js-lru | A fast , simple & universal Least Recently Used map | Caching library
kandi X-RAY | js-lru Summary
kandi X-RAY | js-lru Summary
A fast, simple & universal Least Recently Used (LRU) map for JavaScript
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Top functions reviewed by kandi - BETA
- Measure the block .
- Represents a single entry .
- Entry iterator .
- An iterator iterator
- Value iterator iterator
- an object literal
- Entry point .
- Entry point .
- Define an entry .
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js-lru Examples and Code Snippets
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QUESTION
If I have an array that I want to be of fixed size N for the purpose of caching the most recent of N items, then once limit N is reached, I'll have to get rid of the oldest item while adding the newest item.
Note: I don't care if the newest item is at the beginning or end of the array, just as long as the items get removed in the order that they are added.
The obvious ways are either:
push()
andshift()
(so thatcache[0]
contains the oldest item), orunshift()
andpop()
(so thatcache[0]
contains the newest item)
Basic idea:
...ANSWER
Answered 2018-Jan-02 at 12:29You could use Array#copyWithin
.
The
copyWithin()
method shallow copies part of an array to another location in the same array and returns it, without modifying its size.Description
The
copyWithin
works like C and C++'smemmove
, and is a high-performance method to shift the data of anArray
. This especially applies to theTypedArray
method of the same name. The sequence is copied and pasted as one operation; pasted sequence will have the copied values even when the copy and paste region overlap.The
copyWithin
function is intentionally generic, it does not require that its this value be anArray
object.The
copyWithin
method is a mutable method. It does not alter the length ofthis
, but will change its content and create new properties if necessary.
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