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QUESTION
I'm trying to implement dynamic subscribers in a kdb-tick system whereby a subset of the events are passed to a given consumer based on a query supplied by the consumer.
For instance given a batch of events i.e.:
...ANSWER
Answered 2021-Feb-07 at 11:28I think the fact that you're expecting a string form of a conditional argument is part of your problem (that in turn requires you to parse
a stringified functional select and that parse assumes global).
Why not expect a list form of the conditional argument instead? Then there's no need to parse and you can create a local functional select. E.g.
QUESTION
(Apologies if this is a repeat but my question disappeared- THIS ONE IS MORE DETAILED) I have names that need conversation into a 'static' of 'fixed' GUID. Using ASCII- I have a GUID that represents a a 16-character name. I can re-run these in reverse to see if it is one of our names. But I would like to expand it so I only use an indexed set of characters, and can effectively jam 16 characters into the 128 bits of the GUID (ASCII-8 bit - FF in hex, easy to fake and parse) I am only using 64 characters which I could reduce to 6 bit if I could figure out how to pack the bits in VBA/EXCEL. I could lower that to 5-bit potentially if I dropped the caps.
With 6 or 5 bit, I could get names that were 128/5=25(r3) bits or 128/6=21(r2) bits, or is this even possible? so the indexes would look like:
...ANSWER
Answered 2020-Sep-03 at 22:03Attribute VB_Name = "base2_6"
''Total hack- BUT it works to jam 21 characters using a 6 bit reference
''into a 128bit GUID
''Characters register 6 bit binary MSB at left,
''every 8 bits gets jammed into a HEX and those bits removed off the stack
''when max characters is reached- there are 2 bits left over - filled with
''LSB "00" to force the HEX to generate for 32 characters of hex for
''A 128 bit GUID. Will work on the round trip next to convert from GUID
''to string - 5 more characters than a straight ASCII to hex conversion
Option Explicit
''Background - to create as long of a static GUID from a string (21)
''Base 2^6 = 6 bit, 64 characters, # 0-63
''decode = Value - (CharPosition*Base)
''Encode = Value + (CharPosition*Base)
'look at 24 bit chunks (6bit and 8bit share every 24 bits bit group.)
'00000x00000x00000x00000x = every four characters in 6 bit = 24 bits
'0000000x0000000x0000000x = 3 bytes
'-2hex--x-2hex--x-2hex--x = 3 hex bytes per 4 characters
'128bit = 16 hex pairs or 21 characters + 2 leftover bits.
Const vbqt = """"
''Full VISUAL ASCII characters from 32(space) through 126 ~
Const strASC = " !" & vbqt & "#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~"
''Revit illegal chars "Filesystem" :;< >? [\] ` {|}
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
''5 bit - would allow for 25 charqacters simplified- ignoring upper and lower case
''would require a UCASE convert prior to checking. can contain a few digits only
''Optional simpler base 5bit- not used - do not change this - it will change the whole field base and compression!
''do not change this - it will change the whole field base and compression!
''''''''''''''''0''''''''1'''''''''2'''''''''3'*<31 MAX (32 CHARS)
''''''''''''''''01234567890123456789012345678901 ''NoSpaces!
Const Base5b = ".0123ABCDEFGHIJKLMNOPQRSTUVWXYZ_"
Const x5b = 5 ''Encoding bitsize
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
''6 bit - allows for 21 charqacters simplified- ignoring upper and lower case
''do not change this - it will change the whole field base and compression!
''''''''''''''''00''''''''1'''''''''2'''''''''3'''''''''4'''''''''5'''''''''6''''
''''''''''''''''0123456789012345678901234567890123456789012345678901234567890123 ''NoSpaces!
Const Base6b = ".0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyz"
Const x6b = 6 ''Encoding bitsize
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
''7 bit - would only allow for 18 characters
''do not change this - it will change the whole field base and compression!
''''''''''''''''00 ''''''''1'''''''''2'''''''''3'''''''''4'''''''''5'''''''''6'''''''''7'''''''''''12 *<127
''''''''''''''''01 2 34567890123456789012345678901234567890123456789012345678901234567890123456789---01234567
Const Base7b = " !" & vbqt & "#$%&'()*+.123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyz"
Const x7b = 7 ''Encoding bitsize
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
''8 bit - allows for 256 characters
''Same as straight hex encoding xFF 256 bits - mostly 173 wasted spaces
''''''''''''''''0------------''''''''1'''''''''2'''''''''3'''''''''4'''''''''5'''''''''6'''''''''7'''''''''8'''
''''''''''''''''0----1-------2345678901234567890123456789012345678901234567890123456789012345678901234567890123
Const Base8b = "!" & vbqt & "#$%&'()*+,-./0123456789:;=@ABCDEFGHIJKLMNOPQRSTUVWXYZ^_`abcdefghijklmnopqrstuvwxyz"
Function Encode6Bit2HexGUID(VarName As String) As String ''Range) As String ''guid in HEX
''takes a string of fixed characters Base6b compared against 6 bits to compress 4 characters for every 3 Bytes (FFFFFF)
''To pack into 128 bit string for GUID.
