haskell-fun | A short scripts and programs | Script Programming library

 by   qnikst JavaScript Version: Current License: No License

kandi X-RAY | haskell-fun Summary

kandi X-RAY | haskell-fun Summary

haskell-fun is a JavaScript library typically used in Programming Style, Script Programming applications. haskell-fun has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

A short scripts and programs
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              haskell-fun has a low active ecosystem.
              It has 13 star(s) with 6 fork(s). There are 4 watchers for this library.
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              It had no major release in the last 6 months.
              There are 2 open issues and 1 have been closed. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of haskell-fun is current.

            kandi-Quality Quality

              haskell-fun has no bugs reported.

            kandi-Security Security

              haskell-fun has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              haskell-fun does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

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              haskell-fun releases are not available. You will need to build from source code and install.

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            haskell-fun Key Features

            No Key Features are available at this moment for haskell-fun.

            haskell-fun Examples and Code Snippets

            No Code Snippets are available at this moment for haskell-fun.

            Community Discussions

            QUESTION

            Is there any general functor (not limited to endofunctor) usage in programming?
            Asked 2020-Aug-27 at 08:09

            Is there any general functor (not limited to endofunctor) usage in programming?

            I understand the reason endofunctor employed is to make the structure simple like monoid or monad.

            I also understand ultimately, all the value is settled down to a category of a programming language (such as Hask), but what I'm talking about here is endofunctor between the same category of Strings, Numbers, Booleans, or Functions.

            Related questions:

            Are all Haskell functors endofunctors?

            Differences between functors and endofunctors

            ...

            ANSWER

            Answered 2020-Aug-25 at 12:25

            First, yes.

            For example, we all know that a monoid can be defined to be a single-object category with

            • arrows to be elements
            • the single object has no meaning
            • composition to be operator ((<>) in Haskell)
            • id arrow to be the identity (mempty in Haskell).

            And a homomorphism between two monoids becomes a functor between two categories in this sense.

            Now, say, type A and B are both monoids; A functor between them is just a homomorphic function f :: A -> B that maps each A to B, preserving the composition.

            But, wait, f :: A -> B is not even a Functor (note that I use the monospaced typeface here)!

            No, it is not a Functor in Haskell, but it still is a functor in mathematical sense.

            So, to emphasize, I state it again: "Non-endo" functors ARE used in programming, and probably even more often than endofunctors.

            The point here is that category theory is a highly abstract theory - It provides notions for abstracting concrete objects. We can define these notions to mean different things in different contexts.

            And Hask (or Set, or subcategories of Set) is just one of these infinite definitions, which makes

            • arrows to be functions
            • objects to be types (or, sets)
            • composition to be function composition (.)
            • id arrow to be the id function.

            Compare this "categorical universe" definition with the "categorical monoid" definition above - congrats, you've known two different takes on categories now!

            To conclude, remember that category theory itself is just some abstractions. Abstractions themselves have no meaning and no use at all. We connect them to real things, and only in this way they can bring us convenience. Understand abstract concepts through concrete examples, but NEVER simplify these concepts themselves to anything concrete (Like, never simplify functors to merely the functors between "categorical universes" (e.g. Hask, Set, etc)!).

            P.S. If you ask "Is there a functor that sends Hask to another category in Haskell?" then the answer can be yes or no. For example, you can define a category Hask * Hask to contain any two types' cartesian product, and a functor data Diag a = Diag a a, fmap f x = Diag (f x) (f x) that sends each type A to its square A * A. However, Hask * Hask is still a subcategory of Hask, so we may say this is an endofunctor too.

            Source https://stackoverflow.com/questions/63561210

            QUESTION

            Result type of a polyvariadic function in haskell
            Asked 2020-May-31 at 13:14

            While studying polyvariadic functions in Haskell I stumbled across the following SO questions:

            How to create a polyvariadic haskell function?

            Haskell, polyvariadic function and type inference

            and thought I will give it a try by implementing a function which takes a variable number of strings and concatenates/merges them into a single string:

            ...

            ANSWER

            Answered 2020-May-31 at 12:17

            printf works without type annotation because of type defaulting in GHCi. The same mechanism that allows you to eval show $ 1 + 2 without specifying concrete types.

