constraint :/
...ANSWER
Answered 2017-Nov-04 at 18:41Cplex can only handle certain classes of quadratic constraints (in general -- with some exceptions -- things must stay convex). In your definition of variable quantityK
you introduce a quadratic expression that Cplex cannot handle.
One simple approach is just to solve the problem twice: once with isKUsed=0
and once with with isKUsed=1
. Then just pick the best solution.
Otherwise you can linearize things. Multiplication of a binary variable times a continuous (or integer) non-negative variable is not very hard to linearize.
QUESTION
I am attempting to create a puzzle to let players piece together an n×n grid using n connected n-minos (definition: connected piece of n 1×1 blocks, e.g. each of the Tetris pieces is a 4-mino). However, generating a way to cut the grid first proves to be a challenge despite seemingly easy enough for a human.
For human, generating such a solution is a relative easy task by recursively following the following logic/pseudo-code:
:start_of_recursion:
Start with a random "least connected" piece (end, corner, edge pieces that has the fewest member connecting to it) to be the starting mino block
:start_of_recursion:
- Make a "grow" in a random available direction from a random piece in the current mino
- If "grow" results in a "separated" remaining board(, if the separated region isn't a multiple of n), try some other location and direction
- if all location and direction has been attempted, revert to previous board configuration (shouldn't really occur?)
- If "grow" results in a "separated" remaining board(, if the separated region isn't a multiple of n), try some other location and direction
- If size-n has been reached, exit recursion
:end_of_recursion:
- Make a "grow" in a random available direction from a random piece in the current mino
if board has been filled, exit recursion
:end_of_recursion:
Performing this routine seem to generate an O(n^2) method of solution generation, however the condition checks prove to be really expensive for computers. In order to determine whether the board to be connected, a human simply checks for any "gap" inside the remaining region, and is processed in almost O(1) fashion for a simple non-overlapping graph, whereas my code implementation need to "spread" from a point on the graph into its neighboring territories and check after the spreading is complete to check whether if any points lies outside of reach (O(n) at best). Since this check is to be performed every time in the innermost iteration, it degenerates the complexity into an O(n^(3+)) problem and becomes really inefficient.
Is there a method to check for "gap" in a manner similar to that of human cognition? Or can the problem be fundamentally thought of and simplified into a problem easier for computer to solve?
...ANSWER
Answered 2017-May-26 at 07:01Your problem sounds like a variant of bin packing problem. I would approach this by constraint satisfaction method. Below I'll use Minizinc pseudo-code.
A board consists of cells, each cell could be colored into one color from several. We can represent it as follows:
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