ajax-form | HTML forms on performance-enhancing drugs | Form library

 by   rnicholus JavaScript Version: 2.1.4 License: MIT

kandi X-RAY | ajax-form Summary

kandi X-RAY | ajax-form Summary

ajax-form is a JavaScript library typically used in User Interface, Form, jQuery applications. ajax-form has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i ajax-form' or download it from GitHub, npm.

HTML forms on performance-enhancing drugs.
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            kandi-support Support

              ajax-form has a low active ecosystem.
              It has 232 star(s) with 44 fork(s). There are 23 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 3 open issues and 72 have been closed. On average issues are closed in 22 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of ajax-form is 2.1.4

            kandi-Quality Quality

              ajax-form has 0 bugs and 0 code smells.

            kandi-Security Security

              ajax-form has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              ajax-form code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              ajax-form is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              ajax-form releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed ajax-form and discovered the below as its top functions. This is intended to give you an instant insight into ajax-form implemented functionality, and help decide if they suit your requirements.
            • Add a new time to the list of timers .
            • Copy date properties from source to source .
            • Fake XHRHttpRequest
            • Parses time string into an array of ticks
            • Creates a native Date date .
            • Subscribes to the given method .
            • Match a request .
            • Check if Element is a DOM node
            • Restore methods to global state
            • Creates a new object
            Get all kandi verified functions for this library.

            ajax-form Key Features

            No Key Features are available at this moment for ajax-form.

            ajax-form Examples and Code Snippets

            No Code Snippets are available at this moment for ajax-form.

            Community Discussions

            QUESTION

            How to clear form after submission in rails using (stimulus) hotwire?
            Asked 2022-Mar-14 at 06:09

            I have a form which creates a new post, and a stimulus controller that clears the input fields after submission. However, it does this before the input values reach my rails controller.

            This is my form_controller.js

            ...

            ANSWER

            Answered 2022-Mar-14 at 06:09

            The event is being executed on submit button click instead try running it on form submit. Didn't test the code but you might want to do something like this:

            Try 1:

            Source https://stackoverflow.com/questions/71462885

            QUESTION

            Timeout a submit animation with JavaScript
            Asked 2022-Jan-30 at 18:24

            i have a submit button and a JavaScript. On click the button changes the state from active to inactive and a spinner animation is shown. I want to add to the script a timeout function. The button shall stop the animation and go back in active state after 3000 ms and show the normal submit button again. Here is my code:

            ...

            ANSWER

            Answered 2022-Jan-30 at 18:24

            QUESTION

            django redirect update to detail view after ajax update
            Asked 2021-Dec-07 at 23:11

            I want to redirect to detail view after an update that uses ajax form submission.

            Urls

            ...

            ANSWER

            Answered 2021-Dec-07 at 22:12

            You cannot redirect a user after an ajax request using your backend. The redirect needs to be handled in your ajax call.

            In your update view, check if it's an ajax request. For example, using is_ajax = request.META.get('HTTP_X_REQUESTED_WITH') == 'XMLHttpRequest'.

            If it's an ajax request don't return a redirect but a JsonResponse, such as return JsonResponse({'concept':concept}).

            In your ajax success option, you can then handle the redirect.

            Source https://stackoverflow.com/questions/70267287

            QUESTION

            how to show new select input only when select specific option and when select another options don't show by jquery? laravel
            Asked 2021-May-19 at 06:34

            i'm trying to show new select input contains (states) options, when user select specific option a (USA) country, and when select another country non (USA) don't show the states select options i want in this case still hidden.

            Route

            ...

            ANSWER

            Answered 2021-May-19 at 06:34

            In your inputCountry select-box i am assuming {{ $country->name }} is country name so you can use $(this).find("option:selected").text() to get this value and then compare it with USA if they are equal show your div else hide it.

            Demo Code :

            Source https://stackoverflow.com/questions/67591076

            QUESTION

            Laravel patch method not supported (even on update method)
            Asked 2021-May-04 at 17:38

            HTML PATCHING FORM

            ...

            ANSWER

            Answered 2021-May-04 at 17:38

            Since you using ajax, @method is not working in that. You need to activate PATCH in your webserver, or change your ajax code to submit form in post and add _method in params. For example in jQuery

            Source https://stackoverflow.com/questions/67383558

            QUESTION

            Spring boot unsupported media type with multipart request
            Asked 2021-Jan-06 at 16:38

            I am trying to send a file and two json objects to my Spring Boot backend with a multipart POST request but I always get a 415 http response. Here is a list of things that I already tried to do:

            1. Send each object as a Blob file with an application/json content type as suggested here
            2. Send each object as a String as suggested here
            3. Add contentType: false and processData: false in the ajax request as suggested here
            4. Use @RequestParam instead of @RequestPart in Spring Boot controller

            What am I missing?

            Here is the request:

            ...

