discussion | Dynamic comments for static blogs | REST library

 by   quartzmo JavaScript Version: Current License: No License

kandi X-RAY | discussion Summary

kandi X-RAY | discussion Summary

discussion is a JavaScript library typically used in Web Services, REST, React applications. discussion has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Dynamic comments for static blogs. Use it "server-less" with Firebase, or provide your own RESTful API.

            kandi-support Support

              discussion has a low active ecosystem.
              It has 23 star(s) with 1 fork(s). There are 3 watchers for this library.
              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of discussion is current.

            kandi-Quality Quality

              discussion has 0 bugs and 0 code smells.

            kandi-Security Security

              discussion has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              discussion code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              discussion does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              discussion releases are not available. You will need to build from source code and install.
              It has 6413 lines of code, 0 functions and 6 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed discussion and discovered the below as its top functions. This is intended to give you an instant insight into discussion implemented functionality, and help decide if they suit your requirements.
            • Generate S3 random position
            • Update a model .
            • Generates a unique GUID
            • Unbind model on the model
            Get all kandi verified functions for this library.

            discussion Key Features

            No Key Features are available at this moment for discussion.

            discussion Examples and Code Snippets

            No Code Snippets are available at this moment for discussion.

            Community Discussions


            How to override a nested npm sub-dependency with a different package altogether (not just different package version number)?
            Asked 2022-Apr-04 at 01:19

            I am having trouble resolving a ReDoS vulnerability identified by npm audit. My application has a nested sub-dependency ansi-html that is vulnerable to attack, but unfortunately, it seems that the maintainers have gone AWOL. As you can see in the comments section of that Github issue, to get around this problem, the community has made a fork of the repo called ansi-html-community located here, which addresses this vulnerability.

            Thus, I would like to replace all nested references of ansi-html with ansi-html-community.


            My normal strategy of using npm-force-resolutions does not seem to be able to override nested sub-dependencies with a different package altogether but rather only the same packages that are a different version number. I have researched this for several hours, but unfortunately, the only way I have found to fix this would appear to be with yarn, which I am now seriously considering using instead of npm. However, this is not ideal as our entire CI/CD pipeline is configured to use npm.

            Does anyone know of any other way to accomplish nested sub-dependency package substitution/resolution without having to switch over to using yarn?

            Related Questions

            These are questions of interest that I was able to find, but unfortunately, they tend to only discuss methods to override package version number, not the package itself.

            Discusses how to override version number:

            How do I override nested NPM dependency versions?

            Has a comment discussion about npm shrinkwrap (not ideal):

            npm - how to override a dependent package's dependencies?

            Other related StackOverflow questions:

            CSE Index of related questions



            Answered 2021-Oct-29 at 21:01

            I figured it out. As of October 2021, the solution using npm-force-resolutions is actually very similar to how you would specify it using yarn. You just need to provide a link to the tarball where you would normally specify the overriding version number. Your resolutions section of package.json should look like this:

            Source https://stackoverflow.com/questions/69548370


            Is there a converse to `operator.contains`?
            Asked 2022-Mar-30 at 09:46

            edit: I changed the title from complement to converse after the discussion below.

            In the operator module, the binary functions comparing objects take two parameters. But the contains function has them swapped.

            I use a list of operators, e.g. operator.lt, operator.ge.

            They take 2 arguments, a and b.

            I can say operator.lt(a, b) and it will tell me whether a is less than b.

            But with operator.contains, I want to know whether b contains a so I have to swap the arguments.

            This is a pain because I want a uniform interface, so I can have a user defined list of operations to use (I'm implementing something like Django QL).

            I know I could create a helper function which swaps the arguments:



            Answered 2022-Mar-30 at 00:02

            If either of them posts an answer, you should accept that, but between users @chepner and @khelwood, they gave you most of the answer.

            The complement of operator.contains would be something like operator.does_not_contain, so that's not what you're looking for exactly. Although I think a 'reflection' isn't quite what you're after either, since that would essentially be its inverse, if it were defined.

            At any rate, as @chepner points out, contains is not backwards. It just not the same as in, in would be is_contained_by as you defined it.