Dim i As Integer ''count integer
Dim ie As Integer ''iend of count either MaxChar or less
Dim strName As String ''string to nibble
Dim HexStr As String ''Hex string to build
Const MaxChar = 21
Dim enc6b As Long ''6bit value per character
Dim binStr As String ''Binary representation of number
''strName = VarName.value ''get value to work with
strName = VarName
If Len(strName) > MaxChar Then
MsgBox MaxChar & " character limite exceeded, variables must be unique within the first MaxChar characters.", vbExclamation + vbOKOnly, "Warning"
'
ie = MaxChar
strName = Left(strName, MaxChar)
Else
ie = Len(Left(strName, MaxChar)) '''''''''''''''''''<<<<<<<<<<<<<= 8
HexStr = HexStr & Right("0" & Hex(Bin2Dec(Left(binStr, 8))), 2)
binStr = Right(binStr, Len(binStr) - 8)
Loop
Next i
Encode6Bit2HexGUID = Left(HexStr & String(32, "0"), 32)
'''''''''0 1 2 3
'''''''''12 34 56 78 90 12 34 56 78 90 12 34 56 78 90 12
''guid = XX.XX.XX.XX-XX.XX-XX.XX-XX.XX-XX.XX.XX.XX.XX.XX
''format GUID
Encode6Bit2HexGUID = Format(Encode6Bit2HexGUID, String(8, "&") & "-" & String(4, "&") & "-" & String(4, "&") & "-" & String(4, "&") & "-" & String(12, "&"))
End Function
Function enc6Bc(X As String) As Integer
enc6Bc = InStr(1, Base6b, Left(X, 1), vbBinaryCompare) - 1
If enc6Bc = -1 Then enc6Bc = 0 ''substitute 1st character if not found (returns 0)
End Function
Function Dec2Bina(X As Long, BitNo As Integer) As String
''RA: MAY TAKE A HEAVIER COMPUTATIONAL TOLL THAN THE DIVIDE/2 METHOD
Dim i
For i = BitNo - 1 To 0 Step -1
If X >= 2^ ^ i Then
X = X - 2^ ^ i
Dec2Bina = Dec2Bina & "1"
Else
Dec2Bina = Dec2Bina & "0"
End If
Next i
End Function
'Decimal To Binary
' =================
' Source: http://groups.google.ca/group/comp.lang.visual.basic/browse_thread/thread/28affecddaca98b4/979c5e918fad7e63
' Author: Randy Birch (MVP Visual Basic)
' NOTE: You can limit the size of the returned
' answer by specifying the number of bits
Function Dec2Bin(ByVal DecimalIn As Variant, _
Optional NumberOfBits As Variant) As String
Dec2Bin = ""
DecimalIn = Int(CDec(DecimalIn))
Do While DecimalIn <> 0
Dec2Bin = Format$(DecimalIn - 2 * Int(DecimalIn / 2)) & Dec2Bin
DecimalIn = Int(DecimalIn / 2) ''SHIFT ONE BIT TO THE LEFT WITH DIV2
Loop
If Not IsMissing(NumberOfBits) Then
If Len(Dec2Bin) > NumberOfBits Then
Dec2Bin = "Error - Number exceeds specified bit size"
Else
Dec2Bin = Right$(String$(NumberOfBits, _
"0") & Dec2Bin, NumberOfBits)
End If
End If
End Function
'Binary To Decimal
' =================
Function Bin2Dec(BinaryString As String) As Variant
Dim X As Integer
For X = 0 To Len(BinaryString) - 1
Bin2Dec = CDec(Bin2Dec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * 2 ^ X
Next
End Function
Public Function String_from_6Bit2HexGUID(strGUID As String) As String
Dim i As Integer
Dim strBin As String
Dim str3byte As String
Dim Long3Byte As Long
Dim strVarName As String
strGUID = Replace(strGUID, "-", "") ''remove the dashes
For i = 1 To Len(strGUID) Step 6
str3byte = Left(strGUID, 6)
strGUID = Right(strGUID, Len(strGUID) - Len(str3byte))
Long3Byte = CLng("&H" & str3byte)
If i = 31 Then
strBin = Left(Dec2Bin(Long3Byte, 8), 6)
Else
strBin = Dec2Bin(Long3Byte, 24)
End If
Do While strBin > ""
strVarName = strVarName & Mid(Base6b, Bin2Dec(Left(strBin, 6)) + 1, 1)
strBin = Right(strBin, Len(strBin) - 6)
Loop
Next i
String_from_6Bit2HexGUID = strVarName
End Function
''''''''''''''''''''''''''''''''''''''''''''''''''''''
''Testing funcitons for in and back
Private Sub test_Encode6Bit2Hex()
''''''''''''''''''''''''''''''''0 1 2
'123456789012345687901
QUESTION
I'm working on revalidate flow and face with an issue. The web services flow is the following:
...ANSWER
Answered 2020-May-20 at 12:40I was able to resolve this issue.
