bl | Buffer List : collect buffers | Runtime Evironment library
kandi X-RAY | bl Summary
kandi X-RAY | bl Summary
bl is a storage object for collections of Node Buffers, exposing them with the main Buffer readable API. Also works as a duplex stream so you can collect buffers from a stream that emits them and emit buffers to a stream that consumes them!. The original buffers are kept intact and copies are only done as necessary. Any reads that require the use of a single original buffer will return a slice of that buffer only (which references the same memory as the original buffer). Reads that span buffers perform concatenation as required and return the results transparently.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of bl
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bl Examples and Code Snippets
Lines of Code : 21License : Permissive (MIT License)
Copydef right_rotation(node: my_node) -> my_node:
r"""
A B
/ \ / \
B C Bl A
/ \ --> / / \
Bl Br UB B def lr_rotation(node: my_node) -> my_node:
r"""
A A Br
/ \ / \ / \
B C LR Br C RR B A
/ \ --> / \ [bits 16]
[org 0x7C00]
xor ax, ax
mov ds, ax
mov es, ax
mov ss, ax
mov sp, 0x7C00
cld
; Measure the number of iterations final String baseUrl = "https://appservice-staging.simpleclick.co.uk/";
String token = "eyJhbGciOiJIUzM4N";
@override
void initState() {
super.initState();
getPastCruise();
}
@override
Widget build(BuildContext contex; General LUT lookup with two 16-bit halves
movzx edx, cx ; low 16 bits
mov eax, ecx
shr eax, 16 ; high 16 bits
movzx edx, byte [wordbits + edx]
add dl, [wordbits + eax]
; no/******************************************************************************
* @file gcc_arm32.ld
* @brief GNU Linker Script for Cortex-M based device
* @version V2.0.0
* @date 21. May 2019
*****************************print_char:
push ebp ; prolouge
mov ebp, esp
mov ah, 0eh ; set code for printing
mov al, [esp+8] ; move char into al
int 10h ; call int 10h
mov esp, ebp ; epilouge
pop ebp
ret
call kmain
ca#define ONE 1
unsigned int x;
unsigned int y = 5;
const unsigned int z = 7;
unsigned int fun ( unsigned int a )
{
return(a+ONE);
}
arm-none-eabi-gcc -O2 -c so.c -save-temps -o so.o
cat 0:000> .symopt
Symbol options are 0x30337:
0x00000001 - SYMOPT_CASE_INSENSITIVE
0x00000002 - SYMOPT_UNDNAME
0x00000004 - SYMOPT_DEFERRED_LOADS
0x00000010 - SYMOPT_LOAD_LINES
0x00000020 - SYMOPT_OMAP_FIND_NEAREST
0x00000100 -function drawMarkers() {
var marker0 = new google.maps.Marker({
map: map,
title: '0, 0',
position: overlay.getProjection().fromContainerPixelToLatLng(new google.maps.Point(0, 0))
});
marker0.addListener('click', funCommunity Discussions
Trending Discussions on bl
QUESTION
I'm trying to understand how the "fetch" phase of the CPU pipeline interacts with memory.
Let's say I have these instructions:
...ANSWER
Answered 2021-Jun-15 at 16:34It varies between implementations, but generally, this is managed by the cache coherency protocol of the multiprocessor. In simplest terms, what happens is that when CPU1 writes to a memory location, that location will be invalidated in every other cache in the system. So that write will invalidate the line in CPU2's instruction cache as well as any (partially) decoded instructions in CPU2's uop cache (if it has such a thing). So when CPU2 goes to fetch/execute the next instruction, all those caches will miss and it will stall while things are refetched. Depending on the cache coherency protocol, that may involve waiting for the write to get to memory, or may fetch the modified data directly from CPU1's dcache, or things might go via some shared cache.
QUESTION
I have a navbar and sidebar component in my nextjs app.
In my index component I'm using useState to show and hide sidebar on mobile device.
It works perfectly fine but I want to add animation when user clicks on hamburger menu, the sidebar should be animated left to right and when clicked on close icon it should go back to right to left. FYI I am using tailwind css.
Here's the code:
indexjs file:
ANSWER
Answered 2021-Jun-15 at 06:24Can you try this?
QUESTION
I have started understanding assembly language. I tried to understand the memory layout and addressing of variables in data section and wrote the following code
...ANSWER
Answered 2021-Jun-13 at 18:56addressing of variables in data section
I believe your confusion stems from this idea that your variables are in a separate 'data' section.
Many assemblers will allow you to organize the program in multiple sections like .stack, .data, and .code, and if you do that kind of programming, then the offset address of a data item would not change after inserting an extra instruction.
But your current bootsector code is much simpler. You are not using sections at all. Everything you write gets encoded right where it is.
The code that prints the address occupies 17 bytes.