            ANSWER

            Answered 2021-Jan-04 at 08:26

            You have to set the "Content-Type" to the header

            Source https://stackoverflow.com/questions/65552664

            QUESTION

            Django don't refresh site when form is invalid
            Asked 2020-Oct-12 at 10:30

            I am currently developing a website for which I use a lot of modals with forms in them. The thing is, every time I enter invalid information in a form field and press the submit button, the modal just closes and there is no indication that the form was invalid.

            I already know that there is the possibility of making an ajax request which sends the form data to another view which then responds with a JSONResponse that contains errors which can then be displayed(like shown in this article: https://realpython.com/django-and-ajax-form-submissions/). That would work but by doing that I would lose all benefits of django forms. Because I have to submit the form data as JSON, I cant use functions like form.is_valid.

            So my question is: Is there a way to not refresh the site when a invalid form is submitted and displaying errors without having to send the data via JSON?

            ...

            ANSWER

            Answered 2020-Oct-12 at 10:30

            When you submit HTML form a browser navigates you to the URL that you specify in that form's action attribute. There is no way to implement HTML form submission without the navigation to the action URL.

            So your only choice is an AJAX request.

            Because I have to submit the form data as JSON, I cant use functions like form.is_valid.

            That's not true, you call form.is_valid on the backend side, both HTML form and AJAX send HTTP request to your backend.

            Source https://stackoverflow.com/questions/64315321

            QUESTION

            How do I prevent form from disappearing after user submits?
            Asked 2020-Jul-01 at 10:50

            I have a form in a modal (bootstrap4 theme for a wordpress site) in php. After a user submits the form in this modal, the page "reloads" and the "Form submitted successfully" message replaces the form. This means that when a user clicks the button to open the modal again, there is no form there; just a success message. How do I prevent this behaviour? I want to "reset" the form for a user to a clean form so they can submit again and again each time. This is the site code in context: https://github.com/bettersg/mediaspin/blob/master/articlemodal.php

            And this is the form itself:

            ...

            ANSWER

            Answered 2020-Jul-01 at 10:22

            You could deal with jQuery and AJAX.

            Source https://stackoverflow.com/questions/62673049

            QUESTION

            AJAX infinite preventDefault() on AJAX-responded form (vanilla JS)
            Asked 2020-Jun-30 at 08:49

            I have reviewed several great Questions along the way, so many that I earned my badge for 40 votes in one day. But, nearly all Questions use a non-Vanilla dependency like jQuery or don't address my specific need. Here are two examples of wonderful, yet to-my-sorrow unrelated, Questions:

            I'm surprised this Question has not been asked because I don't regard myself to be so imaginative. If this Question is already out there, I want to please open a Meta discussion on how to update that Question so searches can find it.

            The situation:

            This is Vanilla JS, no dependencies.

            The script uses preventDefault() to interrupt a form-submit button identified by id and call AJAX instead. AJAX works and changes content correctly. Then, the problem begins...

            This AJAX responds with a replaced div containing the same form that preventDefault() interrupts. But, AJAX doesn't recognize that updated form-submit button after the AJAX response JS-alters the div containing that form with the same id.

            Workflow:
            1. HTML -> (success)
            2. -> AJAX (success, first AJAX call)
            3. AJAX -> (success, first AJAX response)
            4. -> AJAX (broken, second AJAX call)
            It works the first time only; I need it to work infinitely.

            Note, I need to process this specific form. Other elements, including possible other forms, may be included in this div that AJAX changes.

            The code:

            index.php:

            (AJAX adapted from MDN - Sending forms through JavaScript: Using FormData bound to a form element)

            ...

            ANSWER

            Answered 2020-Jun-30 at 08:07

            You are binding the eventListener to the

            ajaxForm. Then you replace it (= remove from DOM and add new to the DOM). In that case the eventListener is also removed.

            To have an eventListener on the new form, you can either:

            • Replace only the content of the . In that case the DOM element isn't removed and so the eventListener keeps intact (don't forget to remove the tag in the php response). This is imho the easiest way.

            Source https://stackoverflow.com/questions/62652044

            QUESTION

            v-bind data not updating in vue component template
            Asked 2020-May-20 at 01:30

            When Object is updated in vue component, the Dom is not updating, even though it is connected with v-bind.

            ...

            ANSWER

            Answered 2020-May-20 at 01:30

            To maintain one-way data flow, your component should emit the new image URL value up to the parent where it can make the appropriate change.

            For example, in the parent

            Source https://stackoverflow.com/questions/61903515

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ajax-form

            You can install using 'npm i ajax-form' or download it from GitHub, npm.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • npm

            npm i ajax-form

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            https://github.com/rnicholus/ajax-form.git

          • CLI

            gh repo clone rnicholus/ajax-form

          • sshUrl

            git@github.com:rnicholus/ajax-form.git

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