            Consider that a in b would not be a contains b, but rather b contains a, so the signature of operator.contains makes sense. It follows the convention of the function's stated infix operation being its name. I.e. (a < b) == operator.lt(a, b) and b contains a == operator.contains(b, a) == (a in b). (in a world where contains would be an existing infix operator)

            Although I wouldn't recommend it, because it may cause confusion with others reading your code and making the wrong assumptions, you could do something like:

            Source https://stackoverflow.com/questions/71669583


            Next failed to load SWC binary
            Asked 2022-Mar-22 at 05:46

            When trying to run the command using nextjs npm run dev shows error - failed to load SWC binary see more info here: https://nextjs.org/docs/messages/failed-loading-swc.

            I've tried uninstalling node and reinstalling it again with version 16.13 but without success, on the vercel page, but unsuccessful so far. Any tips?

            Also, I noticed it's a current issue on NextJS discussion page and it has to do with the new Rust-base compiler which is faster than Babel.



            Answered 2021-Nov-20 at 13:57

            This worked as suggeted by nextJS docs but it takes away Rust compiler and all its benefits... Here is what I did for those who eventually get stuck...

            Step 1. add this line or edit next.json.js

            Source https://stackoverflow.com/questions/69816589


            Efficient overflow-immune arithmetic mean in C/C++
            Asked 2022-Mar-10 at 14:02

            The arithmetic mean of two unsigned integers is defined as:



            Answered 2022-Mar-08 at 10:54

            The following method avoids overflow and should result in fairly efficient assembly (example) without depending on non-standard features:

            Source https://stackoverflow.com/questions/71019078


            How do I calculate square root in Python?
            Asked 2022-Feb-17 at 03:40

            I need to calculate the square root of some numbers, for example √9 = 3 and √2 = 1.4142. How can I do it in Python?

            The inputs will probably be all positive integers, and relatively small (say less than a billion), but just in case they're not, is there anything that might break?


            Note: This is an attempt at a canonical question after a discussion on Meta about an existing question with the same title.



            Answered 2022-Feb-04 at 19:44
            Option 1: math.sqrt()

            The math module from the standard library has a sqrt function to calculate the square root of a number. It takes any type that can be converted to float (which includes int) as an argument and returns a float.

            Source https://stackoverflow.com/questions/70793490


            Why is SFINAE for one of the std::basic_string constructors so restrictive?
            Asked 2022-Jan-28 at 12:53

            Discussion about this was started under this answer for quite simple question.


            This simple code has unexpected overload resolution of constructor for std::basic_string:



            Answered 2022-Jan-05 at 12:05

            Maybe I'm wrong, but it seems that last part:

            Source https://stackoverflow.com/questions/70591571


            Is the timing of MATLAB reliable? If yes, can we reproduce the performance with julia, fortran, etc.?
            Asked 2022-Jan-05 at 08:26

            Originally this is a problem coming up in mathematica.SE, but since multiple programming languages have involved in the discussion, I think it's better to rephrase it a bit and post it here.

            In short, michalkvasnicka found that in the following MATLAB sample



            Answered 2021-Dec-30 at 12:23

            tic/toc should be fine, but it looks like the timing is being skewed by memory pre-allocation.

            I can reproduce similar timings to your MATLAB example, however

            • On first run (clear workspace)

              • Loop approach takes 2.08 sec
              • Vectorised approach takes 1.04 sec
              • Vectorisation saves 50% execution time
            • On second run (workspace not cleared)

              • Loop approach takes 2.55 sec
              • Vectorised approach takes 0.065 sec
              • Vectorisation "saves" 97.5% execution time

            My guess would be that since the loop approach explicitly creates a new matrix via zeros, the memory is reallocated from scratch on every run and you don't see the speed improvement on subsequent runs.

            However, when HH remains in memory and the HH=___ line outputs a matrix of the same size, I suspect MATLAB is doing some clever memory allocation to speed up the operation.

            We can prove this theory with the following test:

            Source https://stackoverflow.com/questions/70531385


            The "(optional)" marker in cppreference.com documentation
            Asked 2022-Jan-04 at 14:27

            Last week, I had a discussion with a colleague in understanding the documentation of C++ features on cppreference.com. We had a look at the documentation of the parameter packs, in particular the meaning of the (optional) marker:

            (Another example can be found here.)

            I thought it means that this part of the syntax is optional. Meaning I can omit this part in the syntax, but it is always required to be supported by the compiler to comply with the C++ standard. But he stated that it means that it is optional in the standard and that a compiler does not need to support this feature to comply to the standard. Which is it? Both of these explanations make sense to me.

