frisky | Open Source GraphQL API for Online Shows | GraphQL library
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Open Source GraphQL API for Online Shows
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Community Discussions
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QUESTION
I have few confusions about what exactly happens when you pass the object by value, and about working of copy constructor. To practice the concept, I wrote the following code.
...ANSWER
Answered 2020-Aug-31 at 19:21The main problem is, the "copy" constructor Cat::Cat(Cat &)
doesn't copy the value of itsage
but sets it to an arbitrary value. Thus, passing a Cat
object by value and returning it will yield strange results since the received objects don't resemble the original object.
Details: The parameter Frisky
of the function myFunction
is passed by value. This means calling myFunction
will copy the passed object "into" Frisky
. The copy will be constructed by the copy constructor Cat::Cat(Cat &)
. Since this constructor sets itsage
to 50
, myFunction
always reports an age of 50
regardless of the original passed value.
The same applies here to the return values: Returning an object from a myFunction
constructs a copy for the caller by using the copy constructor Cat::Cat(Cat &)
. The returned copy always has a value itsage=50
.
Solution: Write a proper copy constructor:
QUESTION
To understand working of constructor, copy constructor, destructor, I wrote the following code.
...ANSWER
Answered 2020-Aug-28 at 06:41Your first code returns a copy of Frisky
from myFunction
, that is where the additional copy comes from.
Your second code doesn't work because your copy constructor erroneously takes a non-const reference and you can't pass the temporary value returned from myFunction
to a non-const reference.
Not directly related to your question but you should obey the rule of three and implement the assignment operator too.
QUESTION
I wrote the following code.
...ANSWER
Answered 2020-Aug-16 at 13:54You have a misconception in steps 2 and 3 in both descriptions.
The actual order is:
return Frisky
is executed which returns a copy of (code 1) or reference to (code 2) the local variable.- The function ends and all local variables are destroyed. This does not affect the return value in code 1.
Mani
is initialized with a still-existing copy of (code 1) or a reference to a non-existing (code 2)Cat
instance.
QUESTION
I am having a little confusion about memory allocation. Where does member variable get created (on stack or heap?) when object is created on heap? For example, say we have class Cat as follows.
...ANSWER
Answered 2020-Aug-11 at 18:26itsage
is a subobject of Cat
which means it is part of the the Cat
object itself. Therefore, it exists as part of the heap-allocated Cat
object. new Cat
creates the Cat
object and any subobjects, all within the same allocation.
If it were a pointer, this would still be true. The pointer value would be part of the Cat
object, but it could point to an int
somewhere else.
Note that the C++ standard doesn't use the terms "stack" and "heap." Function local variables (non-static) have automatic storage duration and objects created with new T
have dynamic storage duration. Under the hood, values with these storage durations are typically implemented using the stack and heap respectively, but a conforming implementation is not required to use stack or heap structures.
QUESTION
I am learning c++ from 'Teach yourself c++ in 21 days' by Liberty and Jones. Compiler I am using is gcc 6.3.0. I am on pointer topic. First I am writing one code similar to the one book gives which works fine. Here it is:
...ANSWER
Answered 2020-Aug-08 at 07:52But in the second code, I nowhere assigned any memory address to pointer itsage. But still code worked fine. I am little confused here.
That's a fair doubt. In fact, your 2nd code should never work, as no memory had ever been allocated to itsage
. If it still somehow "worked" for you then it is still a typical undefined behaviour.
You should still allocate the memory before usage as usual, and free it in the constructor. As your class doesn't even have a destructor, perhaps you should choose unique_ptr instead:
QUESTION
i have array of object and fetch to flatlist. but when render and type something/ one character always rerender again and keyboard goes down. any idea for solving my problem?
here is my code... snack expo
...ANSWER
Answered 2020-Aug-07 at 11:59The keyboard goes down because TextInput is unmounted in every rendering.
TextInput is inside the RenderComponent
function, and it is inside Coba
, which means that in every rendering, a new RenderComponent
function is created, and the old RenderComponent
function is thus unmounted.
To solve the problem, create RenderComponent
function outside of Coba
, and pass all necessary data as props. snack expo
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install frisky
Getting the configuration ready Copy the .env.example file at the same location and save as .env
Starting the application (after starting MongoDB's mongod)
Linting the code
Fixing the linting issues
Import shows from sample data
Import episodes from sample data
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