numb | DEPRECATED use npm ] The easiest way | Runtime Evironment library

The state is mutated in the changeSquares handler and the array reference is never updated.

On line 12, instead of writing keyboard.write(numb), write keyboard.write(str(numb)). This changes numb which is an int type to a str type before writing it.

try:

So your question is:

"How to take three values from the array, and the 4th value needs to be the right answer."

Assuming that you know where is the right answer.

Here is a simple solution:

According to https://pkg.go.dev/flag#StringVar

StringVar defines a string flag with specified name, default value, and usage string. The argument p points to a string variable in which to store the value of the flag.

So it means in your case "foo" - will be default value for wordPtr, 42 for numbPtr and false for forkPtr.

First of all, use a better readable syntax, by setting the following directive in front of your code:

You can use std::vector directly, because the type requirements when using standard library containers are restricted to only those required by the functions called on them.

Once you have constructed a std::vector with some elements, only the operations that might add new elements or erase old ones require the value type to be movable. Accessing the vector elements and moving the vector itself are not problems.

Constructing the vector with vec(num) works, because it only default constructs a known number of elements. It can constructs the new elements in-place in the storage.

The constructor used by vec(numB, numA) actually takes as arguments the number of elements and a const lvalue reference to an object of the value type. It does not take constructor arguments to construct the new elements from in-place. Instead when you pass it numA, numA is implicitly converted to a A (via the non-explicit constructor) and a reference to that A is passed to the constructor. The constructor is then specified to copy-construct the vector elements from the passed object. But because std::vector vec; is not copyable, A isn't either and so it fails.

There is however another constructor for std::vector that can construct objects without copy/move constructor: The constructor taking an iterator range. However, to use it we first need to construct an iterator range with the constructor arguments to pass to the vector elements' constructor:

I don't think there's a one-method way to do it. You have to:

• Get all the current values (getAll)
• Remove the key entirely
• Add back the values you want to keep

Here's an example:

I would recommend to create separate component called Question to avoid working with arrays of data and put state login inside. But if this is not possible I would do it this way:

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