In the abscense of the 'section 2 instruction', the address of the char1 variable would be 19. That's 17 plus the 2 bytes comming from the jmp $ instruction.
By inserting the 'section 2 instruction', the address of the char1 variable became 22. That's 17 plus the 3 bytes coming from mov bx, char2 plus the 2 bytes coming from the jmp $ instruction.
ps I'm assuming nothing comes before the printing code...
QUESTION
I am studying ROP on Arm64, I posted my thread here Return Oriented Programming on ARM (64-bit)
However a new/separate issue about choosing rop gadgets has arisen which requires the opening of a new thread. So to sum up i am studying ROP vulnerability on ARM 64 bit and i am trying to test it using a very simple c code (attached to the previous thread). I'am using ropper tool in order to search for gadgets to build my rop chain. But when i overflow the pc with the address of the gadget i got this within gdb:
...ANSWER
Answered 2021-Jun-13 at 14:57Your gadget is at 0x55555558f8.
Ropper shows the addresses of gadgets the way the ELF header describes the memory layout of the binary. According to that header:
- The file contents 0x0-0xadc are to be mapped as
r-xat address 0x0. - The file contents 0xdb8-0x1048 are to be mapped as
rw-at address 0x10db8.
Account for page boundaries and you get one page mapping file offset 0x0 to address 0x0 as executable and two pages mapping file offset 0x0 to address 0x10000 as writeable.
From your GDB dump, these mappings are created at 0x5555555000 and 0x5555565000 in the live process, respectively.
QUESTION
First I create a form and wire it to function But it have two button and one button for form submit and other one for reset everything. But if any button press it will submit after run resetcategory() function but after it run submitcategory() i can't get i use some workaround with if($this->name) but i don't want to use that. Please Help?
My php livewire file is
...ANSWER
Answered 2021-Jun-11 at 20:00This is because you have not specified a type on your Reset button. The default type for a button (if a type is not provided) is submit. So your reset button is actually submitting the form too.
Add type="button" on your Reset button to prevent it submitting the form.
QUESTION
(new in javascript)
I am asked to remove a country (China) from the dropdown menu of the plugin intl-tel-input
the code below displays the dropdown menu and it looks that it calls the utils.js file to retain the countries
...ANSWER
Answered 2021-Jun-11 at 12:14If you take a look at the intl-tel-input documentation regarding Initialisation Options. There is an option called excludeCountries.
We can modify your initialisation code to include this option to exclude China:
QUESTION
I have to prints random values in graphic mode in assembly language 8086. My random procedure works fine in simple mode but in graphic mode it prints garbage values? draw1 macro is used to prints digits or any character on screen in Graphic mode it also works fine. The only issue is in random procedure. It print correct values in simple mode but prints garbage values in Graphic mode.
...ANSWER
Answered 2021-Jun-09 at 20:48QUESTION
I am new to JavaScript and D3.js and atm trying to create an Angular App with a stacked bar chart visualisation of the number of different test results 'OK', 'NOK' and 'Aborted' of each day as a stacked bar in the y-axis and the dates as the x-axis.
My data.csv looks like this:
...ANSWER
Answered 2021-Jun-09 at 03:55If we run with the idea that you ultimately want to leverage some existing code examples and therefore need data shaped like this :
QUESTION
I'm building a reinforcement learning library where I'd like to pass certain instance information into the executables via a piped JSON.
Using aeson's Simplest.hs, I'm able to get the following basic example working as intended. Note that the parameters are sitting in Main.hs as a String params as a placeholder.
I tried to modify Main.hs so I would pipe the Nim game parameters in from a JSON file via getContents, but am running into the expected [Char] vs. IO String issue. I've tried to read up as much as possible about IO, but can't figure out how to lift my JSON parsing method to deal with IO.
How would I modify the below so that I can work with piped-in JSON?
Main.hs
...ANSWER
Answered 2021-Jun-08 at 01:17getContents returns not a String as you apparently expect, but IO String, which is a "program", which, when executed, will produce a String. So when you're trying to parse this program with decode, of course that doesn't work: decode parses a String, it cannot parse a program.
So how do you execute this program to obtain the String? There are two ways: either you make it part of another program or you call it main and it becomes your entry point.
In your case, the sensible thing to do would be to make getContent part of your main program. To do that, use the left arrow <-, like this:
QUESTION
Assume that I have 2 productions X and Y.
X-> AL|BL|X,
Y-> CK|DK|X.
I guess is not possible to reduce unit productions in X, but is this the case for Y?
...ANSWER
Answered 2021-Jun-07 at 14:44You can remove the unit production X → X as it has no effect - expanding X → X in any derivation can be removed and replaced by using one of the other X productions.
Having done that, you can then remove all unit productions for Y by replacing Y → X with Y → ω for each remaining production X → ω.
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