I changed revalidation call symbol from EVCR‡REVAL to EVCR¥REVAL
So I changed ‡ to ¥
QUESTION
I'm working on a finances tracking sheet and have the entry part of it completed, and working fine. The problem is, it runs very slowly as it goes line by line in most cases. Aside from it being a lot of code, I can't figure out how to speed it up or batch anything together. Additionally, the braces for the beginning and ending of the function in question are not connected (they are both colored red when the cursor is next to them), which I can't understand. Can anyone help clean up my code a bit to speed this up? Here is the function in question:
...ANSWER
Answered 2020-May-06 at 19:04Here's some suggestions:
I put my suggestions as comments below your code.
In general avoid the use of getValue() use getValues() instead it returns a 2D array of data. Read the documentation and also look at the returned values in the debugger so that you really understand what you data looks like: [[row0],[row1],[row2]....]
and avoid the use of A1 notations of the form A1:A. Use Sheet.getRange(1,1,Sheet.getLastRow().... instead.
QUESTION
I have got the database which has id
,chapter_name
,chapter_num
,verse_num
,verse_text
,testament
as columns.
I would like to retrieve chapterName and the total number of chapters in each book.
I'm using the following query to do so,
...ANSWER
Answered 2020-Apr-18 at 19:43This is a table of verses with redundant chapter (chapter_num) and book (chapter_name) information. We must first eliminate the redundancy and get a single row for each book and chapter. Then we can count them.
QUESTION
I am in a javascript beginner class and I am stuck with my homework. I went over it what feels like a million times but for some reason, I am missing something and I can't find it. Many thanks in advance!!! It is set up so that if the link has the data-reveal attribute and there is a modal element with the matching ID it will allow for that link to be clicked and the modal appears.
My HTML:
...ANSWER
Answered 2020-Mar-28 at 17:42london.js -> Line 134 /* Problem */
QUESTION
I have image inside svg.
Each reval parts in the image (for start is hidden by black background).
How to replace image tag with another tag like img
or div
or iframe
or webcomponent and still have the same behavior to revael beneath it?
For example I want to have but not in image tag.
or
which render the image with component styles and more.
ANSWER
Answered 2019-Dec-14 at 16:32SVG contents are rendered based on namespaces where it defaults to XML when none is specified.
For you to be able to display html contents inside an SVG tag you need to wrap the html code within a tag. The foreignObject tag allows embedding all kinds of markup, not just HTML. This means, there must be a way of determining what language is used. That's where namespaces come into play.
To tell SVG what kind of foreignObject it is, you have to put the content in the proper namespace. Based on your code a proper example would look like below:
QUESTION
I am working on a method in C where I am trying to convert a decimal to its base. I am having trouble with returning a Char*. I still am unsure how to return a pointer. When I compile this code, I get a warning saying
"warning: function returns address of local variable [-Wreturn-local-addr]". and it has to do with my res character. I am uncertain with why I cannot return res, if it's a char. I don't understand what I am suppose to return if I can't return res. Please help.
...ANSWER
Answered 2019-Oct-30 at 01:00In your decToBase()
function, the issue it's warning about is the use of char res[500];
, which is an array that's allocated on the stack as a local variable. These are all thrown away when the function returns, so if you return a pointer to (or: the address of) the res
array, this pointer points to junk on the stack.
You have to find some other way to manage this allocation, and though some might suggest using malloc()
to allocate memory from the system, this is probably a bad idea because it's asking for problems with memory leaks.
Better is to pass in the buffer you want it to fill, and use that. Then the caller does the allocation and you don't worry about memory leaks.
QUESTION
I have the app below (simplified example). Basically I would like that, when I turn on the app, if the reactive value is equal to ""
than I do not want that the activeButton
appears on the UI. At the moment is appearing but without label. How can I do in this case? Thank you for your help!
ANSWER
Answered 2018-Feb-27 at 16:26You need to add shinyjs::toggle()
:
QUESTION
I'm using a LayoutInflater to inflate a custom layout to generate invoices and receipts as Bitmaps then I send them to the printer or export them as png files, Like this:
...ANSWER
Answered 2018-May-04 at 16:04I figured it out, I needed to create a new context with custom locale and inflate the view with my new context:
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