            I couldn't find any kind of explanation on the cppreference web site. I also tried to google it but always landed at std::optional...



            Answered 2021-Aug-21 at 20:22

            It means that particular token is optional. For instance both these declarations work:

            Source https://stackoverflow.com/questions/68876460


            Are codatatypes really terminal algebras?
            Asked 2021-Nov-27 at 00:22

            (Disclaimer: I'm not 100% sure how codatatype works, especially when not referring to terminal algebras).

            Consider the "category of types", something like Hask but with whatever adjustment that fits the discussion. Within such a category, it is said that (1) the initial algebras define datatypes, and (2) terminal algebras define codatatypes.

            I'm struggling to convince myself of (2).

            Consider the functor T(t) = 1 + a * t. I agree that the initial T-algebra is well-defined and indeed defines [a], the list of a. By definition, the initial T-algebra is a type X together with a function f :: 1+a*X -> X, such that for any other type Y and function g :: 1+a*Y -> Y, there is exactly one function m :: X -> Y such that m . f = g . T(m) (where . denotes the function combination operator as in Haskell). With f interpreted as the list constructor(s), g the initial value and the step function, and T(m) the recursion operation, the equation essentially asserts the unique existance of the function m given any initial value and any step function defined in g, which necessitates an underlying well-behaved fold together with the underlying type, the list of a.

            For example, g :: Unit + (a, Nat) -> Nat could be () -> 0 | (_,n) -> n+1, in which case m defines the length function, or g could be () -> 0 | (_,n) -> 0, then m defines a constant zero function. An important fact here is that, for whatever g, m can always be uniquely defined, just as fold does not impose any contraint on its arguments and always produce a unique well-defined result.

            This does not seem to hold for terminal algebras.

            Consider the same functor T defined above. The definition of the terminal T-algebra is the same as the initial one, except that m is now of type X -> Y and the equation now becomes m . g = f . T(m). It is said that this should define a potentially infinite list.

            I agree that this is sometimes true. For example, when g :: Unit + (Unit, Int) -> Int is defined as () -> 0 | (_,n) -> n+1 like before, m then behaves such that m(0) = () and m(n+1) = Cons () m(n). For non-negative n, m(n) should be a finite list of units. For any negative n, m(n) should be of infinite length. It can be verified that the equation above holds for such g and m.

            With any of the two following modified definition of g, however, I don't see any well-defined m anymore.

            First, when g is again () -> 0 | (_,n) -> n+1 but is of type g :: Unit + (Bool, Int) -> Int, m must satisfy that m(g((b,i))) = Cons b m(g(i)), which means that the result depends on b. But this is impossible, because m(g((b,i))) is really just m(i+1) which has no mentioning of b whatsoever, so the equation is not well-defined.

            Second, when g is again of type g :: Unit + (Unit, Int) -> Int but is defined as the constant zero function g _ = 0, m must satisfy that m(g(())) = Nil and m(g(((),i))) = Cons () m(g(i)), which are contradictory because their left hand sides are the same, both being m(0), while the right hand sides are never the same.

            In summary, there are T-algebras that have no morphism into the supposed terminal T-algebra, which implies that the terminal T-algebra does not exist. The theoretical modeling of the codatatype Stream (or infinite list), if any, cannot be based on the nonexistant terminal algebra of the functor T(t) = 1 + a * t.

            Many thanks to any hint of any flaw in the story above.



            Answered 2021-Nov-26 at 19:57

            (2) terminal algebras define codatatypes.

            This is not right, codatatypes are terminal coalgebras. For your T functor, a coalgebra is a type x together with f :: x -> T x. A T-coalgebra morphism between (x1, f1) and (x2, f2) is a g :: x1 -> x2 such that fmap g . f1 = f2 . g. Using this definition, the terminal T-algebra defines the possibly infinite lists (so-called "colists"), and the terminality is witnessed by the unfold function:

            Source https://stackoverflow.com/questions/70128628


            C Incrementing pointer address passed to a function ++ operator
            Asked 2021-Nov-16 at 18:12

            I have a question that is raised from this discussion: C - modify the address of a pointer passed to a function

            Let's say I have the following code:



            Answered 2021-Nov-16 at 17:49

            The postfix increment operator ++ has higher precedence than the dereference operator *. So this:

            Source https://stackoverflow.com/questions/69993771

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