            GHCi tries to evaluate expressions of type IO a, so you just need to add appropriate instance for MergeStrings:

            Source https://stackoverflow.com/questions/62114605

            QUESTION

            GHC: Are there consistent rules for memoization for calls with fixed values?
            Asked 2019-Jul-12 at 17:22

            In my quest to understand and harness GHC automatic memoization, I've hit a wall: when pure functions are called with fixed values like fib 42, they are sometimes fast and sometimes slow when called again. It varies if they're called plainly like fib 42 or implicitly through some math, e.g. (\x -> fib (x - 1)) 43. The cases have no seeming rhyme or reason, so I'll present them with the intention of asking what the logic is behind the behavior.

            Consider a slow Fibonacci implementation, which makes it obvious when the memoization is working:

            ...

            ANSWER

            Answered 2019-Jul-12 at 17:22

            To elaborate in case it wasn't clear from @amalloy's answer, the problem is that you're conflating two things here -- the implicit memoization-like-behavior (what people mean when they talk about Haskell's "automatic memoization", though it is not true memoization!) that results directly from thunk-based lazy evaluation, and a compiler optimization technique that's basically a form of common subexpression elimination. The former is predictable, more or less; the latter is at the whim of the compiler.

            Recall that real memoization is a property of the implementation of a function: the function "remembers" results calculated for certain combinations of arguments, and may reuse those results instead of recalculating them from scratch when called multiple times with the same arguments. When GHC generates code for functions, it does not automatically generate code to perform this kind of memoization.

            Instead, the GHC code generates to implement function application is unusual. Instead of actually applying the function to arguments to generate the final result as a value, a "result" is immediately constructed in the form of a thunk, which you can view as a suspended function call or a "promise" to deliver a value at a later time.

            When, at some future point, the actual value is needed, the thunk is forced (which actually causes the original function call to take place), and the thunk is updated with the value. If that same value is needed again later, the value is already available, so the thunk doesn't need to be forced a second time. This is the "automatic memoization". Note that it takes place at the "result" level rather than the "function" level -- the result of a function application remembers its value; a function does not remember the results it previously produced.

            Now, normally the concept of the result of a function application remembering its value would be ridiculous. In strict languages, we don't worry that after x = sqrt(10), reusing x will cause multiple sqrt calls because x hasn't "memoized" its own value. That is, in strict languages, all function application results are "automatically memoized" in the same sense they are in Haskell.

            The difference is lazy evaluation, which allows us to write something like:

            Source https://stackoverflow.com/questions/57000994

            QUESTION

            Generating and running Haskell code from Python
            Asked 2018-Apr-13 at 10:14

            We are writing a python program that attempts to synthesize a (simple) haskell-function given input-output pairs. Throughout the run of the program, we generate haskell code and check its correctness against the user-supplied examples. Suppose we get as input "1 2" and expected output "3". We would (eventually) come up with the plus function. We would then run (\x y -> x + y) 1 2 in haskell and check if it evaluates to 3.

            The way we currently do things is by running the following python code:

            ...

            ANSWER

            Answered 2018-Apr-13 at 10:14

            This seems like an odd thing to be doing.. but interesting none the less.

            Two things come immediately to mind here. First is to use ghci repl instead of spawning a new process for every eval attempt. The idea is to stream your I/O into the ghci process instead of spawning a new ghc process for each attempt. The overhead of starting a new process for every eval seems to be quite performance killer. I'd usually go for expect, but since you want python, I'll call on pexpect:

            Source https://stackoverflow.com/questions/49813434

            QUESTION

            Haskell polyvariadic function with no arguments
            Asked 2017-Sep-06 at 21:34

            I'm trying to create a polyvariadic function in Haskell, I used this answer to create a basic function. Here is the function's code :

            ...

            ANSWER

            Answered 2017-Sep-06 at 21:34

            The simplest version only works for Integer results.

            The easy way

            This works off what you already wrote, taking advantage of the fact that 0 is the identity for addition.

            Source https://stackoverflow.com/questions/46078682

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install haskell-fun

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/qnikst/haskell-fun.git

          • CLI

            gh repo clone qnikst/haskell-fun

          • sshUrl

            git@github.com:qnikst/haskell-fun.git

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